Class 8 Maths Chapter-wise Worksheets

Class 8 Maths worksheets are designed to help students strengthen their concepts through regular practice. We provide chapter-wise worksheets for Class 8 Maths with answers in PDF format. These worksheets are aligned with the latest NCERT syllabus and CBSE guidelines so that students can prepare effectively for exams.

Our collection of maths worksheets for Class 8 PDF includes practice sheets for all 16 chapters — from Rational Numbers to Introduction to Graphs. Each worksheet includes important questions, word problems, and exam-based exercises to make learning complete.

Why Use Our Class 8 Maths Worksheets?

• NCERT-Based: Worksheets follow the latest CBSE Class 8 Maths syllabus.
• Chapter-Wise PDFs: Get practice material for all 16 chapters in one place.
• Answer Keys Provided: Includes NCERT solutions for Class 8 Maths worksheets for step-by-step guidance.
• Printable PDFs: Free to download and use offline.
• Exam-Ready Practice: Questions are based on the CBSE exam pattern, including HOTS and application-based problems.

Class 8 Maths Worksheets – Chapter-wise 

NCERT Solutions for Class 8 Maths Worksheets

Along with practice material, we provide NCERT solutions for class 8 maths worksheets so that students can check step-by-step answers. This helps in quick revision, self-assessment, and error correction.

Features of Our Class 8 Maths Worksheets

• Free PDF Download: Easy to print and use for self-study.
• Topic-Wise Practice: Each worksheet targets one concept at a time.
• Exam Preparation: Includes HOTS, word problems, and application-based sums.
• Teacher-Friendly: Useful for assignments, class tests, and homework.

Download Class 8 Maths Worksheets PDF

Get chapter-wise maths worksheets for Class 8 PDF free of cost. Whether you need practice for Rational Numbers, Linear Equations, Data Handling, Mensuration, or any other topic, you’ll find well-structured worksheets with answers here.

Class 8 Maths – Important Questions with Step-by-Step Solutions

This page lists two exam-style questions for each of the 16 NCERT Class 8 Maths chapters with clear, step-by-step solutions. You can copy this HTML directly into your CMS. No CSS is used.

1) Rational Numbers

Q1. Evaluate: -5/6 + 7/9 - 1/3

1. Find LCM of denominators 6, 9, 3: LCM = 18.
2. Convert each fraction:
   • -5/6 = -15/18
   • 7/9 = 14/18
   • -1/3 = -6/18
3. Add numerators: (-15) + 14 + (-6) = -7.
4. Result = -7/18.

Answer: -7/18

Q2. Show closure under multiplication by finding (-2/5) × (15/8)

1. Multiply numerators and denominators: (-2 × 15) / (5 × 8) = -30/40.
2. Simplify: -30/40 = -3/4.
3. The product is rational, so closure holds.

Answer: -3/4

2) Linear Equations in One Variable

Q1. Solve: 3(x - 2) + 4 = 2(2x + 1)

1. Expand: 3x - 6 + 4 = 4x + 2 → 3x - 2 = 4x + 2.
2. Rearrange: -2 - 2 = x → x = -4.

Answer: x = -4

Q2. A number is 7 more than half of another. Their sum is 31. Find the numbers.

1. Let numbers be x and y with x = y/2 + 7 and x + y = 31.
2. Substitute: (y/2 + 7) + y = 31 → (3y/2) = 24 → y = 16.
3. Then x = 16/2 + 7 = 8 + 7 = 15.

Answer: 15 and 16

3) Understanding Quadrilaterals

Q1. For a 12-gon, find (i) sum of interior angles (ii) each interior angle if regular.

1. Sum = (n - 2) × 180° = (12 - 2) × 180° = 1800°.
2. Each (regular) = 1800° / 12 = 150°.

Answer: 1800° and 150°

Q2. In parallelogram ABCD, if ∠A = 70°, find ∠B, ∠C, ∠D.

1. Adjacent angles are supplementary, opposite angles are equal.
2. ∠B = 180° - 70° = 110°; ∠C = ∠A = 70°; ∠D = ∠B = 110°.

