RD Sharma Solutions for Class 6 Maths Chapter 23 Data Handling III (Bar Graphs)

RD Sharma Solutions for Class 6 Maths Chapter 23 – Data Handling III (Bar Graphs) help students learn how to represent and interpret data using bar graphs, one of the most important tools in data handling. This chapter teaches students how to draw, read, and compare information through vertical and horizontal bars, making complex data easier to understand at a glance. With the help of RD Sharma Class 6 Chapter 23 Solutions, students gain step-by-step guidance on solving bar graph problems confidently.

Practicing bar graph questions strengthens logical thinking, improves observation skills, and prepares students for higher-level topics in statistics and data analysis. Since data interpretation is a common part of competitive exams, Olympiads, and future classes, building a strong base through these exercises is essential. The clear explanations in RD Sharma Solutions Class 6 Maths make it easy for students to grasp key concepts and apply them effectively in real-life and academic situations.

RD Sharma Solutions for Class 6 Maths Chapter 23 – Data Handling III (Bar Graphs) introduce students to a simple yet powerful way of representing and comparing data using bars. This chapter helps learners understand how to organize data clearly and interpret it accurately, making it an important topic for both academic learning and real-life application.

RD Sharma Solutions for Class 6 Maths Chapter 23 Data Handling III (Bar Graphs)

A bar graph is a visual representation of data using rectangular bars of equal width, where the length of each bar is proportional to the value it represents. Bar graphs help in comparing different sets of data easily and clearly.

Topics Covered in Chapter 23:

1. Drawing vertical and horizontal bar graphs
2. Understanding scales and units
3. Comparing data using bar lengths
4. Interpreting bar graphs

Answering questions based on bar graphs

Exercise 23.1: Involves reading, interpreting, and drawing bar graphs using given data tables. Students learn how to choose appropriate scales and represent data visually.

Practicing from RD Sharma Solutions Class 6 Maths Chapter 23 helps build strong data interpretation skills, which are vital in higher classes, Olympiads, and reasoning-based exams. It also improves analytical thinking by encouraging students to read and compare data efficiently.

RD Sharma Solutions for Class 6 Maths Chapter 23 Data Handling III (Bar Graphs) Download PDF

Download RD Sharma Solutions for Class 6 Maths Chapter 23 – Data Handling III (Bar Graphs) in free PDF format, expertly solved by qualified Maths teachers at Infinity Learn. Get solutions for all exercise questions to strengthen your understanding of bar graphs and improve your performance in exams. These solutions cover the full syllabus and are perfect for quick revision. 

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Access Answers to Maths RD Sharma Solutions for Class 6 Chapter 23

Q1. The table shows the number of students participating in different sports at a school:

Draw a bar graph to represent this data. Then answer:
a) Which sport has the maximum participation?
b) What is the difference between the number of students playing cricket and table tennis?
Answer 1:
a) Cricket has the maximum participation with 45 students.
b) Difference between students playing cricket and table tennis = 45 - 20 = 25 students.

2. The following bar graph shows the marks obtained by Rahul in different subjects:

English: 75 marks
Hindi: 80 marks
Mathematics: 95 marks
Science: 85 marks
Social Studies: 70 marks

If the maximum marks in each subject is 100, calculate:
a) Rahul's total percentage
b) In which subject did Rahul score the highest marks?
Answer 2:
a) Total marks obtained = 75 + 80 + 95 + 85 + 70 = 405
Total maximum marks = 5 × 100 = 500
Percentage = (405 ÷ 500) × 100 = 81%
b) Rahul scored the highest marks in Mathematics (95 marks).

