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CBSE Worksheet on Algebraic Expressions For Class 8

By rohit.pandey1

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Updated on 24 Oct 2025, 13:03 IST

CBSE Class 8 Algebraic Expressions Worksheet — exam-oriented practice for Chapter 9: Algebraic Expressions and Identities with a clean answer key. This set covers terms, coefficients, like/unlike terms, addition–subtraction of expressions, multiplication, and NCERT-based identities—followed by mixed review questions for quick revision. Each page is structured for step-wise solving, making it ideal for daily homework, class tests, and periodic assessments.

Download the algebraic expressions and identities CBSE Class 8 Maths worksheet PDF for offline study and faster checking. If you’re searching for a focused practice worksheet that mirrors school-level difficulty and improves speed + accuracy, this resource is designed to help you master every concept—concept-wise drills first, then cumulative practice, and finally a consolidated Class 8 worksheet with answers to verify learning.

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Download: Free Class 8 Maths Algebraic Expressions Worksheet with Answers PDF

This free, downloadable Class 8 Maths Algebraic Expressions Worksheet PDF serves as a comprehensive Chapter 9 test paper for revision and practice. It covers all essential topics from the CBSE syllabus and includes detailed answers for self-evaluation.

Here’s what the worksheet includes:

Unlock the full solution & master the concept
Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
  • Extra questions for Class 8 Maths Algebraic Expressions covering basic and advanced concepts.
  • MCQs (Multiple Choice Questions) for quick concept checks and exam-style revision.
  • Word problems on algebraic expressions for Class 8, such as finding the area or perimeter using algebraic sides.
  • Factoring practice problems from the factoring algebraic expressions Class 8 worksheet section using identities.
  • A complete Answer Key with step-by-step solutions for easy verification.

Download the Algebraic Expressions and Identities Class 8 Worksheet PDF with Answers to test your understanding and strengthen your preparation for school exams. Regular practice using these worksheets ensures speed, accuracy, and confidence in algebraic operations.

Key Concepts – CBSE Class 8 Algebraic Expressions and Identities

Before you start solving the CBSE Class 8 Algebraic Expressions Worksheet, revise these important definitions and rules from Chapter 9: Algebraic Expressions and Identities. These basics will help you attempt every question confidently. If you need offline practice, use the Algebraic Expressions and Identities Class 8 Worksheet PDF linked on this page.

CBSE Worksheet on Algebraic Expressions For Class 8

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What is an Algebraic Expression?

An algebraic expression is a combination of numbers, variables, and mathematical operations such as addition, subtraction, multiplication, and division.

Examples: 5x + 7, 3y2 − 2x + 1

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Each algebraic expression is made up of the following parts:

  • Variable: A symbol (like x, y, a) that represents an unknown quantity.
  • Constant: A fixed value such as 5, −10, or 1/2.
  • Term: A single part of an expression, separated by a plus or minus sign. In 3y2 − 2x + 1, the terms are 3y2, −2x, and 1.
  • Coefficient: The number multiplied by the variable. In 3y2, the coefficient is 3; in −2x, it is −2.

Understanding these parts is essential before attempting the algebraic expressions and identities Class 8 worksheet PDF.

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Like Terms and Unlike Terms – CBSE Class 8 Maths Chapter 9

Students often confuse like terms with unlike terms. Here is the difference:

  • Like Terms: Terms having the same variables raised to the same powers. 
    Examples: 7x and −2x; 4a2b and a2b
  • Unlike Terms: Terms with different variables or different powers. 
    Examples: 7x and 7y; 4a2b and 4ab2

Rule to Remember: Only like terms can be added or subtracted. For example, 7x + 2x = 9x, but 7x + 7y cannot be simplified further.

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This rule appears frequently in the Class 8 algebraic expressions worksheet with answers and in school tests.

Types of Algebraic Expressions (Monomial, Binomial, Trinomial, Polynomial)

In the CBSE Class 8 Algebraic Expressions and Identities chapter, expressions are classified by the number of terms:

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TypeDefinitionExamples

MonomialExpression with only one term15, 7x, 4y2
BinomialExpression with two unlike termsx + 5, 3a2 − 2b
TrinomialExpression with three unlike termsx2 + 5x + 6, a + b − c
PolynomialExpression with one or more terms where exponents are non-negative integers2x3 + 3x2 − 5x + 1

These classifications are important for solving the CBSE Class 8 Algebraic Expressions Worksheet and other NCERT Solution-based practice questions.

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Download the Algebraic Expressions and Identities Class 8 Worksheet PDF

After revising the concepts, practice with the Algebraic Expressions and Identities Class 8 Worksheet PDF. It includes exam-oriented questions and a complete answer key to help you check your solutions quickly.

How to Solve Operations on Algebraic Expressions (Step-by-Step)

This guide targets common “how-to” queries for Class 8 and builds confidence with fully solved examples. Use it alongside your algebraic expressions and identities Class 8 worksheet PDF for quick revision.

