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Class 10 Electrostatics and Electricity - Complete CBSE Notes & Revision Guide

By Shailendra Singh

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Updated on 5 Nov 2025, 19:00 IST

Introduction to Electrostatics and Electricity

Electrostatics and Electricity form a fundamental chapter in Class 10 CBSE Physics, covering the behaviour of charges at rest and in motion. This comprehensive guide consolidates all essential concepts, formulas, definitions, and practice questions to help students master Chapter 12 effectively.

Understanding electric charge, current, potential difference, resistance, and power is crucial not only for board exams but also for building a strong foundation for higher physics studies.

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Historical Background

The study of electricity dates back to 600 B.C. when Thales of Miletus discovered that rubbing amber with wool attracted light objects like feathers. The Greek word for amber, elektron, gave rise to terms like electricity, electron, and electric charge.

Key Contributors:

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  • Dr. William Gilbert (1540-1603): Systematically studied electrical and magnetic phenomena; introduced terms like 'electric force' and 'electric attraction'
  • C.F. Du Fay (1698-1739): Proposed the existence of two types of electricity - vitreous (positive) and resinous (negative)
  • Benjamin Franklin (1747): Developed the one-fluid model and introduced the terms 'positive' and 'negative' charge

Definitions for Electrostatics

TermDefinition
Electric ChargeThe property of matter that causes electrical and magnetic effects
ElectrificationThe phenomenon of charging a body by adding or removing electrons
Static ElectricityElectricity due to stationary charges on insulating surfaces
ElectrostaticsThe branch of physics dealing with charges at rest
ConductorsMaterials that allow electric charges to flow freely (e.g., metals)
InsulatorsMaterials that do not allow charges to pass through them (e.g., rubber, glass)
Electric CurrentThe rate of flow of electric charge through a conductor
Potential DifferenceWork done per unit charge in moving a charge between two points
ResistanceThe opposition offered by a conductor to the flow of current
Ohm's LawThe current through a conductor is directly proportional to the potential difference across it

Properties of Electric Charge

  1. Quantization: Charge exists in discrete amounts; q = ±ne, where n = 1, 2, 3... and e = 1.6 × 10⁻¹⁹ C
  2. Conservation: Total charge in an isolated system remains constant
  3. Additivity: Net charge is the algebraic sum of individual charges
  4. Two types: Positive and negative
  5. Like charges repel; unlike charges attract
  6. Charge resides on the outer surface of conductors
  7. Invariance: Charge is independent of the speed of the body

Formulas - Consolidated Table

Formula NameMathematical ExpressionExplanation
Electric CurrentI = Q/tCurrent equals charge flowing per unit time
Ohm's LawV = IRPotential difference equals current times resistance
ResistanceR = ρl/AResistance depends on length, area, and resistivity
Series ResistanceR_eq = R₁ + R₂ + R₃ + ...Total resistance is sum of individual resistances
Parallel Resistance1/R_eq = 1/R₁ + 1/R₂ + 1/R₃ + ...Reciprocal of equivalent resistance
Electric PowerP = VI = I²R = V²/RRate of energy consumption or production
Electrical EnergyU = Pt = VIt = I²RtTotal energy consumed over time
Joule's Law of HeatingH = I²RtHeat produced by current in a conductor
Coulomb's LawF = k(q₁q₂)/d²Force between two point charges
Drift VelocityI = neAvdCurrent in terms of electron drift velocity

Where:

  • I = Current (Ampere, A)
  • Q = Charge (Coulomb, C)
  • t = Time (second, s)
  • V = Potential difference (Volt, V)
  • R = Resistance (Ohm, Ω)
  • P = Power (Watt, W)
  • ρ = Resistivity (Ohm-meter, Ω·m)
  • l = Length of conductor (m)
  • A = Area of cross-section (m²)
  • k = 9 × 10⁹ Nm²/C²

Ohm's Law - The Fundamental Relation

The electric current flowing through a metallic conductor is directly proportional to the potential difference applied across its ends, provided the temperature remains constant.

