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By rohit.pandey1
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Updated on 23 Mar 2026, 12:00 IST
The JEE Main Maths Formulas 2026 play a vital role in achieving a high score, especially after the conclusion of JEE Main 2026 Session 1. Mathematics is one of the most time-consuming and calculation-heavy sections, where quick recall of formulas can significantly improve accuracy and speed during the exam.
For aspirants preparing for JEE Main 2026 Session 2 (April 1–10, 2026), mastering a well-structured JEE Main Maths formula sheet PDF is essential. These formulas cover all key topics from the Class 11 and Class 12 Maths syllabus, including Algebra, Calculus, Coordinate Geometry, Trigonometry, and Vectors.
Experts recommend keeping a quick revision Maths formula sheet for JEE 2026 handy for daily practice and last-minute revision before the exam. Whether you are targeting 99+ percentile in JEE Main 2026 or aiming to boost your score in Session 2, consistent formula revision is a proven strategy for success.
Here is a quick overview of how marks are distributed across chapters. Prioritise accordingly:
| Chapter | Approx. Weightage | Expected Questions |
| Calculus (Limits, Diff., Integration) | 20–22% | 5–6 Qs |
| Coordinate Geometry | 17–18% | 4–5 Qs |
| Algebra (Quadratic, Complex, Binomial) | 15–17% | 4–5 Qs |
| Trigonometry | 12–14% | 3–4 Qs |
| Vectors & 3D Geometry | 8–10% | 2–3 Qs |
| Matrices & Determinants | 6–8% | 2 Qs |
| Permutation, Combination & Probability | 6–8% | 2 Qs |
| Sequences, Series & Statistics | 4–6% | 1–2 Qs |
The top 4 chapters — Calculus, Coordinate Geometry, Algebra, and Trigonometry — together account for 65–70% of the Maths marks. Mastering the formulas in these chapters alone can push you past the 60-mark threshold.
The following formulas have appeared in JEE Main PYQs most frequently over the past 5 years (2021–2025). If you have limited revision time, start here. Mastering this list alone can fetch you 36+ marks.
| Formula | Topic |
| d/dx(xⁿ) = n·xⁿ⁻¹ | Differentiation |
| d/dx(sin x) = cos x | d/dx(cos x) = −sin x | Trig Differentiation |
| d/dx(eˣ) = eˣ | d/dx(ln x) = 1/x | Exp/Log Differentiation |
| ∫xⁿ dx = xⁿ⁺¹/(n+1) + C, n ≠ −1 | Integration |
| Chain Rule: dy/dx = (dy/du)·(du/dx) | Differentiation |
| lim(x→0) sin x / x = 1 | Limits |
| ∫u·dv = uv − ∫v·du (ILATE rule) | Integration by Parts |
| lim(x→0) (1+x)ⁿ¹/ˣ = e | Limits |
| Quotient Rule: (u/v)' = (v·u' − u·v') / v² | Differentiation |
| ∫eˣ dx = eˣ + C | Integration |
| Formula | Topic |
| Distance = √[(x₂−x₁)² + (y₂−y₁)²] | Straight Lines |
| (x−h)² + (y−k)² = r² | Circles |
| Parabola y² = 4ax: Focus (a, 0), Directrix x = −a | Parabola |
| Ellipse: e = c/a, c² = a²−b² | Ellipse |
| Tangent length from external point = √(x₁²+y₁²+2gx₁+2fy₁+c) | Circles |
| Distance from point (x₁,y₁) to line ax+by+c=0: |ax₁+by₁+c|/√(a²+b²) | Straight Lines |
| Angle between lines: tanθ = |(m₁−m₂)/(1+m₁m₂)| | Straight Lines |
| Formula | Topic |
| x = [−b ± √(b²−4ac)] / 2a | Quadratic Formula |
| Sum of roots α+β = −b/a | Product αβ = c/a | Vieta's Formulas |
| Tᴿ₊₁ = C(n,r)·aⁿ⁻ʳ·bʳ | Binomial Theorem |
| De Moivre's: (cosθ + i sinθ)ⁿ = cos nθ + i sin nθ | Complex Numbers |
| Sₙ = n/2 [2a + (n−1)d] | AP Sum |
| α²+β² = (α+β)² − 2αβ | Symmetric Functions |
Trigonometry is one of the most formula-dense chapters in JEE Maths, but it is also one of the most predictable. Almost every question is a direct formula application — there is very little unseen problem-solving required. Master these identities and you will rarely drop marks here.