Answer: ∠B = 110°, ∠C = 70°, ∠D = 110°

4) Practical Geometry

Q1. Construct quadrilateral ABCD given AB = 5 cm, BC = 7 cm, CD = 6 cm, DA = 8 cm, AC = 9 cm. Describe steps.

1. Draw AC = 9 cm.
2. With center A radius 5 cm and center C radius 7 cm, intersect arcs at B; join AB and BC.
3. With center A radius 8 cm and center C radius 6 cm, intersect arcs at D; join AD and CD.
4. ABCD is formed; verify side lengths.

Answer: Construction completed as above.

Q2. Construct quadrilateral PQRS with PQ = 6 cm, QR = 5 cm, RS = 7 cm, ∠Q = 110°, ∠R = 90°.

1. Draw QR = 5 cm.
2. At Q, construct 110° and mark P so that PQ = 6 cm.
3. At R, construct 90° and mark S so that RS = 7 cm.
4. Join PS to obtain PQRS.

Answer: Construction completed as above.

5) Data Handling

Q1. For data 12, 15, 18, 12, 20, 18, 12 find mean, median, and mode.

1. Sum = 12 + 15 + 18 + 12 + 20 + 18 + 12 = 107; n = 7 → Mean = 107 / 7 ≈ 15.29.
2. Ordered data: 12, 12, 12, 15, 18, 18, 20 → Median = 15.
3. Mode = most frequent = 12.

Answer: Mean ≈ 15.29, Median = 15, Mode = 12

Q2. A bag has 5 red, 3 blue, 2 green balls. Find P(red) and P(not red).

1. Total = 5 + 3 + 2 = 10.
2. P(red) = 5/10 = 1/2.
3. P(not red) = 5/10 = 1/2.

Answer: P(red) = 1/2, P(not red) = 1/2

6) Squares and Square Roots

Q1. Find the least number to multiply 396 to make it a perfect square. Also find the square root of the product.

1. Prime factors: 396 = 2^2 × 3^2 × 11.
2. Unpaired factor is 11; multiply by 11: 396 × 11 = 4356.
3. 4356 = 66^2 → square root is 66.

Answer: Multiply by 11; square root = 66

Q2. Find √1296 by prime factorization.

1. 1296 = 2^4 × 3^4 = (2^2 × 3^2)^2 = 36^2.
2. Therefore √1296 = 36.

Answer: 36

7) Cubes and Cube Roots

Q1. Smallest number to multiply 392 to make a perfect cube; also find the cube root.

1. 392 = 2^3 × 7^2.
2. Make powers multiples of 3 → multiply by 7: 392 × 7 = 2744.
3. 2744 = 14^3 → cube root is 14.

Answer: Multiply by 7; cube root = 14

Q2. Smallest number to divide 686 to make a perfect cube; also find the cube root.

1. 686 = 2 × 7^3.
2. Divide by 2: 686 / 2 = 343 = 7^3.
3. Cube root is 7.

Answer: Divide by 2; cube root = 7

8) Comparing Quantities

Q1. An article with MRP Rs. 800 has successive discounts of 20% and 10%. Find the selling price and overall discount.

1. After 20%: 800 × 0.8 = Rs. 640.
2. After 10%: 640 × 0.9 = Rs. 576.
3. Overall discount = 800 - 576 = Rs. 224 = 28%.

Answer: SP = Rs. 576; overall discount = 28%

Q2. Compare SI and CI on Rs. 5000 at 10% p.a. for 2 years.

1. Simple Interest = PRT/100 = 5000 × 10 × 2 / 100 = Rs. 1000.
2. Compound Interest = 5000[(1.10)^2 - 1] = 5000(1.21 - 1) = Rs. 1050.
3. Difference = Rs. 50.

Answer: SI = Rs. 1000; CI = Rs. 1050

9) Algebraic Expressions and Identities

Q1. Find 999^2 using (a - b)^2 identity.

1. 999 = 1000 - 1.
2. (1000 - 1)^2 = 1000^2 - 2(1000)(1) + 1 = 1,000,000 - 2,000 + 1.
3. Result = 998,001.

Answer: 998001

Q2. Factorise: 25x^2 - 30xy + 9y^2

1. Recognize as a perfect square: (5x - 3y)^2.

Answer: (5x - 3y)^2

10) Visualising Solid Shapes

Q1. Verify Euler’s formula V - E + F = 2 for a triangular prism.

