Quadratic equations are one of the most important as well as fundamental topics in algebra, and their roots play a crucial role in understanding their behaviour. In this article, we will explore the concept of quadratic equations, different methods to find their roots, properties of roots, and real-world applications.
A quadratic equation is a polynomial equation of degree two of the form:
ππ₯Β² + ππ₯ + π = 0
where:
π, π, and π are coefficients, with π β 0,
π₯ is the variable.
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The solutions to the quadratic equation are called roots. Roots can be real or complex numbers and represent the values of π₯, satisfying that equation.
There are several methods to find the roots of a quadratic equation. Below, we discuss the most common ones:
The quadratic formula is the most straightforward and widely used method to find the roots of a quadratic equation. The formula is:
π₯ = (βπ Β± β(πΒ² β 4ππ)) / 2π
Here, πΒ² β 4ππ is called the discriminant, and it determines the nature of the roots:
β’ If πΒ² β 4ππ > 0, the equation has two distinct real roots.
β’ If πΒ² β 4ππ = 0, the equation has one real root (a repeated root).
β’ If πΒ² β 4ππ < 0, the equation has two complex roots.
Example:
Solve the quadratic equation 2π₯Β² + 5π₯ β 3 = 0.
Using the quadratic formula:
π₯ = (β5 Β± β(5Β² β 4Γ2Γβ3)) / 2Γ2
π₯ = (β5 Β± β(25 + 24)) / 4
π₯ = (β5 Β± β49) / 4
π₯ = (β5 Β± 7) / 4
Thus, the roots are:
π₯β = (β5 + 7) / 4 = 2 / 4 = 0.5
π₯β = (β5 β 7) / 4 = β12 / 4 = β3
If the quadratic equation can be factored into two binomials, the roots can be found by setting each factor equal to zero.
Example:
Solve the quadratic equation π₯Β² β 5π₯ + 6 = 0.
Factor the equation:
(π₯ β 2)(π₯ β 3) = 0
Set each factor equal to zero:
π₯ β 2 = 0 β π₯ = 2
π₯ β 3 = 0 β π₯ = 3
Thus, the roots are π₯ = 2 and π₯ = 3.
Completing the square is another method used to solve quadratic equations. It involves rewriting the equation in the form (π₯ + π)Β² = π and then solving for π₯.
Example:
Solve the quadratic equation π₯Β² + 6π₯ + 5 = 0.
Step 1: Move the constant term to the other side:
π₯Β² + 6π₯ = β5
Step 2: Complete the square:
π₯Β² + 6π₯ + 9 = β5 + 9
(π₯ + 3)Β² = 4
Step 3: Solve for π₯:
π₯ + 3 = Β±2
π₯ = β3 Β± 2
Thus, the roots are:
π₯β = β3 + 2 = β1
π₯β = β3 β 2 = β5
The roots of a quadratic equation ππ₯Β² + ππ₯ + π = 0 have the following relationship:
1. Sum of the Roots: Sum = βπ / π
2. Product of the Roots: Product = π / π
Quadratic equations have numerous real-life applications, some are discussed below:
1. In physics: Calculating projectile motion, trajectories, and energy.
2. In engineering: Designing structures, analysing forces, and optimizing systems.
3. In economics: Modelling profit, cost, and revenue functions.
4. In geometry: Solving problems related to areas and dimensions.
5. In computer graphics: Understanding curves and shapes.
The discriminant is the part of the quadratic formula under the square root: πΒ² β 4ππ. It helps us determine the nature of the roots.
Yes, if the discriminant is zero (πΒ² β 4ππ = 0), the quadratic equation has one real root (a repeated root).
If the discriminant is negative (πΒ² β 4ππ < 0), the quadratic equation has two complex roots.
The sum of the roots is βπ / π, and the product of the roots is π / π.
Yes, if the discriminant is negative, the quadratic equation has no real roots (only complex roots).
Real roots are solutions that lie on the real number line, while complex roots involve imaginary numbers which are not real (e.g., π = ββ1).
To solve a quadratic equation graphically, plot the equation π¦ = ππ₯Β² + ππ₯ + π and find the points where the graph intersects the π₯-axis (these are the roots).