| Formula | Identity Type |
| sin²θ + cos²θ = 1 | Pythagorean Identity |
| 1 + tan²θ = sec²θ | Pythagorean Identity |
| 1 + cot²θ = cosec²θ | Pythagorean Identity |
| sin(A+B) = sinA cosB + cosA sinB | Sum Formula |
| cos(A+B) = cosA cosB − sinA sinB | Sum Formula |
| tan(A+B) = (tanA + tanB) / (1 − tanA tanB) | Sum Formula |
| sin 2A = 2 sinA cosA = 2tanA / (1+tan²A) | Double Angle |
| cos 2A = cos²A − sin²A = 1 − 2sin²A = 2cos²A − 1 | Double Angle |
| tan 2A = 2tanA / (1 − tan²A) | Double Angle |
| sin 3A = 3sinA − 4sin³A | Triple Angle |
| cos 3A = 4cos³A − 3cosA | Triple Angle |
| sinC + sinD = 2 sin((C+D)/2) cos((C−D)/2) | Sum to Product |
| cosC + cosD = 2 cos((C+D)/2) cos((C−D)/2) | Sum to Product |
| 2 sinA cosB = sin(A+B) + sin(A−B) | Product to Sum |
| 2 cosA cosB = cos(A−B) + cos(A+B) | Product to Sum |
| Formula | Condition |
| sin⁻¹x + cos⁻¹x = π/2 | x ∈ [−1, 1] |
| tan⁻¹x + cot⁻¹x = π/2 | All real x |
| tan⁻¹x + tan⁻¹y = tan⁻¹[(x+y)/(1−xy)] | xy < 1 |
| tan⁻¹x − tan⁻¹y = tan⁻¹[(x−y)/(1+xy)] | xy > −1 |
| sin⁻¹(−x) = −sin⁻¹x | Odd function property |
| cos⁻¹(−x) = π − cos⁻¹x | Even function complement |
| 2 tan⁻¹x = sin⁻¹(2x/(1+x²)) = cos⁻¹((1−x²)/(1+x²)) | x ≥ 0 |
| Formula | Application |
| tanθ = Height / Base (Perpendicular/Base) | Angle of elevation or depression problems |
| Sine Rule: a/sinA = b/sinB = c/sinC = 2R | Finding sides or angles in a triangle |
| Cosine Rule: a² = b² + c² − 2bc cosA | Finding the third side when two sides and included angle are known |
| Area of triangle = (1/2)ab sinC = √[s(s−a)(s−b)(s−c)] | Area using sides or angles |
Memory Trick – ASTC Rule: "All Silver Tea Cups" — All functions are positive in Quadrant 1, Silver (Sin) is positive in Q2, Tea (Tan) is positive in Q3, Cups (Cos) is positive in Q4. This single mnemonic covers all sign-rule questions in trigonometry instantly.
JEE Main 2024 (January, Session 1): If sin x + sin y = a and cos x + cos y = b, find the value of tan((x+y)/2).
Solution using Sum-to-Product formulas:
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
sin x + sin y = 2 sin((x+y)/2) cos((x−y)/2) = a ...(i)
cos x + cos y = 2 cos((x+y)/2) cos((x−y)/2) = b ...(ii)
Dividing (i) by (ii): sin((x+y)/2) / cos((x+y)/2) = a/b
Therefore tan((x+y)/2) = a/b
Calculus is the single most important chapter in JEE Main Maths. With 5–6 questions expected each session, these formulas directly translate to 20+ marks. No serious JEE aspirant can afford any gaps here. Every formula below has appeared in at least one JEE Main paper in the last 5 years.
