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By rohit.pandey1
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Updated on 12 Sep 2025, 10:54 IST
Class 8 Practical Geometry MCQs are one of the best ways to prepare for this important chapter. Practical Geometry is a critical part of the CBSE Class 8 syllabus, and many students feel nervous about it because it has many constructions and concepts. But don’t worry — most questions from this topic in exams are asked as MCQs (Multiple Choice Questions).
By practicing more Class 8 Maths MCQs, students can build confidence, revise faster, and score higher marks. For your benefit, we have put together all important Class 8 Math Chapter 4 Practical Geometry MCQs in one place. You can download these MCQs or practice them online.
Q1. Which instrument is used to draw arcs and circles in Practical Geometry?
(a) Ruler
(b) Protractor
(c) Compass
(d) Divider
Answer: (c) Compass
Explanation: A compass is the correct instrument for drawing arcs/circles by keeping one leg fixed and moving the pencil leg.
Why Others Are Incorrect:
Q2. The straight edge of a ruler is used to:
(a) Measure angles
(b) Draw straight lines
(c) Mark arcs
(d) Draw circles
Answer: (b) Draw straight lines
Explanation: The ruler’s straight edge is specifically designed to draw or measure straight lines.
Why Others Are Incorrect:
Q3. Which of the following is NOT required for constructing an angle of 90°?
(a) Compass
(b) Protractor
(c) Divider
(d) Ruler
Answer: (c) Divider
Explanation: A divider is not used for angle construction; it is used only for comparing lengths.
Why Others Are Incorrect:
Q4. To construct an angle bisector, the compass is placed at:
(a) The vertex of the angle
(b) The midpoint of one arm
(c) Any random point
(d) Intersection of arcs
Answer: (a) The vertex of the angle
Explanation: Bisector construction begins at the vertex so arcs can be drawn on both arms.
Other Options: Midpoint/random points are wrong starting places, and intersection of arcs is the result, not the starting step.
Q5. Constructing a perpendicular bisector divides a line segment into:
(a) Two equal angles
(b) Two equal halves
(c) Unequal parts
(d) Right triangles
Answer: (b) Two equal halves
Explanation: Perpendicular bisector cuts the line segment into two equal parts at 90°.
Q6. Which of the following angles can be constructed exactly using compass and straightedge?
(a) 30°
(b) 40°
(c) 75°
(d) 55°
Answer: (a) 30°
Explanation: 30° is constructed by bisecting a 60° angle (which can be drawn with equilateral triangle steps).
Q7. A triangle can be constructed only if its three sides:
(a) Are equal
(b) Are greater than the sum of any two sides
(c) Satisfy triangle inequality
(d) Are less than any two sides
Answer: (c) Satisfy triangle inequality
Explanation: The sum of any two sides must be greater than the third side.
Q8. Which is NOT a valid condition for unique triangle construction?
(a) SSS
(b) SAS
(c) SSA
(d) ASA
Answer: (c) SSA
Explanation: SSA can form two different triangles (ambiguous case), hence not unique.
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Q9. RHS criterion is used when:
(a) Two sides and included angle known
(b) All three sides known
(c) Right angle, hypotenuse and one side known
(d) Two angles and one side known
Answer: (c) Right angle, hypotenuse and one side known
Explanation: RHS guarantees one unique right triangle.
Q10. Which set of data cannot guarantee unique triangle construction?
(a) 3 sides
(b) 2 angles and 1 side
(c) 2 sides and included angle
(d) 2 sides and non-included angle
Answer: (d) 2 sides and non-included angle
Explanation: This case may give two triangles (ambiguous SSA case).
Q11. To construct a quadrilateral uniquely, we need:
(a) Any four sides
(b) Four sides and one angle
(c) Four sides and one diagonal
(d) Three sides and one angle
Answer: (c) Four sides and one diagonal
Explanation: These measurements allow forming two connected triangles, uniquely fixing the quadrilateral.
Q12. Which quadrilateral can be constructed with two adjacent sides and one diagonal?
(a) Rectangle
(b) Parallelogram
(c) Any quadrilateral
(d) Kite or rhombus
Answer: (d) Kite or rhombus
Explanation: These shapes are defined by equal adjacent sides + diagonal property.
Q13. In a parallelogram, which property is used for construction?
(a) Opposite sides are equal and parallel
(b) All sides equal
(c) Diagonals perpendicular
(d) All angles 90°
Answer: (a) Opposite sides are equal and parallel
Explanation: This property fixes the fourth vertex once three vertices are drawn.
Q14. Verification of SSS triangle construction is done by:
(a) Measuring one side
(b) Measuring all sides
(c) Measuring angles only
(d) Checking perimeter
Answer: (b) Measuring all sides
Explanation: If all three sides match the given data, construction is correct.
Q15. An error in construction can be detected if:
(a) Figure looks symmetrical
(b) Given conditions are satisfied
(c) Measurements don’t match data
(d) Drawn with ruler only
Answer: (c) Measurements don’t match data
Explanation: Comparing measurements with given data is the surest way to detect errors.
Q16. When constructing a perpendicular bisector, the arcs from both ends should:
(a) Be random
(b) Intersect on both sides of the segment
(c) Only intersect on one side
(d) Not intersect
Answer: (b) Intersect on both sides
Explanation: This ensures a true perpendicular line through the midpoint.
Q17. Which step is done last when constructing a triangle by SAS?
(a) Draw base side
(b) Construct given angle
(c) Cut off required length on other side
(d) Join new point to end of base
Answer: (d) Join new point to end of base
Explanation: Joining the point completes the triangle construction.
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SSS (three sides), SAS (two sides and included angle), ASA (two angles and included side), and RHS (right angle, hypotenuse, and one side).
Measure its sides, diagonals, and angles to check if they satisfy the given data and properties of the quadrilateral.
Ruler (scale), compass, protractor, set-squares, sharp pencil, and eraser.
It ensures that the three sides can form a closed figure; otherwise, construction is not possible.
Draw the base side of given length first, then construct the given angle at one end of the base.
So that arcs intersect above and below the line, ensuring the bisector is at the correct midpoint and at 90°.