RD Sharma Class 8 Maths Chapter 22 Mensuration III (Surface Area and Volume of a Right Circular Cylinder)

Understanding the surface area and volume of 3D shapes is a key part of the CBSE Syllabus for Class 8 Maths, and RD Sharma Class 8 Chapter 22 titled "Mensuration III (Surface Area and Volume of a Right Circular Cylinder)" helps students grasp these concepts in a structured and simple way. This chapter explains how to calculate the curved surface area, total surface area, and volume of a right circular cylinder using basic formulas and real-life examples. Whether you are looking for detailed practice or aiming to strengthen your fundamentals, the RD Sharma Class 8 Maths Solutions Chapter 22 can be an excellent guide.

These solutions are designed to match the latest CBSE curriculum and offer step-by-step answers that are easy to follow. For students following the 2025-26 session, these updated resources, including RD Sharma Class 8 Chapter 22 2025-26 content, provide clarity and enhance problem-solving skills. The RD Sharma Class 8 Solutions Mensuration III (Surface Area and Volume of a Right Circular Cylinder) not only complement your classroom learning but also serve as a helpful companion to the NCERT Solutions for Class 8 Maths.

Whether you're revising for exams or preparing for higher-level math, using RD Sharma Class 8 Solutions Chapter 22 ensures you're on the right track. Explore the core concepts with ease and master Mensuration III through logical explanations and plenty of examples provided in the RD Sharma Chapter 22 Class 8 guide.

RD Sharma Class 8 Maths Chapter 22 Mensuration III (Surface Area and Volume of a Right Circular Cylinder) PDF

If you're looking to master Class 8 Maths Chapter 22 Mensuration III (Surface Area and Volume of a Right Circular Cylinder) PDF, the RD Sharma Class 8 Maths Chapter 22 resource is a great tool to start with. This chapter explains the surface area and volume of a right circular cylinder in a simple and practical way.

With step-by-step solutions and clearly explained formulas, the Class 8 Maths Chapter 22 Mensuration III (Surface Area and Volume of a Right Circular Cylinder) Solutions PDF helps students build a strong understanding of 3D shapes. The RD Sharma Class 8 Mensuration III (Surface Area and Volume of a Right Circular Cylinder) PDF is especially helpful for CBSE students who want to revise quickly and learn through solved examples.

Whether you're searching for RD Sharma Chapter 22 Class 8 Mensuration III (Surface Area and Volume of a Right Circular Cylinder) or the full Class 8 Maths Chapter 22 PDF RD Sharma, this guide makes learning easier and exam-ready.

Here are important questions with solutions in equation format from RD Sharma Class 8 Chapter 22 – Mensuration III (Surface Area and Volume of a Right Circular Cylinder). These are crafted in a simple way for easy understanding and useful for practice and revision.

1. Find the curved surface area (CSA) of a cylinder of radius 7 cm and height 10 cm.

Solution:

CSA = 2πrh

= 2 × (22/7) × 7 × 10

= 440 cm²

2. Find the total surface area (TSA) of a cylinder with radius 5 cm and height 12 cm.

Solution:

TSA = 2πr(h + r)

= 2 × (22/7) × 5 × (12 + 5)

= 2 × (22/7) × 5 × 17

= 534.29 cm² (approx.)

3. A cylinder has radius 3.5 cm and height 20 cm. Find its volume.

Solution:

Volume = πr²h

= (22/7) × (3.5)² × 20

= (22/7) × 12.25 × 20

= 770 cm³

4. If the volume of a cylinder is 1000 cm³ and height is 10 cm, find the radius.

Solution:

Volume = πr²h

1000 = (22/7) × r² × 10

r² = (1000 × 7) / (22 × 10)

r² = 31.82

r ≈ √31.82 ≈ 5.64 cm

5. Find the height of a cylinder whose curved surface area is 352 cm² and radius is 4 cm.

Solution:

CSA = 2πrh

352 = 2 × (22/7) × 4 × h

352 = (176/7) × h

h = (352 × 7) / 176

h = 14 cm

6. A cylindrical water tank has a base radius of 2 m and height 7 m. How much water can it hold? (in litres)

Solution:

Volume = πr²h

= (22/7) × (2)² × 7

= (22/7) × 4 × 7 = 88 m³

1 m³ = 1000 litres

So, 88 × 1000 = 88,000 litres

7. Find the radius of a cylinder whose total surface area is 462 cm² and height is 7 cm.

Solution:

TSA = 2πr(h + r)

462 = 2 × (22/7) × r(7 + r)

462 = (44/7) × r(7 + r)

Multiply both sides by 7:

3234 = 44 × r(7 + r)

Divide both sides by 44:

r(7 + r) = 73.5

Try r = 3: 3(7 + 3) = 30 — too small

Try r = 5: 5(7 + 5) = 60 — still small

Try r = 6: 6(7 + 6) = 78

So, r = 6 cm

8. A cylinder has equal height and radius. If the volume is 616 cm³, find the height.

Solution:

Let r = h

Volume = πr²h = πr³

616 = (22/7) × r³

r³ = (616 × 7)/22 = 196

r = ∛196 ≈ 5.8 cm

So, height = 5.8 cm

9. The height of a cylinder is 15 cm and total surface area is 924 cm². Find its radius.

Solution:

TSA = 2πr(h + r)

924 = 2 × (22/7) × r(15 + r)

Simplify: 924 = (44/7) × r(15 + r)

Multiply both sides by 7:

6468 = 44 × r(15 + r)

r(15 + r) = 147

Try r = 3: 3(15 + 3) = 54

Try r = 7: 7(15 + 7) = 154 — close

Try r = 6: 6(15 + 6) = 126

Try r = 7:

r = 7 cm

10. Find the cost of painting the outer surface of a cylinder with radius 6 cm and height 10 cm at ₹2 per cm².

Solution:

CSA = 2πrh

= 2 × (22/7) × 6 × 10 = 376.57 cm² (approx.)

Cost = 376.57 × 2 = ₹753.14

Let me know if you want a downloadable PDF or worksheet format too!

Benefits of Using RD Sharma for Mensuration III (Surface Area and Volume of a Right Circular Cylinder) Maths Examination

Studying Mensuration III (Surface Area and Volume of a Right Circular Cylinder) from RD Sharma Class 8 Maths Chapter 22 helps students prepare better for CBSE Maths exams. The book offers easy-to-follow explanations, real-life examples, and solved questions that build confidence and clarity.

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• Covers full CBSE Class 8 syllabus
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• Structured Layout: Concepts are arranged from basic to advanced level.
• Solved Examples: Every topic includes detailed examples with formulas.
• Practice Exercises: Ample practice questions for better learning.
• CBSE Pattern: Fully aligned with the CBSE Syllabus Class 8 Maths.
• PDF Format Available: Easy to access and download for revision.

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Using RD Sharma Class 8 Maths Chapter 22 offers several advantages:

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When Is the Best Time to Use RD Sharma Class 8 Mensuration III (Surface Area and Volume of a Right Circular Cylinder)?

You can start using RD Sharma Class 8 Solutions Chapter 22 in the following situations:

• During School Lessons: To understand the topic being taught in class.
• Before Exams: For thorough revision using solved examples.
• During Homework: To solve practice problems with guidance.
• While Solving Sample Papers: For extra preparation and self-evaluation.

The Impact of RD Sharma Class 8 Solutions Mensuration III (Surface Area and Volume of a Right Circular Cylinder) in Student’s Preparation

The RD Sharma Class 8 Solutions Mensuration III (Surface Area and Volume of a Right Circular Cylinder) plays an important role in improving a student’s preparation level. Here’s how:

• Boosts Confidence: Students feel more prepared after solving questions.
• Improves Scores: Regular practice leads to better exam performance.
• Reduces Mistakes: Understanding formulas reduces calculation errors.
• Enhances Conceptual Clarity: Helps students visualize 3D shapes like cylinders better.

Bonus Tips for Students:

• Practice daily using the RD Sharma Class 8 Maths Chapter 22 PDF.
• Revise formulas for curved surface area, total surface area, and volume regularly.
• Use NCERT Solutions for Class 8 Maths as a supplement to RD Sharma.
• Attempt mock tests and previous year questions for extra practice.