| Limit Formula | Form |
| lim(x→0) sin x / x = 1 | 0/0 form |
| lim(x→0) tan x / x = 1 | 0/0 form |
| lim(x→0) (1 − cos x) / x² = 1/2 | 0/0 form |
| lim(x→0) (eˣ − 1) / x = 1 | 0/0 form |
| lim(x→0) (aˣ − 1) / x = logₑ a | 0/0 form |
| lim(x→0) (1 + x)ⁿ¹/ˣ = e | 1∞ form |
| lim(x→∞) (1 + 1/x)ˣ = e | 1∞ form |
| lim(x→a) (xⁿ − aⁿ) / (x − a) = n·aⁿ⁻¹ | 0/0 form |
| lim(x→0) log(1 + x) / x = 1 | 0/0 form |
| Function f(x) | Derivative f'(x) |
| xⁿ | n·xⁿ⁻¹ |
| eˣ | eˣ |
| aˣ | aˣ · ln a |
| ln x | 1/x |
| logₐ x | 1 / (x ln a) |
| sin x | cos x |
| cos x | −sin x |
| tan x | sec²x |
| cot x | −cosec²x |
| sec x | sec x · tan x |
| cosec x | −cosec x · cot x |
| sin⁻¹x | 1 / √(1−x²) |
| cos⁻¹x | −1 / √(1−x²) |
| tan⁻¹x | 1 / (1+x²) |
| Product Rule: d(uv)/dx | u'v + uv' |
| Quotient Rule: d(u/v)/dx | (v·u' − u·v') / v² |
| Chain Rule: dy/dx | (dy/du) · (du/dx) |
| Integral | Result |
| ∫ xⁿ dx | xⁿ⁺¹/(n+1) + C, n ≠ −1 |
| ∫ eˣ dx | eˣ + C |
| ∫ aˣ dx | aˣ / ln a + C |
| ∫ 1/x dx | ln|x| + C |
| ∫ sin x dx | −cos x + C |
| ∫ cos x dx | sin x + C |
| ∫ sec²x dx | tan x + C |
| ∫ cosec²x dx | −cot x + C |
| ∫ sec x tan x dx | sec x + C |
| ∫ cosec x cot x dx | −cosec x + C |
| ∫ 1/√(1−x²) dx | sin⁻¹x + C |
| ∫ 1/(1+x²) dx | tan⁻¹x + C |
| ∫ 1/√(x²−a²) dx | ln|x + √(x²−a²)| + C |
| ∫ 1/(x²+a²) dx | (1/a) tan⁻¹(x/a) + C |
| Property | Formula |
| Reversal of limits | ∫[a to b] f(x) dx = −∫[b to a] f(x) dx |
| Splitting | ∫[a to b] f(x) dx = ∫[a to c] f(x) dx + ∫[c to b] f(x) dx |
| Even function (−a to a) | ∫[−a to a] f(x) dx = 2∫[0 to a] f(x) dx if f(−x) = f(x) |
| Odd function (−a to a) | ∫[−a to a] f(x) dx = 0 if f(−x) = −f(x) |
| King's property | ∫[0 to a] f(x) dx = ∫[0 to a] f(a−x) dx |
ILATE Rule for Integration by Parts: When applying ∫u·dv = uv − ∫v·du, choose the first function u in this order: Inverse trigonometric → Logarithmic → Algebraic → Trigonometric → Exponential. The function that comes earlier in ILATE becomes u.
JEE Main 2023 (April, Session 2): Evaluate ∫ x·eˣ dx.
Solution using Integration by Parts (ILATE):
u = x (Algebraic), dv = eˣ dx (Exponential) — so u comes first by ILATE.
u = x ⇒ du = dx | v = eˣ
∫ x·eˣ dx = x·eˣ − ∫ eˣ dx = x·eˣ − eˣ + C = eˣ(x − 1) + C
Answer: eˣ(x − 1) + C
Coordinate geometry is the most predictable chapter in JEE Main Maths. The same formula types appear year after year — tangent to circle, tangent to parabola, equation of ellipse, angle between lines. Master these and this chapter becomes free marks.
