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By Brijesh Sharma
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Updated on 9 Oct 2025, 01:00 IST
Amines are an important topic in the CBSE Class 12 Chemistry syllabus, and having a good grip on this chapter is must for scoring higher marks in board as well as competitive exams like NEET Exam or JEE Exam. In this section, we provide MCQ of Amines Class 12 with Answers prepared according to NCERT solutions for Class 12 Chemistry so that students can revise quickly. Practicing amines MCQ helps to understand concepts like classification of amines, preparation methods, chemical properties and their uses in daily life.
The MCQ on Amines Class 12 are designed in such way that they cover both basic and tricky points from the chapter. Many students find this topic little confusing due to reactions and structures, but with these amines Class 12 MCQ and detailed explanations you can clear your doubts easily. We also provide amines Class 12 MCQ PDF so you can study offline. Whether you are searching for MCQ amines Class 12 for exam preparation or just want a quick test of your knowledge, this resource will be helpful.
By regularly solving MCQ of Amines Class 12 you improve speed, accuracy, and confidence. These MCQs questions follow competency-based learning approach, making them aligned with latest board exam patterns.
Here is a complete set of 50 MCQs on Amines Class 12 with answers and explanations, aligned with CBSE Class 12 Chemistry syllabus and NCERT solutions for class 12 chemistry.
Q1. Amines are derivatives of:
a) Alcohols
b) Ammonia
c) Carboxylic acids
d) Ketones
Answer: b) Ammonia
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Explanation: Amines are derived by replacing one or more hydrogen atoms of ammonia (NH₃) with alkyl or aryl groups.
Q2. Which of the following is a secondary amine?
a) CH₃NH₂
b) (CH₃)₂NH
c) (CH₃)₃N
d) Aniline
Answer: b) (CH₃)₂NH
Explanation: Secondary amines have two alkyl groups attached to nitrogen.
Q3. The IUPAC name of CH₃–NH–CH₃ is:
a) Dimethylamine
b) Methylamine
c) Trimethylamine
d) Ethylamine
Answer: a) Dimethylamine
Explanation: Two methyl groups attached to nitrogen make it dimethylamine.
Q4. Which amine is also known as phenylamine?
a) Methylamine
b) Aniline
c) Ethylamine
d) Propylamine
Answer: b) Aniline
Explanation: C₆H₅NH₂ is called aniline or phenylamine.
Q5. Which functional group is present in amines?
a) –OH
b) –NH₂
c) –COOH
d) –CHO
Answer: b) –NH₂
Explanation: The amino group –NH₂ defines amines.
Q6. Which of the following is a tertiary amine?
a) (CH₃)₂NH
b) (CH₃)₃N
c) CH₃NH₂
d) C₆H₅NH₂
Answer: b) (CH₃)₃N
Explanation: Tertiary amines have three alkyl groups on nitrogen.
Q7. Which amine shows the strongest hydrogen bonding?
a) Primary amine
b) Secondary amine
c) Tertiary amine
d) All equal
Answer: a) Primary amine
Explanation: Primary amines have two hydrogens available for hydrogen bonding.
Q8. Among CH₃NH₂, (CH₃)₂NH, (CH₃)₃N, the most basic is:
a) CH₃NH₂
b) (CH₃)₂NH
c) (CH₃)₃N
d) All equal
Answer: b) (CH₃)₂NH
Explanation: In aqueous medium, secondary amine is most basic due to +I effect and availability of lone pair.
Q9. Aniline is less basic than methylamine because:
a) Resonance reduces electron density on N
b) Inductive effect increases electron density
c) Both are equally basic
d) Aniline is sterically hindered
Answer: a) Resonance reduces electron density on N
Explanation: In aniline, lone pair on nitrogen is delocalized with the benzene ring.
Q10. Which of the following amines is aromatic?
a) Methylamine
b) Dimethylamine
c) Aniline
d) Ethylamine
Answer: c) Aniline
Explanation: Aniline has an aryl group attached to nitrogen.
Q11. Carbylamine reaction is shown by:
a) Primary amines
b) Secondary amines
c) Tertiary amines
d) Aromatic amines only
Answer: a) Primary amines
Explanation: Only primary amines form isocyanides with chloroform + alkali.
Q12. The product formed when aniline reacts with bromine water is:
a) Nitroaniline
b) Tribromoaniline
c) Anisole
d) Phenol
Answer: b) Tribromoaniline
Explanation: Aniline reacts with Br₂ water to give white precipitate of 2,4,6-tribromoaniline.
Q13. Which reagent is used to convert amine to diazonium salt?
a) HCl + NaNO₂
b) HNO₃
c) SOCl₂
d) Br₂
Answer: a) HCl + NaNO₂
Explanation: Primary aromatic amine + nitrous acid at 273 K forms diazonium salt.
