Two cells of emf E1 and E2 are connected to two resistors R1 and R2 as shown. If E2 is short circuited then currents through R1 and R2 are

Two cells of emf E₁ and E₂ are connected to two resistors R₁ and R₂ as shown. If E₂ is short circuited then currents through R₁ and R₂ are

A
$\frac{E_{1}}{R_{2}}, 0$
B
$0, \frac{E_{1}}{R_{2}}$
C
$\frac{E_{1}}{R_{1}}, 0$
D
$0, \frac{E_{1}}{R_{1}}$

Solution:

After short circuiting, R₂ becomes meaningless. Current will not flow through R₂.

So, current will be $\frac{E_{1}}{R_{1}}$

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