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The velocity of projection of a body is increased by 2%. Other factors remaining unchanged, what will be the percentage change in the maximum height attained?

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detailed solution

Correct option is D

We know that, $y_{m} = H = \frac{(usinθ)}{2 g} = \frac{u^{2} \sin^{2} θ}{2 g}$
$∴ \frac{ΔH}{H} = \frac{2 Δu}{u} . Given \frac{Δu}{u} = 2 %$
$∴ \frac{ΔH}{H} = 2 \times 2 = 4 %$

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detailed solution

Correct answer is 4

We know that, $y_{m} = H = \frac{(usinθ)}{2 g} = \frac{u^{2} \sin^{2} θ}{2 g}$
$∴ \frac{ΔH}{H} = \frac{2 Δu}{u} . Given \frac{Δu}{u} = 2 %$
$∴ \frac{ΔH}{H} = 2 \times 2 = 4 %$

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