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Mathematical Form: V = IR

V-I Graph: A straight line passing through the origin with slope equal to resistance R.

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Factors Affecting Resistance

  1. Length (l): R ∝ l
  2. Area of cross-section (A): R ∝ 1/A
  3. Material (resistivity ρ)
  4. Temperature

Resistivity vs Conductivity

  • Resistivity (ρ): Intrinsic property of material; SI unit: Ω·m
  • Materials with low resistivity are good conductors

Series and Parallel Connections

Series Connection

  • Same current flows through all resistors
  • Total voltage = V₁ + V₂ + V₃
  • Equivalent resistance increases: R_eq = R₁ + R₂ + R₃
  • Used when you want to increase total resistance

Parallel Connection

  • Same voltage across all resistors
  • Total current = I₁ + I₂ + I₃
  • Equivalent resistance decreases: 1/R_eq = 1/R₁ + 1/R₂ + 1/R₃
  • Used in household wiring
  • Current distribution: I₁/I₂ = R₂/R₁ (inversely proportional to resistance)

Electric Power and Energy

Power

  • Definition: Rate of doing work or energy consumed per unit time
  • SI Unit: Watt (W) = Joule/second
  • Practical Unit: Kilowatt (kW) = 1000 W

Commercial Unit of Energy

  • 1 Unit = 1 kWh = 3.6 × 10⁶ J
  • Used by electricity boards for billing
  • Example: A 100W bulb running for 10 hours consumes 1 kWh = 1 unit

Heating Effect of Current (Joule's Law)

When current flows through a resistor, heat is produced: H = I²Rt joules

Applications:

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  • Electric bulbs (tungsten filament)
  • Electric heater, iron, toaster
  • Electric fuse

Common Numerical Problems & Solution Steps

Problem Type 1: Finding Current Using Ohm's Law

Question: A potential difference of 12V is applied across a resistor of 4Ω. Find the current.

Solution Steps:

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  1. Write given data: V = 12V, R = 4Ω
  2. Apply Ohm's Law: V = IR
  3. I = V/R = 12/4 = 3A

Problem Type 2: Equivalent Resistance in Series

Question: Three resistors of 2Ω, 3Ω, and 5Ω are connected in series. Find equivalent resistance.

Solution Steps:

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  1. For series: R_eq = R₁ + R₂ + R₃
  2. R_eq = 2 + 3 + 5 = 10Ω

Problem Type 3: Equivalent Resistance in Parallel

Question: Two resistors of 6Ω and 3Ω are connected in parallel. Find equivalent resistance.

Solution Steps:

  1. For parallel: 1/R_eq = 1/R₁ + 1/R₂
  2. 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2
  3. R_eq = 2Ω

Quick formula for two resistors: R_eq = (R₁ × R₂)/(R₁ + R₂) = (6×3)/(6+3) = 18/9 = 2Ω

Problem Type 4: Power and Energy Calculation

Question: A 100W bulb is used for 5 hours. Calculate energy consumed in kWh.

Solution Steps:

  1. P = 100W = 0.1 kW
  2. t = 5 hours
  3. Energy = P × t = 0.1 × 5 = 0.5 kWh = 0.5 units

Problem Type 5: Heat Produced

Question: A current of 5A flows through a 10Ω resistor for 2 minutes. Calculate heat produced.