| Formula | Description |
| Distance = √[(x₂−x₁)² + (y₂−y₁)²] | Distance between two points |
| Midpoint = ((x₁+x₂)/2, (y₁+y₂)/2) | Midpoint formula |
| Section formula: ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)) | Point dividing line in ratio m:n |
| Slope m = (y₂−y₁)/(x₂−x₁) = tanθ | Slope of a line |
| y − y₁ = m(x − x₁) | Point-slope form |
| y = mx + c | Slope-intercept form |
| x/a + y/b = 1 | Intercept form |
| ax + by + c = 0 | General form |
| Perpendicular distance from (x₁,y₁): |ax₁+by₁+c| / √(a²+b²) | Point to line distance |
| Angle between lines: tanθ = |(m₁−m₂)/(1+m₁m₂)| | Acute angle between two lines |
| Parallel condition: m₁ = m₂ | Two lines are parallel |
| Perpendicular condition: m₁·m₂ = −1 | Two lines are perpendicular |
| Formula | Description |
| (x−h)² + (y−k)² = r² | Standard form: centre (h,k), radius r |
| x²+y²+2gx+2fy+c=0; centre (−g,−f), r=√(g²+f²−c) | General form |
| Length of tangent from P(x₁,y₁) = √(x₁²+y₁²+2gx₁+2fy₁+c) | Tangent length from external point |
| Tangent at (x₁,y₁): xx₁+yy₁+g(x+x₁)+f(y+y₁)+c=0 | Equation of tangent at a point on circle |
| Condition of tangency: c = a√(1+m²) for y=mx+c tangent to x²+y²=a² | Line tangent to circle condition |
| Common chord of two circles S₁=0 and S₂=0: S₁−S₂=0 | Equation of radical axis |
| Property | Parabola (y²=4ax) | Ellipse (x²/a²+y²/b²=1, a>b) | Hyperbola (x²/a²−y²/b²=1) |
| Vertex | (0, 0) | (0, 0) | (0, 0) |
| Focus | (a, 0) | (±c, 0) | (±c, 0) |
| Directrix | x = −a | x = ±a/e | x = ±a/e |
| Eccentricity e | e = 1 | e = c/a; c²=a²−b²; 0<e<1 | e = c/a; c²=a²+b²; e>1 |
| Latus Rectum | 4a | 2b²/a | 2b²/a |
| Focal property | SP = ePM | r₁+r₂ = 2a (sum constant) | |r₁−r₂| = 2a (difference constant) |
| Parametric form | (at², 2at) | (a cosθ, b sinθ) | (a secθ, b tanθ) |
| Tangent at (x₁,y₁) | yy₁ = 2a(x+x₁) | xx₁/a²+yy₁/b²=1 | xx₁/a²−yy₁/b²=1 |
Universal Conic Shortcut: The formula SP = ePM covers ALL conics in one — where S is the focus, P is any point on the conic, M is the foot of perpendicular from P to the directrix, and e is the eccentricity. For a parabola e=1, ellipse e<1, hyperbola e>1. Memorise this one formula and it applies universally.
JEE Main 2024 (April): Find the length of the tangent drawn from the point (5, 1) to the circle x² + y² + 6x − 4y − 3 = 0.
Solution:
Circle: x²+y²+2gx+2fy+c = 0 where g=3, f=−2, c=−3
Length of tangent = √(x₁²+y₁²+2gx₁+2fy₁+c) with (x₁,y₁) = (5,1)
= √(25 + 1 + 6(5) + (−4)(1) + (−3))
= √(25 + 1 + 30 − 4 − 3)
= √49 = 7
This formula type — tangent length from external point — appears in approximately 80% of JEE Main papers. It takes under 30 seconds once the formula is memorised.