1. Vertices V = 6, Edges E = 9, Faces F = 5.
2. Compute: 6 - 9 + 5 = 2.

Answer: Verified (2)

Q2. For a square pyramid, list V, E, F and verify Euler’s relation.

1. V = 5, E = 8, F = 5.
2. Compute: 5 - 8 + 5 = 2.

Answer: Verified (2)

11) Mensuration

Q1. Find the curved surface area of a cylinder with radius 7 cm and height 10 cm. Use pi = 22/7.

1. CSA = 2πrh = 2 × (22/7) × 7 × 10 = 440 cm^2.

Answer: 440 cm^2

Q2. A square garden of side 20 m has a surrounding path of width 1 m. Find the area of the path.

1. Outer side = 20 + 1 + 1 = 22 m.
2. Area of path = 22^2 - 20^2 = 484 - 400 = 84 m^2.

Answer: 84 m^2

12) Exponents and Powers

Q1. Simplify: ((2^-3 × 5^2)^2) / 10^-1

1. (2^-3 × 5^2)^2 = 2^-6 × 5^4.
2. Divide by 10^-1 is multiply by 10^1 = 2^1 × 5^1.
3. Overall = 2^-6 × 5^4 × 2^1 × 5^1 = 2^-5 × 5^5 = (5/2)^5 = 3125/32.

Answer: 3125/32

Q2. Write 0.00056 in standard (scientific) form.

1. 0.00056 = 5.6 × 10^-4.

Answer: 5.6 × 10^-4

13) Direct and Inverse Proportions

Q1. 8 workers finish a job in 15 days. How many workers are needed to finish it in 12 days?

1. Workers × Days = Constant → 8 × 15 = x × 12.
2. x = (8 × 15) / 12 = 10.

Answer: 10 workers

Q2. A car covers 150 km in 3 hours at uniform speed. Find time to cover 220 km.

1. Speed = 150 / 3 = 50 km/h.
2. Time = 220 / 50 = 4.4 h = 4 hours 24 minutes.

Answer: 4 hours 24 minutes

14) Factorisation

Q1. Factorise: 6x^2 - x - 15

1. Product = 6 × (-15) = -90. Split -x as +9x - 10x.
2. 6x^2 + 9x - 10x - 15 = 3x(2x + 3) - 5(2x + 3).
3. Factor by grouping: (2x + 3)(3x - 5).

Answer: (2x + 3)(3x - 5)

Q2. Factorise: x^3 - 8

1. Difference of cubes: x^3 - 2^3 = (x - 2)(x^2 + 2x + 4).

Answer: (x - 2)(x^2 + 2x + 4)

15) Introduction to Graphs

Q1. For y = 2x + 1, make a table for x = -1, 0, 1, 2 and find intercepts.

1. Points:
   • x = -1 → y = -1 → (-1, -1)
   • x = 0 → y = 1 → (0, 1)
   • x = 1 → y = 3 → (1, 3)
   • x = 2 → y = 5 → (2, 5)
2. y-intercept at (0, 1); x-intercept from 2x + 1 = 0 → x = -1/2 → (-1/2, 0).

Answer: Points as listed; intercepts: (0, 1) and (-1/2, 0)

Q2. A distance–time graph passes through (1, 60) and (3, 180). Find the speed.

1. Slope = (180 - 60) / (3 - 1) = 120 / 2 = 60 km/h.

Answer: 60 km/h

16) Playing with Numbers

Q1. For a 3-digit number 3ab (hundreds digit 3), give the condition for divisibility by 9.

1. A number is divisible by 9 if sum of digits is a multiple of 9.
2. Sum = 3 + a + b must be a multiple of 9.

Answer: 3 + a + b is a multiple of 9

Q2. A two-digit number has digit sum 11. The difference between the number and the reversed-number is 27. Find the number.

1. Let tens = x, ones = y. Then x + y = 11.
2. (10x + y) − (10y + x) = 27 → 9(x − y) = 27 → x − y = 3.
3. Solve: add equations → 2x = 14 → x = 7; then y = 4.

Answer: 74