Solution Steps:

  1. I = 5A, R = 10Ω, t = 2 minutes = 120 seconds
  2. H = I²Rt = (5)² × 10 × 120
  3. H = 25 × 10 × 120 = 30,000 J = 30 kJ

10 Multiple Choice Questions (MCQs) with Answers

1. The SI unit of electric charge is:

  • A) Ampere
  • B) Volt
  • C) Coulomb
  • D) Ohm

Answer: C) Coulomb

2. 1 Coulomb of charge is equivalent to the charge carried by:

  • A) 6.25 × 10¹⁸ electrons
  • B) 6.25 × 10¹⁶ electrons
  • C) 1.6 × 10⁻¹⁹ electrons
  • D) 1.6 × 10¹⁹ electrons

Answer: A) 6.25 × 10¹⁸ electrons

3. The device used to measure electric current is:

  • A) Voltmeter
  • B) Ammeter
  • C) Galvanometer
  • D) Rheostat

Answer: B) Ammeter

4. An ammeter should be connected in a circuit:

  • A) In series
  • B) In parallel
  • C) Either in series or parallel
  • D) None of these

Answer: A) In series

5. Ohm's law is not applicable to:

  • A) Metallic conductors
  • B) Electrolytes
  • C) Semiconductors at constant temperature
  • D) Vacuum tubes

Answer: D) Vacuum tubes (Non-ohmic devices)

6. When two resistors are connected in series, the equivalent resistance is:

  • A) Less than the smallest resistance
  • B) Greater than the largest resistance
  • C) Equal to the sum of resistances
  • D) Both B and C

Answer: D) Both B and C

7. The resistivity of a conductor depends on:

  • A) Length
  • B) Area of cross-section
  • C) Material and temperature
  • D) Current flowing

Answer: C) Material and temperature

8. The commercial unit of electrical energy is:

  • A) Joule
  • B) Watt
  • C) Kilowatt-hour
  • D) Volt-ampere

Answer: C) Kilowatt-hour

9. A fuse wire is made of an alloy of:

  • A) Copper and iron
  • B) Tin and lead
  • C) Tin and copper
  • D) Iron and nickel

Answer: C) Tin and copper (low melting point)

10. Which of the following does NOT represent electrical power?

  • A) I²R
  • B) VI
  • C) V²/R
  • D) IR²

Answer: D) IR²

One-Page Revision Sheet for Exams

Quick Formulas

FormulaExpression
CurrentI = Q/t
Ohm's LawV = IR
ResistanceR = ρl/A
SeriesR_s = R₁ + R₂ + ...
Parallel1/R_p = 1/R₁ + 1/R₂ + ...
PowerP = VI = I²R = V²/R
EnergyE = Pt = VIt
HeatH = I²Rt
1 Unit1 kWh = 3.6 × 10⁶ J

Important Points to Remember

  • Charge: Quantized, conserved, scalar quantity
  • 1 Coulomb = 6.25 × 10¹⁸ electrons
  • Current direction: Opposite to electron flow
  • Ohm's Law: V ∝ I (at constant temperature)
  • Good conductors: Low resistance
  • Series: Same current, voltage adds up
  • Parallel: Same voltage, current adds up
  • Ammeter: Low resistance, in series
  • Voltmeter: High resistance, in parallel
  • Fuse: Safety device, melts when current exceeds limit
  • Electric bulb: Tungsten filament (high melting point ~3400°C)

Important Constants

  • Elementary charge (e): 1.6 × 10⁻¹⁹ C
  • Coulomb's constant (k): 9 × 10⁹ Nm²/C²
  • Resistivity of copper: 1.7 × 10⁻⁸ Ω·m

Exam Tips

  1. Always write given data and required quantity first
  2. State the formula before substitution
  3. Check units carefully
  4. For numerical: Show all steps clearly
  5. Remember: In series R increases, in parallel R decreases
  6. Power rating on appliances: e.g., 60W, 220V means power consumed when 220V is applied

Kirchhoff's Laws (Advanced Concept)

Kirchhoff's Current Law (KCL) / Junction Rule

Statement: The algebraic sum of currents at any junction in a circuit is zero.

ΣI = 0 (or) Incoming current = Outgoing current

Basis: Law of conservation of charge

Kirchhoff's Voltage Law (KVL) / Loop Rule

Statement: The algebraic sum of potential differences in any closed loop is zero.

