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Q.

If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from ϕ1 to ϕ2 then the magnitude of current that passes through the coil is

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a

ϕ2-ϕ1R

b

Nϕ2-ϕ1R

c

ϕ2-ϕ1NR 

d

NRϕ2-ϕ1

answer is B.

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Detailed Solution

To find the magnitude of the induced current, we can apply the equation i=ER

here E=Nϕ2-ϕ1

i=Nϕ2-ϕ1R

Initial rate of flux induction = ϕ1

Final rate of flux induction = ϕ2

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