Courses
By Brijesh Sharma
|
Updated on 20 Sep 2025, 18:07 IST
The chapter on Aldehydes, Ketones and Carboxylic Acids is one of the most important topics in the CBSE Class 12 Chemistry Syllabus. Students often find this chapter challenging because it include many reactions, mechanism and properties. To make preparation more easy, solving CBSE Class 12 Chemistry MCQs for Aldehydes, Ketones and Carboxylic Acids is very useful. Practicing multiple choice questions help learners to test concept understanding and improve problem solving speed.
These MCQs on Class 12 Chemistry Chapter 12 Aldehydes, Ketones and Carboxylic Acids MCQs are design according to NCERT Solutions and follow the pattern of board exams. They are also connected with NCERT Solutions for Class 12 Chemistry, so that students can revise the concepts quickly. By solving aldehydes ketones and carboxylic acids mcq regularly, students can identify weak areas and focus more on revision.
This set of questions cover all key subtopics like preparation, physical properties, chemical properties and important named reactions. With repeated practice of aldehyde ketone and carboxylic acids mcq or mcq on aldehydes ketones and carboxylic acids, students gain confidence for cbse class 12 board exam.
Here is a set of CBSE Class 12 Chemistry MCQs with answers and explanations for the chapter Aldehydes, Ketones and Carboxylic Acids.
Ques: The functional group of aldehyde is:
a) –COOH
b) –CHO
c) –CO–
d) –OH
Answer: b) –CHO
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Explanation: Aldehydes contain the –CHO group where carbon is attached to hydrogen and double bonded to oxygen.
Ques: The common name of methanal is:
a) Formaldehyde
b) Acetaldehyde
c) Acetone
d) Formic acid
Answer: a) Formaldehyde
Explanation: Methanal (HCHO) is known as formaldehyde, widely used as a preservative.
Ques: The IUPAC name of CH3–CO–CH3 is:
a) Acetaldehyde
b) Propanone
c) Butanone
d) Acetone
Answer: b) Propanone
Explanation: CH3–CO–CH3 is a ketone with three carbons. IUPAC name is propanone.
Ques: Tollen’s reagent is used to test for:
a) Ketones
b) Aldehydes
c) Carboxylic acids
d) Alcohols
Answer: b) Aldehydes
Explanation: Aldehydes reduce Tollen’s reagent (ammoniacal AgNO3) to form silver mirror.
Ques: Which of the following gives iodoform test?
a) Acetone
b) Formaldehyde
c) Benzaldehyde
d) Formic acid
Answer: a) Acetone
Explanation: Compounds with –COCH3 group give iodoform test. Acetone has this group.
Ques: The reduction of aldehydes to primary alcohols is carried out by:
a) LiAlH4
b) H2/Pd
c) NaBH4
d) All of these
Answer: d) All of these
Explanation: Strong and mild reducing agents both reduce aldehydes to primary alcohols.
Ques: The product of oxidation of ketones is:
a) Alcohols
b) Aldehydes
c) Acids
d) None under mild conditions
Answer: d) None under mild conditions
Explanation: Ketones are resistant to mild oxidizing agents. They oxidize with strong agents to give acids.
Ques: The carboxylic group is represented as:
a) –COH
b) –COOH
c) –CO–
d) –OH
Answer: b) –COOH
Explanation: Carboxylic acids contain –COOH group.
Ques: The acidity of carboxylic acid is due to:
a) C=O group
b) –OH group
c) Resonance stabilization of carboxylate ion
d) None
Answer: c) Resonance stabilization of carboxylate ion
Explanation: The carboxylate ion is stabilized by resonance, increasing acidity.
Ques: Which of the following has the highest boiling point?
a) Aldehydes
b) Ketones
c) Carboxylic acids
d) Alcohols
Answer: c) Carboxylic acids
Explanation: Carboxylic acids form strong hydrogen bonds (dimeric), leading to high boiling point.
Ques: Aldol condensation involves:
a) Acidic medium
b) Basic medium
c) Neutral medium
d) Oxidizing medium
Answer: b) Basic medium
Explanation: Aldol condensation occurs in basic medium due to enolate ion formation.
Ques: Which acid is used in vinegar?
a) Formic acid
b) Acetic acid
c) Oxalic acid
d) Propanoic acid
Answer: b) Acetic acid
Explanation: Vinegar contains 5–8% acetic acid.
Ques: Which of the following is most reactive towards nucleophilic addition?
a) Formaldehyde
b) Acetaldehyde
c) Acetone
d) Benzaldehyde
Answer: a) Formaldehyde
Explanation: Less steric hindrance and strong electrophilicity make formaldehyde most reactive.
