Two identical strings X and Z made of same material have tension TX and TZ in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio TXTZ is:

A
0.44
B
1.5
C
2.25
D
1.25

Solution:

$f = \frac{1}{2 ℓ} \sqrt{\frac{T}{μ}}$
For identical string $l$ and $μ$ will be same
$\begin{array}{l} f \propto \sqrt{T} \\ \frac{450}{300} = \sqrt{\frac{T_{x}}{T_{y}}} \\ \frac{T_{x}}{T_{y}} = \frac{9}{4} = 2 .25 \end{array}$

FAQ Metallurgy JEE

Conservation of Biodiversity – Definition, Methods, Examples and Strategies

JEE Main Previous Year Papers Questions With Solutions Chemistry Nitro,Amine and Azo Compounds

Democratic Rights Class 9 Extra Questions Civics Chapter 6

Essay on All that Glitters is not Gold in English for Children and Students

Evans Tries an O-level Important Questions Class 12 English

Short and Long Essay on Corruption in English for Children and Students

Essay on Holi

Holi Wishes SMS and Messages for Mobile and Whatsapp

Two identical strings X and Z made of same material have tension T_X and T_Z in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio $\frac{T_{X}}{T_{Z}}$ is:

Solution:

Related content