| Formula | Description |
| |⃗a| = √(a₁²+a₂²+a₃²) | Magnitude of a vector |
| ⃗a·⃗b = |⃗a||⃗b|cosθ = a₁b₁+a₂b₂+a₃b₃ | Dot product (scalar product) |
| |⃗a×⃗b| = |⃗a||⃗b|sinθ | Cross product magnitude |
| ⃗a·⃗b = 0 ⇒ perpendicular | ⃗a×⃗b = ⃗0 ⇒ parallel | Perpendicular and parallel conditions |
| Projection of ⃗a on ⃗b = (⃗a·⃗b) / |⃗b| | Scalar projection |
| Area of triangle = (1/2)|⃗a×⃗b| | Area using cross product of two sides |
| Scalar triple product [⃗a ⃗b ⃗c] = ⃗a·(⃗b×⃗c) | Volume of parallelepiped |
| [⃗a ⃗b ⃗c] = 0 ⇒ ⃗a, ⃗b, ⃗c are coplanar | Coplanarity condition |
| Direction cosines: l²+m²+n² = 1 | Basic property of direction cosines |
| 3D Line: (x−x₁)/a = (y−y₁)/b = (z−z₁)/c | Symmetric form of line equation |
| Angle between lines: cosθ = |l₁l₂+m₁m₂+n₁n₂| | Using direction cosines |
| Plane: ax+by+cz+d=0; normal vector (a,b,c) | General equation of plane |
| Distance from (x₁,y₁,z₁) to plane: |ax₁+by₁+cz₁+d| / √(a²+b²+c²) | Point to plane distance |
| Distance between parallel planes: |d₁−d₂| / √(a²+b²+c²) | For planes ax+by+cz+d₁=0 and ax+by+cz+d₂=0 |
| Formula | Description |
| det(A) = ad−bc for 2×2 matrix [[a,b],[c,d]] | 2×2 Determinant |
| det(A) = a(ei−fh) − b(di−fg) + c(dh−eg) for 3×3 | 3×3 Determinant by expansion along row 1 |
| A⁻¹ = (1/det A) · adj(A) | Inverse of a matrix |
| (AB)⁻¹ = B⁻¹A⁻¹ | Inverse of a product (order reverses) |
| (AB)ᵀ = BᵀAᵀ | Transpose of a product |
| det(AB) = det(A)·det(B) | Determinant product rule |
| det(kA) = kⁿ·det(A) for n×n matrix | Scalar multiplication of determinant |
| det(Aᵀ) = det(A) | Transpose preserves determinant |
| Cramer's Rule: x = Dˣ/D, y = Dᵧ/D, z = Dᵨ/D | Solution of system of linear equations |
| AX=B has unique solution if |A|≠0 | Consistency: unique solution |
| AX=B has no solution or infinite solutions if |A|=0 | Consistency: singular matrix |
| Formula | Description |
| x = [−b ± √(b²−4ac)] / 2a | Quadratic formula (roots of ax²+bx+c=0) |
| α+β = −b/a | αβ = c/a | Vieta's formulas: sum and product of roots |
| D = b²−4ac: D>0 real distinct, D=0 equal, D<0 complex | Discriminant and nature of roots |
| α²+β² = (α+β)² − 2αβ | Sum of squares of roots |
| α³+β³ = (α+β)³ − 3αβ(α+β) | Sum of cubes of roots |
| Equation with roots α,β: x² − (α+β)x + αβ = 0 | Forming quadratic from given roots |
| For both roots positive: α+β>0 and αβ>0 and D≥0 | Sign conditions on roots |
| Formula | Description |
| i = √(−1), i² = −1, i³ = −i, i⁴ = 1 | Powers of i (cycle of 4) |
| z = a+ib; |z| = √(a²+b²); z̅ = a−ib | Modulus and conjugate |
| z·z̅ = |z|²; z+z̅ = 2Re(z) | Conjugate multiplication property |
| Polar form: z = r(cosθ + i sinθ) = re^(iθ) | Polar and Euler form (Euler's formula) |
| De Moivre's theorem: zⁿ = rⁿ(cos nθ + i sin nθ) | nth power in polar form |
| |z₁+z₂| ≤ |z₁|+|z₂| (Triangle inequality) | Fundamental inequality |
| 1 + ω + ω² = 0 | ω³ = 1 | Cube roots of unity (ω = e^(2πi/3)) |
| |z₁z₂| = |z₁||z₂| | arg(z₁z₂) = arg(z₁)+arg(z₂) | Product modulus and argument |
| Formula | Description |
| (a+b)ⁿ = ∑ C(n,r) aⁿ⁻ʳ bʳ, r=0 to n | Full binomial expansion |
| General term: Tᴿ₊₁ = C(n,r) · aⁿ⁻ʳ · bʳ | (r+1)th term from the beginning |
| Middle term: T₊(n/2+1) if n is even; two middle terms if n is odd | Middle term identification |
| C(n,r) = n! / [r!(n−r)!] | Binomial coefficient |
| Sum of all coefficients = 2ⁿ (put a=b=1) | Total coefficient sum |
| Sum of odd-position = Sum of even-position = 2ⁿ⁻¹ | Alternate coefficient sums |
| Term independent of x: set power of x = 0 in Tᴿ₊₁, solve for r | Constant term technique |
Binomial Constant Term Shortcut: Write Tᴿ₊₁ for the expansion, collect all the powers of x into a single expression in r, set that expression equal to 0, and solve for r. This method works for every "term independent of x" or "coefficient of xⁿ" question in JEE Main without exception.
