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Updated on 29 Sep 2025, 16:22 IST
Factorisation Class 8 Worksheets: Explore and download the free PDF version of CBSE Factorisation worksheet for Class 8 Maths. Our CBSE Class 8 Maths Factorisation Worksheets are carefully designed to match the latest syllabus and exam format set by CBSE. These worksheets aim to assist students in understanding the concept of factorisation more easily. You can access Class 8 Maths worksheets for each chapter along with detailed answers to improve your Maths skills and proficiency.
Factorisation is a important mathematical concept, especially in algebra, essential for simplifying expressions and solving equations. In CBSE Class 8 Maths Syllabus, the Factorisation chapter teaches students to express algebraic expressions as products of their factors. By breaking down complex expressions into simpler factors, students can solve problems efficiently and understand algebraic manipulation better. This chapter covers several techniques for factorising algebraic expressions. These techniques include common factorisation, factorisation by grouping, and special factorisation formulas such as perfect squares and cubes. Mastery of factorisation not only aids in solving mathematical problems but also forms the basis for advanced topics in algebra and calculus.
Q1. Factorise the following expressions.
(a) 54m3n + 81m4n2
(b) 15x2y3z + 25x3y2z + 35x2y2z2
Solution:
(a) 54m3n + 81m4n2
= 2 × 3 × 3 × 3 × m × m × m × n + 3 × 3 × 3 × 3 × m × m × m × m × n × n
= 3 × 3 × 3 × m × m × m × n × (2 + 3 mn)
= 27m3n (2 + 3mn)
(b) 15x2y3z + 25 x3y2z + 35x2y2z2 = 5x2y2z ( 3y + 5x + 7)
Q2. Factorise the following polynomials.
(a) 6p(p – 3) + 1 (p – 3)
(b) 14(3y – 5z)3 + 7(3y – 5z)2
Solution:
(a) 6p(p – 3) + 1 (p – 3) = (p – 3) (6p + 1)
(b) 14(3y – 5z)3 + 7(3y – 5z)2
= 7(3y – 5z)2 [2(3y – 5z) +1]
= 7(3y – 5z)2 (6y – 10z + 1)
Q3. Factorise the following:
(a) p2q – pr2 – pq + r2
(b) x2 + yz + xy + xz
Solution:
(a) p2q – pr2 – pq + r2
= (p2q – pq) + (-pr2 + r2)
= pq(p – 1) – r2(p – 1)
= (p – 1) (pq – r2)
(b) x2 + yz + xy + xz
= x2 + xy +xz + yz
= x(x + y) + z(x + y)
= (x + y) (x + z)
Q4. Factorise the following polynomials.
(a) xy(z2 + 1) + z(x2 + y2)
(b) 2axy2 + 10x + 3ay2 + 15
Solution:
(a) xy(z2 + 1) + z(x2 + y2)
= xyz2 + xy + 2x2 + zy2
= (xyz2 + zx2) + (xy + zy2)
= zx(yz + x) + y(x + yz)
= zx(x + yz) + y(x + yz)
= (x + yz) (zx + y)
(b) 2axy2 + 10x + 3ay2 + 15
= (2axy2 + 3ay2) + (10x + 15)
= ay2(2x + 3) +5(2x + 3)
= (2x + 3) (ay2 + 5)
Q5. Factorise the following expressions.
(а) x2 + 4x + 8y + 4xy + 4y2
(b) 4p2 + 2q2 + p2q2 + 8
Solution:
(a) x2 + 4x + 8y + 4xy + 4y2
= (x2 + 4xy + 4y2) + (4x + 8y)
= (x + 2y)2 + 4(x + 2y)
= (x + 2y)(x + 2y + 4)
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(b) 4p2 + 2q2 + p2q2 + 8
= (4p2 + 8) + (p2q2 + 2q2)
= 4(p2 + 2) + q2(p2 + 2)
= (p2 + 2)(4 + q2)
Q6. Factorise:
(a) a2 + 14a + 48
(b) m2 – 10m – 56
Solution:
(a) a2 + 14a + 48
= a2 + 6a + 8a + 48
[6 + 8 = 14 ; 6 × 8 = 48]
= a(a + 6) + 8(a + 6)
= (a + 6) (a + 8)
(b) m2 – 10m – 56
= m2 – 14m + 4m – 56
[14 – 4 = 10; 4 × 4 = 56]
= m(m – 14) + 6(m – 14)
= (m – 14) (m + 6)
Q7. Factorise the following polynomials.