3. The bar graph below shows the rainfall (in mm) in a city for the first six months of a year:

January: 15 mm
February: 10 mm
March: 25 mm
April: 40 mm
May: 65 mm
June: 120 mm

Answer the following questions:
a) In which month was the rainfall exactly four times that of February?
b) What is the total rainfall from January to June?
c) In which month was the increase in rainfall from the previous month the greatest?
Answer 3:
a) Rainfall in February = 10 mm
Four times of February's rainfall = 4 × 10 = 40 mm
So, the rainfall was exactly four times that of February in April (40 mm).
b) Total rainfall = 15 + 10 + 25 + 40 + 65 + 120 = 275 mm
c) Increase from January to February = 10 - 15 = -5 mm
Increase from February to March = 25 - 10 = 15 mm
Increase from March to April = 40 - 25 = 15 mm
Increase from April to May = 65 - 40 = 25 mm
Increase from May to June = 120 - 65 = 55 mm
The greatest increase was from May to June (55 mm).

4. The following data shows the number of books sold by a bookstore during different months:

Draw a bar graph to represent this data and answer:
a) What is the average number of books sold per month?
b) By what percentage did the number of books sold increase from January to May?
Answer 4:
a) Average number of books sold = (350 + 400 + 300 + 450 + 500) ÷ 5 = 2000 ÷ 5 = 400 books
b) Increase = 500 - 350 = 150 books
Percentage increase = (150 ÷ 350) × 100 = 42.86% 

5. The bar graph shows the number of bicycles manufactured by a company during five consecutive years:

If the cost of manufacturing one bicycle is ₹2000, calculate:
a) The total cost of manufacturing bicycles in all five years
b) By what percentage did production increase from 2020 to 2024?
c) What was the average annual production over the five years?
Answer 5:
a) Total bicycles manufactured = 1500 + 2000 + 1800 + 2500 + 3000 = 10,800
Total manufacturing cost = 10,800 × ₹2000 = ₹21,600,000
b) Percentage increase = [(3000 - 1500) ÷ 1500] × 100 = (1500 ÷ 1500) × 100 = 100%
c) Average annual production = 10,800 ÷ 5 = 2,160 bicycles per year

6. The bar graph shows the average temperature (in °C) of a city during different months:

Create a double bar graph comparing this data with another city whose temperatures are consistently 5°C lower throughout these months. Then answer:
a) What is the difference in temperature between the two cities in May?
b) What is the average temperature of the second city over the six months?
Answer 6:
a) Temperature of first city in May = 32°C
Temperature of second city in May = 32 - 5 = 27°C
Difference = 5°C
b) Average temperature of second city = (7 + 10 + 15 + 20 + 27 + 30) ÷ 6 = 109 ÷ 6 = 18.17°C

7. The following data shows the expenditure (in thousands of rupees) of a family on different items in a month:

Create a bar graph and answer:
a) What percentage of the total expenditure is spent on food?
b) How much more money is spent on housing compared to transportation?
c) If the family's monthly income is ₹40,000, how much do they save each month?
Answer 7:
a) Total expenditure = ₹(12 + 8 + 6 + 4 + 5) thousand = ₹35 thousand
Percentage spent on food = (12 ÷ 35) × 100 = 34.29%
b) Difference = ₹8,000 - ₹4,000 = ₹4,000
c) Monthly income = ₹40,000
Total expenditure = ₹35,000
Monthly savings = ₹40,000 - ₹35,000 = ₹5,000

8. The bar graph shows the number of students who scored different ranges of marks in a mathematics test:

Answer the following questions:
a) How many students took the test?
b) What percentage of students scored more than 60 marks?
c) What is the modal class of marks?
d) If 40 marks is the passing score, what percentage of students failed the test?
Answer 8:
a) Total number of students = 5 + 12 + 18 + 10 + 5 = 50 students
b) Students scoring more than 60 marks = 10 + 5 = 15 students
Percentage = (15 ÷ 50) × 100 = 30%
c) Modal class is 41-60 marks (with 18 students, which is the highest frequency)
d) Students who failed (scored less than 40 marks) = 5 students
Percentage who failed = (5 ÷ 50) × 100 = 10%