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By Brijesh Sharma
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Updated on 17 Oct 2025, 16:13 IST
The topic of Coordination Compounds is one of the most intresting and scoring topics in Class 12 Chemistry. Many students find it little confusing at first, but once the basic concept of central metal atom and ligands are clear, solving MCQs becomes much easy. This page provide complete set of MCQs for the Coordination Compounds chapter 9 of Class 12 Chemistry designed from the latest CBSE class 12 chemistry Syllabus and NCERT Solutions for class 12 chemistry. These MCQs questions help students to understand important formula, IUPAC nomenclature, oxidation number, and geometry of complex compounds.
The Class 12 Chemistry MCQ for Coordination Compounds also includes important tricky questions for quick revision before exams. Practicing coordination compounds class 12 mcq regularly helps to improve logical thinking and problem solving speed. Each coordination compounds mcq class 12 is made as per board pattern to make student confident in Class 12 board exams and competitive tests like JEE Exam or NEET Exam. We have also included coordination chemistry mcq with answers so that learners can check their preparation instantly.
Ques: Which of the following is a coordination compound?
a) NaCl
b) [Cu(NH₃)₄]SO₄
c) K₂SO₄
d) Na₂CO₃
Ans: b
Explanation: It contains a complex ion [Cu(NH₃)₄]²⁺ coordinated with NH₃ ligands.
Ques: In [Co(NH₃)₆]Cl₃, the coordination number of Co is:
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a) 3
b) 4
c) 6
d) 2
Ans: c
Explanation: Six NH₃ ligands surround Co³⁺ ion.
Ques: The oxidation number of Co in [Co(C₂O₄)₃]³⁻ is:
a) +2
b) +3
c) 0
d) +1
Ans: b
Explanation: Each oxalate (C₂O₄²⁻) = −2 × 3 = −6; total charge = −3 ⇒ Co = +3.
Ques: Which of the following is an example of a bidentate ligand?
a) NH₃
b) H₂O
c) C₂O₄²⁻
d) CN⁻
Ans: c
Explanation: Oxalate ion (C₂O₄²⁻) can attach through two oxygen atoms.
Ques: In [Ni(CO)₄], Ni has an oxidation number of:
a) +2
b) 0
c) −1
d) +1
Ans: b
Explanation: CO is a neutral ligand; total charge = 0.
Ques: Which of the following is an ambidentate ligand?
a) CN⁻
b) NO₂⁻
c) NH₃
d) H₂O
Ans: b
Explanation: NO₂⁻ can coordinate via N (nitro) or O (nitrito).
Ques: [Fe(CN)₆]⁴⁻ exhibits:
a) High spin complex
b) Low spin complex
Ans: b
Explanation: CN⁻ is a strong field ligand causing pairing of electrons.
Ques: Which one of the following has a coordination number 4 and tetrahedral geometry?
a) [Ni(CN)₄]²⁻
b) [NiCl₄]²⁻
c) [Cu(NH₃)₄]²⁺
d) [Co(NH₃)₆]³⁺
Ans: b
Explanation: Cl⁻ is weak field → sp³ hybridization → tetrahedral.
Ques: In [Cr(H₂O)₆]³⁺, the type of hybridization is:
a) sp³d²
b) d²sp³
c) dsp²
d) sp³
Ans: b
Explanation: Inner orbital complex (low spin) → d²sp³ hybridization.
Ques: Which ligand causes maximum crystal field splitting?
a) Cl⁻
b) CN⁻
c) H₂O
d) NH₃
Ans: b
Explanation: CN⁻ is a strong field ligand (highest in spectrochemical series).
Ques: [Co(NH₃)₅Br]SO₄ and [Co(NH₃)₅SO₄]Br are examples of:
a) Ionization isomerism
b) Hydrate isomerism
Ans: a
Explanation: Different counter-ions in the coordination sphere.
Ques: Which pair shows linkage isomerism?
a) [Co(NH₃)₆]Cl₃
b) [Co(NO₂)(NH₃)₅]²⁺ and [Co(ONO)(NH₃)₅]²⁺
Ans: b
Explanation: NO₂⁻ can coordinate via N or O.
Ques: Which is optical isomer?
a) [Co(en)₃]³⁺
b) [Co(NH₃)₆]³⁺
Ans: a
Explanation: "en" (ethylenediamine) is bidentate → forms chiral complex.
Ques: [Pt(NH₃)₂Cl₂] shows:
a) Geometrical isomerism
b) Optical isomerism
Ans: a
Explanation: Can exist as cis and trans forms.
Ques: [CoCl₂(en)₂]⁺ has how many geometrical isomers?
a) 1
b) 2
c) 3
d) 4
Ans: b
Explanation: cis and trans possible with two bidentate ligands.
