RD Sharma Solutions for Class 9 Maths Chapter 17 Construction

Here are the RD Sharma Solutions Class 9 Maths Chapter 17 Construction Solutions, designed to help students prepare effectively for their exams. By referring to these solutions and practicing the problems, students can boost their confidence and improve their scores.

RD Sharma Solution for Class 9 Chapter 17 - Question with Answers

1. Construct a triangle ABC given AB = 6 cm, AC = 5 cm, and ∠A = 60°.

Solution: Draw AB = 6 cm. At A, construct ∠BAC = 60°, and cut AC = 5 cm on this ray. Join BC to complete triangle ABC.

Solution: Draw XY = 7 cm, make ∠XYZ = 45°, and cut YZ = 6 cm on the ray. Join XZ to complete the triangle.

Solution: Draw QR = 5 cm, construct ∠PQR = 90°, cut PQ = 4 cm on the ray, and join PR.

Solution: Begin with BC = 6 cm, construct ∠ACB = 45°, cut AB = 7 cm, and complete triangle ABC.

Solution: Draw AB = 5 cm, construct ∠A = 90°, cut AC = 6 cm, and join BC.

Exercise 17.2 (Bisecting Angles and Lines)

6. Construct and bisect ∠ABC = 60°.

Solution: Draw ∠ABC = 60° using compass and bisect it using arc method.

Solution: Draw 8 cm line, use compass from both ends to draw arcs, and join intersection to bisect.

Solution: Construct ∠ABC = 90° and bisect it using compass to get 45°.

Solution: Use arcs from A and B and draw perpendicular bisector.

Solution: Use compass to make ∠120° and divide it into two 60° angles.

Exercise 17.3 (Perpendiculars from Points)

11. Draw a line and a point above it. Construct a perpendicular from the point to the line.

Solution: Use compass to draw equal arcs and create perpendicular through intersections.

Solution: Use compass to mark equal arcs and draw perpendicular at the point.

Solution: Follow standard construction of perpendicular from external point.

Solution: Use arcs and label midpoint from intersection.

Solution: Use compass to construct 90° at the ray’s origin.

Exercise 17.4 (Triangle Constructions with Special Conditions)

16. Construct a triangle with base 5 cm, height 4 cm, and angle at base 60°.

Solution: Use base and height to create perpendicular, then angle to complete triangle.

Solution: Draw base, construct both angles, and mark the vertex from their intersection.

Solution: Construct both angles at PQ ends and join their intersection as R.

Solution: Use angle constructions and intersection to form triangle.

Solution: Construct right angle at B and mark points at given lengths.

Advanced Constructions (Altitude, Medians)

21. Construct triangle and draw altitudes from each vertex.

Importance of RD Sharma Solutions for Class 9 Maths Chapter 17 – Constructions

1. Builds Strong Geometric Foundations

Chapter 17 of RD Sharma covers Constructions, a vital area of geometry that lays the groundwork for higher mathematical reasoning and precision. The solutions provided help students understand how to draw geometrical figures like angles, triangles, perpendiculars, and bisectors using only a ruler and compass. These fundamental skills are essential for both academic exams and real-world applications in architecture, engineering, and design.

2. Step-by-Step Visual Approach

Each question in RD Sharma’s solution is solved with clear, step-by-step instructions along with corresponding geometric figures. This visual and procedural clarity enables students to follow the logic behind each construction, helping them grasp not just the “how,” but also the “why” behind each method.

3. Aligned with CBSE Curriculum

The RD Sharma Solutions strictly follow the CBSE syllabus for the academic year 2025–26. This ensures that students are well-prepared for school exams and internal assessments without missing out on any topic mandated by the board.

4. Enhances Accuracy and Precision

Geometry demands a high level of accuracy. By practicing from these structured solutions, students develop precision in using instruments like the compass and ruler—an important skill set for mathematical drawing tasks. The solutions emphasize exact measurements, correct angles, and systematic constructions.

5. Simplifies Complex Concepts

Even complex geometrical constructions are broken down into easy-to-understand steps using simple language. This makes the topic accessible to all students, including those who may struggle with visualizing or executing geometric methods on their own.

6. Useful for Competitive Exams

Constructions are a common part of Olympiads, NTSE, and other entrance tests. Practicing RD Sharma’s solutions gives students an extra edge in competitive exam preparation by strengthening their conceptual clarity and problem-solving skills in geometry.

7. Boosts Exam Confidence

Since the solutions cover each question from the RD Sharma textbook thoroughly, students feel more confident while attempting similar problems in their exams. Regular practice also improves time management and accuracy during tests.

8. Guided by Expert Faculty

These solutions are prepared by subject matter experts who understand students’ learning curves and common errors. Their guidance through these solutions ensures a deeper understanding and correct application of geometric principles.