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Q.

The balancing lengths of potentiometer wire are 800cm and 600cm when two cells of emf’s  E1 and  E2 are connected in the secondary circuit first in series and then terminals of one cell is reversed;  E1E2 is equal to ______

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a

1411

b

43

c

71

d

111

answer is C.

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Detailed Solution

ℓ1ℓ2=E1+E2E1-E2

⇒E1E2=ℓ1+ℓ2ℓ1−ℓ2=800+600800−600=1400200=71

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