How to Add and Subtract Algebraic Expressions

Strategy: Arrange expressions in standard form, combine like terms (same variables with the same powers), and keep signs carefully.

Solved Example – Addition of Algebraic Expressions

Question: Add the expressions: 3x + 4y − 7 and 5x − 2y + 9.

  1. Write them together and group like terms: 
    (3x + 4y − 7) + (5x − 2y + 9) = (3x + 5x) + (4y − 2y) + (−7 + 9)
  2. Simplify each group: 
    3x + 5x = 8x; 4y − 2y = 2y; −7 + 9 = 2
  3. Answer: 8x + 2y + 2

Final: The sum is 8x + 2y + 2. Use this approach in your addition of algebraic expressions Class 8 worksheet questions.

Solved Example – Subtraction of Algebraic Expressions

Subtract (2x − 3y + 5) from(7x + y − 4).

  1. “Subtract A from B” means: B − A
    (7x + y − 4) − (2x − 3y + 5)
  2. Distribute the negative sign across the second bracket: 
    = 7x + y − 4 − 2x + 3y − 5
  3. Group like terms: 
    (7x − 2x) + (y + 3y) + (−4 − 5)
  4. Simplify: 
    5x + 4y − 9
  5. Answer: 5x + 4y − 9

Remember: The word from reverses the natural order. This is a key step in the subtraction of algebraic expressions Class 8 worksheet problems.

How to Multiply Algebraic Expressions 

Use the distributive property. Multiply coefficients, then apply exponent rules for the same base.

Solved Example – Monomial × Binomial

Question: Multiply 3x by (2x − 5).

  1. Distribute the monomial: 
    3x × (2x − 5) = (3x × 2x) + (3x × −5)
  2. Multiply and simplify: 
    3x × 2x = 6x2; 3x × (−5) = −15x
  3. Answer: 6x2 − 15x

Solved Example – Binomial × Binomial

Question: Multiply (2x + 3)(x − 5).

  1. Distribute each term in the first bracket to the second (FOIL method): 
    (2x + 3)(x − 5) = 2x·x + 2x·(−5) + 3·x + 3·(−5)
  2. Compute each product: 
    2x·x = 2x2; 2x·(−5) = −10x; 3·x = 3x; 3·(−5) = −15
  3. Combine like terms: 
    2x2 + (−10x + 3x) − 15 = 2x2 − 7x − 15
  4. Answer: 2x2 − 7x − 15

Use this pattern for any “how to multiply a binomial by a binomial Class 8” question in your multiplication of algebraic expressions Class 8 worksheet.

Division of Algebraic Expressions Class 8 Worksheet (Solved Example)

Strategy: When dividing a polynomial by a monomial, divide each term of the polynomial by the monomial.

Solved Example – Polynomial ÷ Monomial

Question: Simplify the expression: (6x2 − 9x + 12) ÷ 3x.

  1. Split the fraction term-wise: 
    (6x2 ÷ 3x) − (9x ÷ 3x) + (12 ÷ 3x)
  2. Divide each term: 
    6x2 ÷ 3x = 2x; 9x ÷ 3x = 3; 12 ÷ 3x = 4 ÷ x
  3. Write the simplified result: 
    2x − 3 + 4/x

Answer: 2x − 3 + 4/x. Always reduce coefficients and subtract exponents for like bases when possible. This format is commonly asked as “simplify the expression” in the division of algebraic expressions Class 8 worksheet.

Algebraic Identities Class 8: Master the 4 Standard Identities

Mastering the standard algebraic identities Class 8 is the most important skill in CBSE Chapter 9: Algebraic Expressions and Identities. These identities help students simplify expressions, avoid calculation errors, and solve exam-style questions faster. Schools frequently test the ability to apply formulas in both numerical and algebraic forms, which is why this topic ranks among the most searched in Class 8 Maths worksheets. Use this page as a quick-reference guide and pair it with our Algebraic Expressions and Identities Class 8 Worksheet PDF for practice.

What are the 4 Standard Identities in Class 8?

Here are the four standard algebraic identities for Class 8 students as prescribed in the CBSE Class 8 Maths syllabus. Learn and practice them well, as they form the foundation for all algebraic simplifications and factorizations in higher classes.

  1. Identity 1: (a + b)² = a² + 2ab + b² 
    This identity is used to expand the square of a sum.
  2. Identity 2: (a − b)² = a² − 2ab + b² 
    This identity helps expand the square of a difference.
  3. Identity 3: (a + b)(a − b) = a² − b² 
    This represents the difference of squares and is useful in factorization.
  4. Identity 4: (x + a)(x + b) = x² + (a + b)x + ab 
    This identity helps find the product of two binomials having the same first term.

Solved Problems: How to Use Algebraic Identities

Let’s solve a few examples step by step to understand how to apply these identities effectively in your worksheet on algebraic identities Class 8.

