In the circuit shown in the figure, the total charge is 750 μC and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is:

In the circuit shown in the figure, the total charge is $750 μC$ and the voltage across capacitor $C_{2}$ is 20 V. Then the charge on capacitor C₂ is:

A
$590 μC$
B
$450 μC$
C
$650 μC$
D
$160 μC$

Solution:

$\begin{array}{l} Q = C_{1} V_{1} \Rightarrow 750 = 15 V_{1} \Rightarrow V_{1} = 50 V, V_{2} = 20 V \\ Q_{3} = C_{3} V_{2} = 160 μc \\ Q_{2} = 750 - 160 = 590 μc \end{array}$

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