JEE Main 2023 (January): Find the term independent of x in the expansion of (x + 1/x²)⁹.
Solution:
General term: Tᴿ₊₁ = C(9,r) · x⁹⁻ʳ · (1/x²)ʳ = C(9,r) · x⁹⁻ʳ · x⁻²ʳ
Power of x = (9−r) + (−2r) = 9−3r
For term independent of x: 9−3r = 0 ⇒ r = 3
T₄ = C(9,3) = 9!/(3!·6!) = 84
Answer: 84
| Formula | Description |
| P(n,r) = n! / (n−r)! | Permutation: ordered selection of r from n |
| C(n,r) = n! / [r!(n−r)!] | Combination: unordered selection of r from n |
| C(n,r) = C(n, n−r) | Symmetry property |
| C(n,r) + C(n,r−1) = C(n+1,r) | Pascal's Rule |
| Number of arrangements with repetition: nʳ | r items from n with repetition allowed |
| Circular arrangements: (n−1)! | n distinct objects in a circle |
| Arrangements with identical objects: n! / (p!q!r!...) | n objects with p alike, q alike, r alike... |
| Formula | Description |
| P(A) = Favourable outcomes / Total outcomes | Classical probability |
| 0 ≤ P(A) ≤ 1; P(Ω) = 1; P(∅) = 0 | Axioms of probability |
| P(A') = 1 − P(A) | Complement rule |
| P(A∪B) = P(A)+P(B)−P(A∩B) | Addition theorem |
| P(A∩B) = P(A)·P(B|A) = P(B)·P(A|B) | Multiplication theorem (conditional) |
| P(B|A) = P(A∩B) / P(A) | Definition of conditional probability |
| Independent events: P(A∩B) = P(A)·P(B) | Independence condition |
| Bayes' theorem: P(Aᵢ|B) = P(Aᵢ)P(B|Aᵢ) / ∑P(Aⱼ)P(B|Aⱼ) | Reverse conditional probability |
| P(X=r) = C(n,r)·pʳ·qⁿ⁻ʳ, q=1−p | Binomial distribution |
| Mean of binomial = np | Variance = npq | Binomial distribution parameters |
| Formula | Description |
| AP: aₙ = a + (n−1)d | nth term of an Arithmetic Progression |
| Sₙ = n/2 [2a + (n−1)d] = n/2 [a + l] | Sum of n terms of AP (l = last term) |
| GP: aₙ = a·rⁿ⁻¹ | nth term of a Geometric Progression |
| Sₙ = a(rⁿ−1)/(r−1), r≠1 | Sₙ = na when r=1 | Sum of n terms of GP |
| S∞ = a/(1−r), |r| < 1 | Sum of infinite GP |
| HP: nth term = 1 / [a + (n−1)d] | nth term of Harmonic Progression |
| AM ≥ GM ≥ HM (for positive numbers) | Relationship between means |
| AM = (a+b)/2; GM = √(ab); HM = 2ab/(a+b) | Formulas for two numbers a, b > 0 |
| ∑n = n(n+1)/2 | Sum of first n natural numbers |
| ∑n² = n(n+1)(2n+1)/6 | Sum of squares of first n natural numbers |
| ∑n³ = [n(n+1)/2]² | Sum of cubes of first n natural numbers |
| Mean x̅ = ∑fxᵢ / ∑f | Arithmetic mean for grouped data |
| Variance σ² = ∑f(xᵢ−x̅)² / ∑f = ∑fxᵢ²/∑f − (x̅)² | Variance formula |
| Standard Deviation σ = √(Variance) | Standard deviation |
| Coefficient of Variation = (σ/x̅) × 100% | Relative measure of dispersion |
Download the complete JEE Main 2026 Maths Important Formulas PDF below. The PDF includes all chapter-wise formula tables from this article, the top 50 most repeated formulas master list, and a compact A4 quick-revision sheet designed for last-minute exam day review.
