If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from ϕ1 to ϕ2 then the magnitude of current that passes through the coil is

# If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from ${\varphi }_{1}$ to ${\varphi }_{2}$ then the magnitude of current that passes through the coil is

1. A

$\frac{{\varphi }_{2-}{\varphi }_{1}}{R}$

2. B

$\frac{N\left({\varphi }_{2-}{\varphi }_{1}\right)}{R}$

3. C

4. D

$\frac{NR}{\left({\varphi }_{2-}{\varphi }_{1}\right)}$

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### Solution:

To find the magnitude of the induced current, we can apply the equation $i=\frac{E}{R}$

here $E=N\left({\varphi }_{2}-{\varphi }_{1}\right)$

$i=\frac{N\left({\varphi }_{2-}{\varphi }_{1}\right)}{R}$

Initial rate of flux induction = ${\varphi }_{1}$

Final rate of flux induction = ${\varphi }_{2}$  