(a) 16x4 – 81
(b) (a – b)2 + 4ab
Solution:
(a) 16x4 – 81
= (4x2)2 – (9)2
= (4x2 + 9)(4x2 – 9)
= (4x2 + 9)[(2x)2 – (3)2]
= (4x2 + 9)(2x + 3) (2x – 3)
(b) (a – b)2 + 4ab
= a2 – 2ab + b2 + 4ab
= a2 + 2ab + b2
= (a + b)2
(Simple common factor questions, 5 × 1 = 5 marks)
Q1. Factorise: 12x + 20
Answer: 4(3x + 5)
Q2. Factorise: 15a²b + 25ab²
Answer: 5ab(3a + 5b)
Q3. Factorise: 7p² – 14p
Answer: 7p(p – 2)
Q4. Factorise: 9x³ – 3x²
Answer: 3x²(3x – 1)
Q5. Factorise: 16y² – 4y
Answer: 4y(4y – 1)
(Simple regrouping and identity-based, 5 × 2 = 10 marks)
Q6. Factorise: 15pq + 15 + 9q + 25p
Answer:
= (15pq + 15) + (9q + 25p)
= 15(qp + 1) + (9q + 25p)
= (qp + 1)(15 + 9) [after regrouping appropriately]
Q7. Factorise using identity: 49p² – 36
Answer: = (7p)² – (6)² = (7p + 6)(7p – 6)
Q8. Factorise: x² + 10x + 25
Answer: = (x + 5)²
Q9. Factorise: a² – 121
Answer: = (a + 11)(a – 11)
Q10. Factorise: 4x² – 25y²
Answer: = (2x + 5y)(2x – 5y)
(Division of polynomials and multi-step problems, 5 × 3 = 15 marks)
Q11. Divide: (12x³ + 18x²) ÷ 6x
Answer: = (12x³ ÷ 6x) + (18x² ÷ 6x) = 2x² + 3x
Q12. Divide: (20m²n – 30mn²) ÷ 10mn
Answer: = 2m – 3n
Q13. Divide: (28x⁴ – 56x³) ÷ 14x²
Answer: = (28x⁴ ÷ 14x²) – (56x³ ÷ 14x²) = 2x² – 4x
Q14. Factorise: 25x² – 30xy + 9y²
Answer: = (5x – 3y)²
Q15. Factorise: p³ + q³
Answer: = (p + q)(p² – pq + q²)
(Hard questions and word problems, 5 × 4 = 20 marks)
Q16. The area of a rectangle is given as (x² + 7x + 12). If its width is (x + 3), find its length.
Answer:
Length = (x² + 7x + 12) ÷ (x + 3)
= (x + 3)(x + 4) ÷ (x + 3)
= (x + 4)
Q17. Factorise: ab + bc + ca + a² + b² + c²
Answer: = (a + b + c)²
Q18. Factorise: x³ – 27
Answer: = (x – 3)(x² + 3x + 9)
Q19. If the area of a square is given by the expression (x² – 14x + 49), find the side of the square.
Answer:
Area = (x² – 14x + 49)
= (x – 7)²
∴ Side = (x – 7)
Q20. A rectangular park has an area given by (y² – 16). If its length is (y + 4), find its breadth.
Answer:
Breadth = (y² – 16) ÷ (y + 4)
= (y + 4)(y – 4) ÷ (y + 4)
= (y – 4)
Total: 20 questions = 50 marks
This makes the worksheet balanced, exam-aligned, and suitable for both practice and assessment.
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For CBSE Class 8, you need to master three main techniques:
This is a key method used for expressions like x2 + 5x + 6. You need to find two numbers that add up to the middle number (5) and multiply to give the last number (6). For this example, the numbers are 2 and 3. So, you rewrite the expression as x2 + 2x + 3x + 6 and then factorise by grouping.
You must memorize these three algebraic identities, as they are used all the time:
Yes, it is extremely important! Factorisation is the foundation for many chapters in Class 9 and Class 10, especially Polynomials and Quadratic Equations. If you master this chapter now, your future maths classes will be much easier.
The worksheet provided on this page includes a section with challenging questions to test your skills. You can also refer to RD Sharma or RS Aggarwal books, as they have a wide variety of extra questions for thorough practice.
It's simple! Just multiply the factors you have found. If your product is the same as the original algebraic expression you started with, your answer is 100% correct. This is a great way to verify your answers in an exam.