The current ‘i’ in the circuit as shown in fig. is

The current ‘i’ in the circuit as shown in fig. is

A
2A
B
$\frac{1}{3} A$
C
1A
D
1.5A

Solution:

$R_{AB} = \frac{2}{3} R = \frac{2}{3} \times 3 = 2 Ω; i = \frac{V}{R} = \frac{3}{2} = 1 .5 A$

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