Q14. Hinsberg’s reagent is:
a) C₆H₅SO₂Cl
b) CHCl₃
c) HNO₃
d) NaOH
Answer: a) C₆H₅SO₂Cl
Explanation: Used to distinguish primary, secondary, tertiary amines.
Q15. Gabriel phthalimide synthesis is used to prepare:
a) Primary amines
b) Secondary amines
c) Tertiary amines
d) Aromatic amines
Answer: a) Primary amines
Explanation: It gives only primary amines.
Q16. Ammonolysis of alkyl halides gives:
a) Alcohols
b) Amines
c) Acids
d) Alkanes
Answer: b) Amines
Explanation: Alkyl halides react with ammonia to give amines.
Q17. Reduction of nitro compounds gives:
a) Alcohols
b) Amines
c) Carboxylic acids
d) Ketones
Answer: b) Amines
Explanation: Nitro group is reduced to amino group.
Q18. Hoffmann bromamide reaction gives:
a) Primary amine
b) Secondary amine
c) Amide
d) Nitro compound
Answer: a) Primary amine
Explanation: Amides react with Br₂ + NaOH to form primary amines with one carbon less.
Q19. Which one of the following is not a method of preparation of amines?
a) Hoffmann bromamide reaction
b) Gabriel synthesis
c) Reduction of nitro compounds
d) Aldol condensation
Answer: d) Aldol condensation
Explanation: Aldol is for aldehydes and ketones, not amines.
Q20. Which is the best method for preparing primary amines without isomers?
a) Gabriel phthalimide synthesis
b) Ammonolysis
c) Reduction of nitro compound
d) Hoffmann bromamide reaction
Answer: a) Gabriel phthalimide synthesis
Explanation: Gabriel method avoids formation of secondary or tertiary amines.
Q21. Benzene diazonium chloride is stable at:
a) 0–5°C
b) 25°C
c) 50°C
d) Room temperature
Answer: a) 0–5°C
Explanation: Diazonium salts decompose above 5°C.
Q22. Gattermann reaction involves replacement of diazonium group with:
a) –H
b) –Cl or –Br
c) –NO₂
d) –OH
Answer: b) –Cl or –Br
Explanation: Gattermann reaction replaces diazonium group with halogen using Cu/HX.
Q23. Sandmeyer’s reaction is useful for:
a) Introducing alkyl group
b) Introducing –Cl, –Br, –CN groups
c) Removing nitrogen group
d) Introducing –OH
Answer: b) Introducing –Cl, –Br, –CN groups
Explanation: Sandmeyer uses Cu salts with diazonium salts.
Q24. Coupling reaction of diazonium salts gives:
a) Phenols
b) Azo dyes
c) Nitro compounds
d) Amines
Answer: b) Azo dyes
Explanation: Diazonium salts couple with phenols or anilines to form azo dyes.
Q25. Diazotisation is the process of:
a) Preparing aldehydes
b) Preparing ketones
c) Converting amine to diazonium salt
d) Preparing alcohols
Answer: c) Converting amine to diazonium salt
Explanation: Primary aromatic amine reacts with nitrous acid to give diazonium salt.
Q26. Boiling point of amines is higher than alkanes due to:
a) Dipole-dipole interactions
b) Hydrogen bonding
c) Ionic bonding
d) Vander Waals forces only
Answer: b) Hydrogen bonding
Explanation: Primary and secondary amines form intermolecular hydrogen bonds.
Q27. The order of solubility of amines in water is:
a) Primary > Secondary > Tertiary
b) Secondary > Tertiary > Primary
c) Tertiary > Secondary > Primary
d) Equal
Answer: a) Primary > Secondary > Tertiary
Explanation: Solubility decreases as hydrogen bonding capability decreases.
Q28. Which one is least basic in aqueous medium?
a) CH₃NH₂
b) (CH₃)₂NH
c) (CH₃)₃N
d) Aniline
Answer: d) Aniline
Explanation: Resonance in aniline reduces electron density on N.
Q29. The basic character of aliphatic amines is due to:
a) Inductive effect of alkyl groups
b) Resonance
c) Aromatic ring
d) Electrostatic repulsion
Answer: a) Inductive effect of alkyl groups
Explanation: Alkyl groups push electrons toward nitrogen, increasing basicity.
Q30. Which medium increases basic strength of amines?
a) Gaseous state
b) Aqueous solution
c) Solid state
d) None
Answer: a) Gaseous state
Explanation: In gas phase, no solvation effect. Basicity depends only on +I effect.
Q31. Hinsberg test is used to distinguish:
a) Alcohols
b) Amines
c) Aldehydes
d) Acids
Answer: b) Amines
Explanation: Differentiates primary, secondary, tertiary amines.
