If there are 999 bases in an RNA that code for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?

Follow the Following Steps to solve

Step 1:

Each codon (a group of bases) has 3 bases in it. So, 3 bases = 1 amino acid.

Step 2:

When you delete the base at position 901, the first 900 bases are unaffected. They are grouped into 300 codons (because 900 divided by 3 is 300).

Step 3:

After the 901st position, things change because of the deletion. You have 998 - 900 = 98 altered bases left.

Step 4:

These 98 altered bases can be grouped into 98/3 = 32.67 codons. Since you can't have a fraction of a codon, it means 32 codons will be complete, but 1 will be incomplete. So, 33 codons in total will be affected.

Conclusion:

So, the correct answer is:

B) 33

And that's why 33 codons will be altered due to the deletion of one base at the 901st position.

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