Block B moves to the right with a constant velocityV0 the velocity of the body A relative to B is

3T VB=2T×VA VA=32VB VAB=VA−VB=32−1VB VAB=12V0 towards right

3T VB=2T×VA VA=32VB VAB=VA−VB=32−1VB VAB=12V0 towards right

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Block B moves to the right with a constant velocityV₀ the velocity of the body A relative to B
is

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$\frac{V_{0}}{2} t o w a r d s l e f t$

$\frac{V_{0}}{2} t o w a r d s r i g h t$

$\frac{{3V}_{0}}{2} t o w a r d s l e f t$

$\frac{{3V}_{0}}{2} t o w a r d s r i g h t$

answer is B.

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$3 T V_{B} = 2 T \times V_{A} V_{A} = \frac{3}{2} V_{B} V_{AB} = V_{A} - V_{B} = (\frac{3}{2} - 1) V_{B} V_{AB} = \frac{1}{2} V_{0} towards right$

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