If speed of electron in ground state energy level is 2.2× 106 ms–1, then its speed in fourth excited state will be

# If speed of electron in ground state energy level is 2.2× 106 ms–1, then its speed in fourth excited state will be

1. A

6.8 × 106 ms–1

2. B

8.8 × 105 ms–1

3. C

5.5 × 105 ms–1

4. D

5.5 × 106 ms–1

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We know that $\mathrm{V}=\frac{\mathrm{c}}{137}\frac{\mathrm{Z}}{\mathrm{n}};\mathrm{V}\propto \frac{1}{\mathrm{n}}$
$\begin{array}{l}\frac{{\mathrm{V}}_{1}}{{\mathrm{V}}_{2}}=\frac{{\mathrm{n}}_{2}}{{\mathrm{n}}_{1}};\frac{2.2×{10}^{6}}{{\mathrm{V}}_{2}}=\frac{4}{1}\\ {\mathrm{V}}_{2}=\frac{2.2×{10}^{6}}{4}=0.55×{10}^{6}=5.5×{10}^{5}\end{array}$