Multiplying  2i^+7j^  by 5 gives10i^+xj^   then x value ______

# Multiplying  $2\stackrel{^}{\mathrm{i}}+7\stackrel{^}{\mathrm{j}}$  by 5 gives$10\stackrel{^}{\mathrm{i}}+\mathrm{x}\stackrel{^}{\mathrm{j}}$   then x value ______

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When  $2\stackrel{^}{\mathrm{i}}+7\stackrel{^}{\mathrm{j}}$ is multiplied by 5, both the components get multiplied by 5. Hence, the answer is  .$10\stackrel{^}{\mathrm{i}}+35\stackrel{^}{\mathrm{j}}$