If y=x3+2×2+7x+8 then dydxwill be

If $y = x^{3} + 2 x^{2} + 7 x + 8 t h e n \frac{d y}{d x}$ will be

A
$3 x^{2} + 2 x + 15$
B
$3 x^{2} + 4 x + 7$
C
$x^{3} + 2 x^{2} + 15$
D
$x^{3} + 4 x + 7$

Solution:

$y = x^{3} + 2 x^{2} + 7 x + 8$

$\frac{d y}{d x} = \frac{d}{d x} (x^{3} + 2 x^{2} + 7 x + 8)$

$= 3 x^{3} + 4 x + 7$

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