ΣV = 0 (or) Σε = ΣIR

Basis: Law of conservation of energy

Heating Effect of Electric Current - Applications

Useful Applications

  1. Electric Bulb: Converts electrical energy to light (and heat)
  2. Electric Heater: Nichrome wire coil produces heat
  3. Electric Iron: Heating element made of high-resistance alloy
  4. Fuse Wire: Safety device using low melting point alloy

Disadvantages

  • Energy loss in transmission lines
  • Unwanted heating in appliances (needs cooling arrangements)
  • Can damage electronic components

Electric Safety - The Role of Fuse

A fuse is a protective device with a wire of low melting point (usually tin or tin-copper alloy) connected in series with the circuit.

How it works:

  • If current exceeds safe limit → Heat produced (H = I²Rt) increases
  • Fuse wire melts → Circuit breaks → Appliance protected

Types:

  • Cartridge fuse
  • Kit-Kat fuse
  • Fuse plug (household use)

Rating: Fuse wires are rated by maximum current they can carry (e.g., 5A, 15A)

Practical Applications & Real-World Connections

Household Wiring

  • All appliances connected in parallel (same 220V supply)
  • Separate fuses for different sections
  • If one appliance fails, others continue to work

Electric Bills

  • Calculated based on units consumed (kWh)
  • Cost per unit varies by region
  • Energy-efficient appliances reduce bills

Power Rating of Appliances

ApplianceTypical Rating
LED Bulb7-15W
CFL15-25W
Incandescent Bulb60-100W
Tube Light40W
Ceiling Fan75W
Electric Iron1000W
Room Heater2000W
Water Heater2000W

Important Graphs

V-I Graph (Ohmic Conductor)

  • Straight line passing through origin
  • Slope = Resistance (R)
  • Verifies Ohm's Law

V-I Graph (Non-Ohmic Devices)

  • Not a straight line
  • Example: Diode, transistor, filament bulb

Exam Strategy & Preparation Tips

For Theory Questions (3-5 marks)

  1. Define terms clearly with examples
  2. State laws before derivations
  3. Draw neat diagrams where needed
  4. Use bullet points for listing properties

For Numerical Problems (3-4 marks)

  1. Write all given data
  2. Identify required quantity
  3. Choose appropriate formula
  4. Show all calculation steps
  5. Write answer with correct units

Common Mistakes to Avoid

Confusing series and parallel formulas

Wrong unit conversions (kW to W, hours to seconds) Not converting time to seconds in heat calculations

Forgetting to square current in P = I²R

Using wrong formula for resistance (R = ρl/A, not R = lρA)

Practice Questions for Self-Assessment

Numerical Practice

  1. Calculate the equivalent resistance when 2Ω, 3Ω, and 6Ω are connected in parallel.
  2. A wire of resistance 10Ω is doubled in length. What is the new resistance?
  3. How much energy is consumed when a 2kW heater is used for 30 minutes?
  4. Three resistors of 5Ω each are first connected in series, then in parallel. Find the ratio of equivalent resistances.
  5. A current of 0.5A flows through a 100Ω resistor for 10 seconds. Calculate heat produced.

Conceptual Questions

  1. Why is tungsten used for filament in electric bulbs?
  2. Explain why household appliances are connected in parallel, not series.
  3. An ammeter has low resistance while a voltmeter has high resistance. Why?
  4. Why does the cord of an electric heater not glow while the heating element does?
  5. What is the function of an earth wire in domestic circuits?

Conclusion

Mastering Electrostatics and Electricity requires a clear understanding of fundamental concepts, regular practice of numerical problems, and familiarity with formulas. This chapter forms the basis for understanding advanced topics in electricity and electronics in higher classes.

Notes:

  • Electric charge is quantized and conserved
  • Ohm's Law is the cornerstone of circuit analysis
  • Series and parallel connections have distinct characteristics
  • Electric power and energy calculations are crucial for real-world applications
  • Safety measures like fuses prevent electrical hazards

Regular revision using the one-page sheet, solving MCQs, and practicing numericals will ensure excellent performance in board exams

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FAQs on Class 10 Electrostatics and Electricity CBSE Notes

What is the difference between current and charge?