Ques: Which compound does not give Fehling’s test?
a) Acetaldehyde
b) Formaldehyde
c) Benzaldehyde
d) Ethanol
Answer: c) Benzaldehyde
Explanation: Aromatic aldehydes generally do not give Fehling’s test.
Ques: Esterification of carboxylic acid is carried out in the presence of:
a) Base
b) H2SO4
c) HCl
d) NaOH
Answer: b) H2SO4
Explanation: Conc. H2SO4 acts as catalyst and dehydrating agent in esterification.
Ques: Formalin is:
a) 40% formaldehyde in water
b) 10% formic acid in water
c) Pure aldehyde
d) None
Answer: a) 40% formaldehyde in water
Explanation: Formalin is aqueous solution of formaldehyde.
Ques: Benzaldehyde on oxidation gives:
a) Benzoic acid
b) Benzyl alcohol
c) Acetophenone
d) Phenol
Answer: a) Benzoic acid
Explanation: Mild oxidation converts benzaldehyde to benzoic acid.
Ques: Acetone reacts with hydrazine to form:
a) Oxime
b) Hydrazone
c) Semicarbazone
d) Phenylhydrazone
Answer: b) Hydrazone
Explanation: Ketones react with hydrazine to form hydrazones.
Ques: The reaction between acid chloride and alcohol gives:
a) Amide
b) Anhydride
c) Ester
d) Aldehyde
Answer: c) Ester
Explanation: Alcohol reacts with acid chloride in esterification reaction.
Ques: The acidity of formic acid is due to:
a) Formyl group
b) Resonance
c) –OH group
d) Carboxyl group
Answer: d) Carboxyl group
Explanation: Formic acid has –COOH group responsible for acidity.
Ques: Which compound gives positive iodoform test?
a) Propanone
b) Propanal
c) Benzaldehyde
d) Methanol
Answer: a) Propanone
Explanation: Compounds with –COCH3 group (like acetone) give positive test.
Ques: Which of the following is not a carbonyl compound?
a) Formaldehyde
b) Acetone
c) Methanoic acid
d) Benzaldehyde
Answer: c) Methanoic acid
Explanation: Carboxylic acids are not classified as carbonyl compounds for this context.
Ques: Which is the strongest acid?
a) Formic acid
b) Acetic acid
c) Benzoic acid
d) Propanoic acid
Answer: a) Formic acid
Explanation: Absence of electron-donating alkyl groups makes formic acid strongest.
Ques: Ketones on reduction give:
a) Primary alcohols
b) Secondary alcohols
c) Aldehydes
d) Carboxylic acids
Answer: b) Secondary alcohols
Explanation: Reduction of ketones leads to secondary alcohols.
Ques: Acetaldehyde reacts with HCN to form:
a) Hydroxynitrile
b) Alcohol
c) Aldol
d) Carboxylic acid
Answer: a) Hydroxynitrile
Explanation: Nucleophilic addition of HCN to aldehydes gives cyanohydrin.
Ques: Which acid is dicarboxylic?
a) Acetic acid
b) Oxalic acid
c) Formic acid
d) Benzoic acid
Answer: b) Oxalic acid
Explanation: Oxalic acid has two –COOH groups.
Ques: Cannizzaro reaction is shown by:
a) Formaldehyde
b) Acetone
c) Propanal
d) Acetaldehyde
Answer: a) Formaldehyde
Explanation: Aldehydes without α-hydrogen (like HCHO) undergo Cannizzaro reaction.
Ques: Acetone is commonly called:
a) Nail polish remover
b) Vinegar
c) Spirit
d) Ether
Answer: a) Nail polish remover
Explanation: Acetone is used as solvent in nail polish removers.
Ques: Which is a derivative of acetic acid?
a) Acetyl chloride
b) Acetic anhydride
c) Ethyl acetate
d) All of these
Answer: d) All of these
Explanation: All are derivatives of acetic acid.
Ques: Which reaction converts aldehydes into alcohols?
a) Oxidation
b) Reduction
c) Substitution
d) Hydrolysis
Answer: b) Reduction
Explanation: Aldehydes reduce to primary alcohols.
No courses found
MCQs help students revise concepts, test understanding, and prepare for board.
These MCQs are designed according to NCERT Solutions for Class 12 Chemistry and strictly follow the CBSE Class 12 Chemistry syllabus.
Both contain carbonyl groups, but aldehydes are generally more reactive towards nucleophiles and oxidation compared to ketones.
The MCQs include nomenclature, physical and chemical properties, preparation methods, important named reactions, and tests like Tollen’s and Fehling’s.
Students should solve MCQs topic-wise after studying theory, check detailed explanations, and repeat practice to strengthen weak areas.