The magnetic field at a distance of 2cm from the axis of a straight conductor carrying current is 12mT.The current in the conductor is

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1200 A

1210 A

12 A

125A

answer is B.

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Detailed Solution

given that $B = 12 \times 10^{- 3} T$

We know $r = 2 \times 10^{- 2} c m$

$B = \frac{μ_{0 i}}{2 πr} \Rightarrow i = \frac{B \times 2 πr}{μ_{0}} = \frac{12 \times 10^{- 3} \times 2 π \times 2 \times 10^{- 2}}{4 π \times 10^{- 7}}$

=1200A

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