Charge (Q) is a property of matter measured in coulombs. Current (I) is the rate of flow of charge, measured in amperes (I = Q/t).

Why is resistance in parallel less than each individual resistance?

Because multiple paths are available for current flow, reducing overall opposition.

Can we use copper wire as a fuse?

No, copper has a high melting point. Fuse wire must have a low melting point to melt quickly when excess current flows.

What happens to resistance if length is doubled and area is halved?

Since R = ρl/A, resistance becomes 4 times (doubled due to length, doubled again due to halved area).

How is electric shock dangerous?

Electric current passing through the body can disrupt heart rhythm, cause burns, and damage nerves. Always follow safety precautions.

What is the difference between AC and DC current?

The fundamental difference between AC (Alternating Current) and DC (Direct Current) lies in the direction and magnitude of electron flow. In DC current, electrons flow in a single, constant direction from the negative terminal to the positive terminal of a power source, such as a battery or cell. The magnitude of DC current remains constant over time, making it ideal for applications requiring steady voltage and current levels. Common sources of DC include batteries, solar cells, and DC power supplies used in electronic devices like mobile phones, laptops, and LED lights.

In contrast, AC current involves electrons that periodically reverse their direction of flow, typically in a sinusoidal pattern. The voltage and current in AC vary with time, oscillating between positive and negative values at a specific frequency (50 Hz in India, 60 Hz in the USA). This alternating nature makes AC current highly efficient for long-distance power transmission because it can be easily stepped up or down using transformers, minimizing energy loss during transmission. Our household electrical supply operates on AC current at 220-240V. The key advantage of AC over DC for power distribution is that transformers can change AC voltage levels efficiently, whereas DC voltage transformation is more complex and expensive.

The choice between AC and DC depends on the application. DC is preferred for battery-operated devices, electronic circuits, and applications requiring precise voltage control. AC dominates power generation and distribution systems due to its efficiency in transmission over long distances and the ease with which voltage levels can be modified. Understanding this distinction helps students appreciate why batteries provide DC while wall outlets provide AC, and why devices like phone chargers contain adapters to convert AC to DC for electronic components that require stable, unidirectional current flow.

Why are household appliances connected in parallel and not in series?

Household electrical appliances are connected in parallel rather than in series for several critical practical and safety reasons. The most important reason is that parallel connection ensures each appliance receives the full supply voltage (220V in most countries) regardless of how many other devices are operating simultaneously. In a parallel circuit, all components are connected across the same two points, creating multiple pathways for current flow. This means your refrigerator, television, fan, and lights all operate at the rated voltage they're designed for, ensuring optimal performance and preventing damage that could occur from insufficient voltage.

In a series connection, the supply voltage would be divided among all connected appliances according to their resistances. This would mean that as you switch on more devices, the voltage across each device would decrease, causing them to operate inefficiently or not at all. For example, if you connected three 100W bulbs in series across a 220V supply, each would receive only about 73V instead of the rated 220V, causing them to glow very dimly. Moreover, in a series circuit, all devices must be switched on together, and if one appliance fails or is switched off, the entire circuit breaks, and all other devices stop working. Imagine if turning off your bedroom light caused your refrigerator to stop working—this would be completely impractical for household use.

Parallel connection offers the crucial advantage of independent operation. Each appliance can be switched on or off individually using its own switch without affecting other devices. Additionally, if one appliance fails or its fuse blows, other appliances continue to function normally because current can still flow through alternative parallel paths. The total current drawn from the main supply is the sum of individual currents through each appliance, which is why circuit breakers and fuses are rated according to the maximum expected total current. This configuration also allows for flexible power consumption—you can use any combination of appliances simultaneously based on your needs, making parallel connection the universal standard for residential and commercial electrical installations worldwide.