Knowing formulas is only half the battle. The other half is knowing which formulas to prioritise, which question types repeat, and how to sequence your revision. Here is the complete strategy built from 5 years of JEE Main paper analysis.
| Priority Rank | Chapter | Target Score | Recommended Revision Days | Why This Priority |
| 1 | Calculus | 20–22 marks | 7–8 days | Highest weightage; questions are formula-direct; consistent across all sessions |
| 2 | Coordinate Geometry | 17–18 marks | 6–7 days | Predictable question types; same formula used year after year |
| 3 | Trigonometry | 12–14 marks | 4–5 days | Almost entirely formula application; very low conceptual barrier |
| 4 | Algebra | 15–17 marks | 5–6 days | High marks but slightly more concept-dependent |
| 5 | Vectors and 3D Geometry | 8–10 marks | 3–4 days | Formulaic once dot product and cross product are mastered |
| 6 | Matrices and Determinants | 6–8 marks | 2–3 days | Procedural questions; determinant expansion and Cramer's Rule |
| 7 | PnC and Probability | 6–8 marks | 2–3 days | Logic-based; fewer formulas but more application thinking |
| 8 | Sequences, Series and Statistics | 4–6 marks | 1–2 days | Straightforward; revise AP/GP/summation formulas last |
The following question types appear in virtually every JEE Main paper. If you master the formula for each, these become guaranteed marks:
| Category | Chapters | Revision Strategy |
| Easy scoring (formula plug-in, minimal thinking) | Trigonometry, Statistics, Sequences and Series | Revise formulas once, solve 5 PYQs per topic — done in 2–3 days total |
| High yield (formula plus concept, maximum marks) | Calculus, Coordinate Geometry | Spend maximum time here; practice varied question types; solve 10+ PYQs per formula type |
| Risky (more conceptual, unpredictable) | Algebra, Probability | Focus only on the most-repeated formula types; skip rare question types if time is short |
Exam-day tip: In the actual JEE Main paper, attempt formula-direct questions first — tangent to conic, integration by parts, quadratic root conditions — before attempting application-based questions. These take under 60 seconds each once the formula is memorised, and securing them first builds confidence for the rest of the paper.
| Week | Days | Chapters to Revise | Daily Formula Goal | Daily PYQ Goal | End-of-Week Milestone |
| Week 1 | Days 1–7 | Calculus + Trigonometry | 10–12 formulas/day | 5 PYQs/day | All calculus and trigonometry formulas memorised and applied |
| Week 2 | Days 8–14 | Coordinate Geometry + Algebra | 10–12 formulas/day | 5 PYQs/day | All conic, quadratic, complex numbers, binomial formulas ready |
| Week 3 | Days 15–21 | Vectors, 3D, Matrices, PnC, Probability | 8–10 formulas/day | 3 PYQs/day | All remaining chapters fully covered |
| Week 4 | Days 22–30 | Full revision + 2 complete mock tests | Full formula sheet review (all chapters) | 1 full mock test per 4 days | 2 full mock tests completed; formula gaps identified and fixed |
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The most important formulas are from Calculus (integration, differentiation, limits — 20–22% weightage), Coordinate Geometry (straight lines, circles, conics — 17–18%), and Trigonometry (identities, compound angles — 12–14%). Together these three chapters account for 50–55% of Maths marks.
Based on 5-year PYQ trend analysis: Calculus (20–22%), Coordinate Geometry (17–18%), Algebra including Quadratic, Complex Numbers and Binomial (15–17%), and Trigonometry (12–14%). These four chapters together account for 65–70% of the paper.
Memorising all formulas in this sheet and practising each on 5–10 PYQs can realistically fetch 60–70 marks out of 100, putting you in the 90+ percentile range for Maths. The key is applying formulas correctly, not just memorising them.
Yes, if you have already studied the chapters. Day 1–2: Calculus and Trigonometry. Day 3–4: Coordinate Geometry. Day 5: Algebra. Day 6: Vectors, Matrices, PnC. Day 7: Full review with the quick-revision PDF. Do not try to read entire notes in the last week — use only the formula sheet.
Use these 5 techniques:
(1) Derive formulas at least once instead of just reading them.
(2) Use mnemonics — ILATE for integration by parts, ASTC for sign rules.
(3) Group related formulas as one memory block.
(4) Use spaced repetition with Anki or flashcards on Days 1, 3, 7, 14, 30.
(5) Link each formula to a specific PYQ question type immediately after learning it.
The total formula count across all chapters is approximately 150–200. However, the top 50 most-repeated formulas covering Calculus, Coordinate Geometry, and Algebra are the absolute must-knows and can get you 36–40+ marks by themselves.