The equivalent resistance between points A and B of an infinite network of resistance each of  1Ω connected as shown is

The equivalent resistance between points A and B of an infinite network of resistance each of  1Ω connected as shown is

  1. A

    infinite

  2. B

    2Ω

  3. C

    zero

  4. D

    1+52

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    +91

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    Solution:

     

     

     

     

     

    RAB=R+R×RABR+RAB

    RAB=1+1×RAB1+RAB

    RAB1+RAB=1+2RAB

    RAB+RAB2=1+2RAB

    RAB2-RAB-1=0

    +1±1+42=1+52

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