The emf of a Daniel cell is 1.08 V When the terminals of the cells are connected to a resistance of 3 Ω , the potential difference across the terminals is found to be 0.6 V . Then the internal resistance of the cell is

emf of a Daniel cell $E = 1.08 V$ Resistance $R = 3 Ω$
Potential difference $V = 0.6 V$ Internal resistance $r$

$V = E - Ir$

$\Rightarrow 0.6 = 1.08 - Ir \Rightarrow Ir = 0.48$

$(\frac{1.08}{R + r}) r = 0.48 \Rightarrow r = 2.4 Ω$

The emf of a Daniel cell is $1 .08 V$ When the terminals of the cells are connected to a resistance of $3 Ω$ , the potential difference across the terminals is found to be $0 .6 V$ . Then the internal resistance of the cell is