Q32. Which amine does not respond to Hinsberg’s test?
a) Primary
b) Secondary
c) Tertiary
d) All
Answer: c) Tertiary
Explanation: Tertiary amines do not react with Hinsberg’s reagent.
Q33. Primary amine with nitrous acid gives:
a) Alcohol
b) Hydrocarbon
c) Phenol
d) Diazonium salt
Answer: d) Diazonium salt (aromatic) or alcohol (aliphatic)
Explanation: Aromatic → diazonium salt, aliphatic → alcohol + N₂ gas.
Q34. Secondary amine with nitrous acid gives:
a) Nitrosamine
b) Alcohol
c) Diazonium salt
d) Amide
Answer: a) Nitrosamine
Explanation: Characteristic yellow oily nitrosamine.
Q35. Tertiary amine with nitrous acid gives:
a) Nitrosamine
b) Alcohol
c) Salt of amine
d) Hydrocarbon
Answer: c) Salt of amine
Explanation: Forms insoluble amine salt with HNO₂.
Q36. Which compound is used in the preparation of azo dyes?
a) Diazonium salts
b) Carboxylic acids
c) Alcohols
d) Ketones
Answer: a) Diazonium salts
Explanation: Diazonium salts couple to form azo dyes.
Q37. Aniline on acetylation with acetic anhydride gives:
a) Acetanilide
b) Phenol
c) Nitroaniline
d) Benzamide
Answer: a) Acetanilide
Explanation: Used to protect amino group.
Q38. Which of the following amines is used in making artificial silk?
a) Aniline
b) Diphenylamine
c) Methylamine
d) Ethylamine
Answer: a) Aniline
Explanation: Aniline is used in dyes and artificial silk.
Q39. Explosives like TNT are prepared from:
a) Aniline
b) Nitrobenzene
c) Toluene
d) Benzamide
Answer: c) Toluene
Explanation: Toluene nitration gives trinitrotoluene.
Q40. Ethylamine reacts with acetyl chloride to form:
a) Ethanamide
b) Acetamide
c) N-ethylacetamide
d) Aniline
Answer: c) N-ethylacetamide
Explanation: Acylation of amine gives substituted amide.
Q41. The order of basicity in aqueous solution is:
(CH₃)₂NH > CH₃NH₂ > (CH₃)₃N. Why?
Answer: Due to solvation. Secondary amines form stronger hydrogen bonds than tertiary.
Q42. Which method can prepare pure aromatic primary amine?
a) Reduction of nitrobenzene
b) Gabriel synthesis
c) Hoffmann bromamide reaction
d) Ammonolysis
Answer: a) Reduction of nitrobenzene
Explanation: Nitrobenzene reduction gives aniline.
Q43. Which reagent converts amines to alkyl isocyanides (carbylamines)?
a) Chloroform + KOH
b) NaNO₂ + HCl
c) Acetyl chloride
d) HNO₃
Answer: a) Chloroform + KOH
Explanation: Carbylamine test identifies primary amines.
Q44. The product of reduction of diazonium salt with hypophosphorous acid is:
a) Benzene
b) Aniline
c) Phenol
d) Chlorobenzene
Answer: a) Benzene
Explanation: –N₂ group replaced by H.
Q45. Which amine does not undergo acylation?
a) Primary
b) Secondary
c) Tertiary
d) All
Answer: c) Tertiary
Explanation: Tertiary amines lack –NH hydrogen.
Q46. Aniline is less basic than cyclohexylamine because:
a) Inductive effect
b) Resonance
c) Steric hindrance
d) Solvation
Answer: b) Resonance
Explanation: Lone pair delocalization lowers basicity.
Q47. Which amine forms stable diazonium salt at 0–5°C?
a) Ethylamine
b) Aniline
c) Dimethylamine
d) Tertiary butylamine
Answer: b) Aniline
Explanation: Only aromatic diazonium salts are stable.
Q48. Which one is used as intermediate for dyes, drugs, polymers?
a) Aniline
b) Nitrobenzene
c) Phenol
d) Acetanilide
Answer: a) Aniline
Explanation: Aniline is a major industrial raw material.
Q49. Which of the following is true?
a) Aromatic amines are stronger bases than aliphatic amines
b) Aliphatic amines are stronger bases than aromatic amines
c) Both have same basicity
d) Cannot be compared
Answer: b) Aliphatic amines are stronger bases than aromatic amines
Explanation: Resonance in aromatic reduces electron density.
Q50. Which property differentiates primary, secondary and tertiary amines?
a) Physical state
b) Hinsberg test
c) Melting point
d) Odor
Answer: b) Hinsberg test
Explanation: Hinsberg test is a reliable chemical distinction.
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