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Two cells of emf E₁ and E₂ are connected to two resistors R₁ and R₂ as shown. If E₂ is short circuited then currents through R₁ and R₂ are

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\frac{E_{1}}{R_{2}}, 0

0, \frac{E_{1}}{R_{2}}

\frac{E_{1}}{R_{1}}, 0

0, \frac{E_{1}}{R_{1}}

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detailed solution

Correct option is C

After short circuiting, R₂ becomes meaningless. Current will not flow through R₂.

So, current will be $\frac{E_{1}}{R_{1}}$

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Two cells of emf E1 and E2 are connected to two resistors R1 and R2 as shown. If E2 is short circuited then currents through R1 and R2 are