Ques: [MA₂B₂] type complexes show:
a) Geometrical isomerism
b) Ionization isomerism
Ans: a
Ques: [Co(NH₃)₆]³⁺ shows:
a) Optical
b) Geometrical
c) None
Ans: c
Explanation: All ligands same → no isomerism.
Ques: [Co(en)₂Cl₂]⁺ has:
a) Two optical isomers
b) No optical isomer
Ans: a
Ques: Which is an example of coordination isomerism?
a) [Cu(NH₃)₄][PtCl₄] and [Pt(NH₃)₄][CuCl₄]
Ans: a
Ques: Hydrate isomerism occurs in:
a) [Cr(H₂O)₆]Cl₃, [Cr(H₂O)₅Cl]Cl₂·H₂O
Ans: True
Explanation: Differ in number of coordinated water molecules.
Ques: Which theory explains color and magnetism of complexes?
a) Valence Bond Theory
b) Crystal Field Theory
Ans: b
Ques: In [Fe(CN)₆]⁴⁻, Fe is:
a) diamagnetic
b) paramagnetic
Ans: a
Explanation: CN⁻ causes pairing → no unpaired electrons.
Ques: Hybridization in [Ni(CN)₄]²⁻ is:
a) sp³
b) dsp²
Ans: b
Explanation: Square planar, low spin → dsp².
Ques: [Cu(NH₃)₄]²⁺ color is due to:
a) Charge transfer
b) d–d transition
Ans: b
Ques: Colorless complex forms when:
a) No unpaired d-electrons
Ans: a
Ques: Which is paramagnetic?
a) [Co(NH₃)₆]³⁺
b) [Fe(H₂O)₆]²⁺
Ans: b
Explanation: Fe²⁺ has 4 unpaired electrons.
Ques: Valence bond theory fails to explain:
a) Color
Ans: a
Ques: In tetrahedral field splitting, Δt is:
a) smaller than Δo
Ans: a
Ques: CFSE for high-spin d⁵ octahedral =
a) 0
Ans: a
Ques: Ligand field strength order:
Cl⁻ < H₂O < NH₃ < CN⁻
Ques: [Cr(H₂O)₄Cl₂]Cl name:
Ans: Tetraaquadichloridochromium(III) chloride
Ques: [Co(NH₃)₆]Cl₃ name:
Ans: Hexaamminecobalt(III) chloride
Ques: [Pt(NH₃)₂Cl₂] name:
Ans: Diamminedichloridoplatinum(II)
Ques: [Fe(C₂O₄)₃]³⁻ name:
Ans: Trioxalatoiron(III)
Ques: [Cu(NH₃)₄]SO₄ name:
Ans: Tetraamminecopper(II) sulfate
Ques: [Ag(NH₃)₂]⁺ name:
Ans: Diamminesilver(I)
Ques: [Ni(CO)₄] name:
Ans: Tetracarbonylnickel(0)
Ques: [Zn(NH₃)₄]²⁺ name:
Ans: Tetraamminezinc(II)
Ques: [Cr(H₂O)₆]³⁺ name:
Ans: Hexaaquachromium(III)
Ques: [Co(en)₃]³⁺ name:
Ans: Tris(ethylenediamine)cobalt(III)
Ques: Which complex is used in photography?
Ans: [Ag(NH₃)₂]⁺ — forms during silver halide dissolution.
Ques: Which compound is used in electroplating silver?
Ans: K[Ag(CN)₂]
Ques: Which complex is known as Prussian Blue?
Ans: Fe₄[Fe(CN)₆]₃
Ques: Which shows spin-only magnetic moment of 5.92 BM?
Ans: High-spin d⁵ (Mn²⁺)
Ques: Which complex is square planar?
Ans: [Ni(CN)₄]²⁻
Ques: Which ligand forms chelates?
Ans: en, C₂O₄²⁻
Ques: Chelate effect means:
Ans: Greater stability due to ring formation.
Ques: EDTA⁴⁻ is:
Ans: Hexadentate ligand.
Ques: Coordination number depends on:
Ans: Number of donor atoms bonded to central metal.
Ques: Which of the following complexes is colorless?
a) [Sc(H₂O)₆]³⁺
Ans: a
Explanation: Sc³⁺ has no d-electrons → no d–d transition.
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Coordination compounds are substances where a central metal atom or ion is linked to ligands through coordinate bonds. They are an important part of inorganic chemistry and carry good weightage in board exams.
Practicing MCQs helps students strengthen their conceptual knowledge, increases speed in solving objective‑type questions, and prepares them for competitive exams like JEE and NEET.
Yes, all coordination compounds class 12 mcq questions are prepared according to the updated CBSE Class 12 Chemistry syllabus and NCERT guidelines.
NCERT Solutions provide accurate explanations that help in understanding the theory part clearly, making it easier to solve complex MCQs with confidence.
Yes, coordination chemistry mcq with answers are included so students can cross‑check their responses and analyze their understanding of the topic.