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In Bohr’s model of hydrogen atom, the ratio between the period of revolution of an electron in orbit n=1 to the period of the electron in the orbit n=2 is

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1:4

1:2

1:8

2:1

answer is D.

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Detailed Solution

$T \propto n^{3}; ∴ \frac{T_{1}}{T_{2}} = {(\frac{n_{1}}{n_{2}})}^{3}$
$∴ \frac{T_{1}}{T_{2}} = {(\frac{1}{2})}^{3}; ∴ T_{1} : T_{2} = 1 : 8$

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