The balancing lengths of potentiometer wire are 800cm and 600cm when two cellsof emf’s E1 and E2 are connected in the secondary circuit first in series and then terminals of one cell is reversed E1E2 is equal to ______

The balancing lengths of potentiometer wire are 800cm and 600cm when two cellsof emf’s E₁and E₂ are connected in the secondary circuit first in series and then terminals of one cell is reversed $\frac{E_{1}}{E_{2}}$ is equal to ______

A
$\frac{1}{11}$
B
$\frac{14}{11}$
C
$\frac{7}{1}$
D
$\frac{4}{3}$

Solution:

$\frac{E_{1}}{E_{2}} = \frac{ℓ_{1} + ℓ_{2}}{ℓ_{1} - ℓ_{2}}; \frac{E_{1}}{E_{2}} = \frac{800 + 600}{800 - 600} = \frac{7}{1}$

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