Three simple harmonic motions in the same direction having the same amplitude a and same period are superposed. If each differs in phase from the next by 45o, then:(i) the resultant amplitude is (1+2)a(ii) the phase of the resultant motion relative to the first is 900(iii) the energy associated with the resulting motion is 3+22 times the energy associated with any single motion(iv) the resulting motion is not simple harmonic

Three simple harmonic motions in the same direction having the same amplitude a and same period are superposed. If each differs in phase from the next by 45o, then:
(i) the resultant amplitude is (1+2)a
(ii) the phase of the resultant motion relative to the first is 900
(iii) the energy associated with the resulting motion is 3+22 times the energy associated with any single motion
(iv) the resulting motion is not simple harmonic

  1. A

    (i, iii)

  2. B

    (i, ii)

  3. C

    (i, iv)

  4. D

    (iii, iv)

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    Solution:

    Resultant y=y1+y2+y3
        

                y=a sin ωt-45o+a sin ωt+a sinωt+45o        y=1+2a sin ωt  
    So the phase of the resulting motion relative to the first (1) is 45°.
     As       Energy (Amplitude)2 So       ERES=1+2aa2=3+22

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