Example 1: Solve (102)² using an identity

Solution:

  1. We know (a + b)² = a² + 2ab + b².
  2. Here, a = 100 and b = 2.
  3. So, (102)² = (100 + 2)² = 100² + 2 × 100 × 2 + 2²
  4. = 10000 + 400 + 4 = 10404

Hence, (102)² = 10404. You can similarly find (99)² by using (a − b)² identity.

Example 2: Find the product of (103) × (104) using the (x + a)(x + b) identity

Solution:

  1. We use (x + a)(x + b) = x² + (a + b)x + ab.
  2. Here, x = 100, a = 3, and b = 4.
  3. Substitute the values: (103)(104) = 100² + (3 + 4) × 100 + (3 × 4)
  4. = 10000 + 700 + 12 = 10712

Therefore, (103)(104) = 10712. This is how to use the (x + a)(x + b) identity quickly without long multiplication.

Example 3: Simplify (3x + 4y)² using an identity

Solution:

  1. We use (a + b)² = a² + 2ab + b².
  2. Here, a = 3x and b = 4y.
  3. (3x + 4y)² = (3x)² + 2 × (3x)(4y) + (4y)²
  4. = 9x² + 24xy + 16y²

Final Answer: 9x² + 24xy + 16y²

This question is commonly asked in the Class 8 algebraic identities worksheet and helps in strengthening conceptual clarity.

Solved Example of Algebraic Expressions For Class 8 Worksheet

Q1. Simplify the following expressions:

a) 3𝑥+5𝑥
b) 7𝑦−2𝑦+4
c) 6𝑎+3𝑏−2𝑎+𝑏

Q2. Expand the following expressions: a) 2(𝑥+4)2(x+4)
b) 3(𝑎−5)3(a−5)
c) 4(2𝑦+3)4(2y+3)

Q3. Combine like terms: a) 5𝑥+3𝑥−25
b) 8𝑎−3𝑎+6
c) 10𝑏+𝑏−7

Q4. Solve for x: a) 2𝑥+3=11
b) 5𝑥−2=18
c) 3𝑥+7=2𝑥+10

Q5. Perimeter of a Rectangle

A rectangle has a length of (3x+2) units and a width of (x−1) units. Write an expression for the perimeter of the rectangle.

Solution:

The formula for the perimeter (P) is P = 2(length + width).

P = 2((3x + 2) + (x - 1))

P = 2(4x + 1)

The perimeter of the rectangle is 8x + 2 units.

Q6. Books in a Book Shop

There are 6x + 8y shelves in a book shop and on each shelf there are 8x + 6y books. How many books are there in the book shop?

Solution:

Total books = (Number of shelves) × (Books per shelf).

Total books = (6x + 8y)(8x + 6y)

= 48x2 + 36xy + 64xy + 48y2

There are 48x2 + 100xy + 48y2 books.

Q7. Polynomial Subtraction

Subtract the sum of 11x2 + 5xy + 2y2 + 6 and 3x2 − 9xy − 4y2 + 5 from 8x2 − 13xy + 14y2.

Solution:

Step 1: Find the sum of the first two expressions.

Sum = (11x2 + 5xy + 2y2 + 6) + (3x2 − 9xy − 4y2 + 5) = 14x2 − 4xy − 2y2 + 11

Step 2: Subtract this sum from the third expression.

(8x2 − 13xy + 14y2) - (14x2 − 4xy − 2y2 + 11)

= 8x2 − 13xy + 14y2 - 14x2 + 4xy + 2y2 - 11

The result is -6x2 - 9xy + 16y2 - 11.

Q8. What Must Be Added?

What must be added to p2 − 8p + 11 to get 3p2 − 2p + 6?

Solution:

Subtract the initial expression from the final expression.

(3p2 − 2p + 6) - (p2 − 8p + 11)

= 3p2 − 2p + 6 - p2 + 8p - 11

You must add 2p2 + 6p - 5.

Q9. What Must Be Subtracted?

What must be subtracted from −p2 + 2q2 + 4r2 − 4pqr to get 2p2 − q2 − 3r2 + pqr?

Solution:

Subtract the final expression from the initial expression.

(−p2 + 2q2 + 4r2 − 4pqr) - (2p2 − q2 − 3r2 + pqr)

= -p2 + 2q2 + 4r2 − 4pqr - 2p2 + q2 + 3r2 - pqr

You must subtract -3p2 + 3q2 + 7r2 - 5pqr.

Q10. Multiplication by Distributive Law

Find the multiplication of (4m3 + 36m2n) × (-mn2⁄3) by using distributive law.

Solution:

(4m3 × -mn2/3) + (36m2n × -mn2/3)

= -4/3 m4n2 - 36/3 m3n3

The product is -4/3 m4n2 - 12m3n3.

Q11. Polynomial Division

Divide (p4 − 256) by (p + 4).

Solution:

Using polynomial long division, the quotient is p3 - 4p2 + 16p - 64 and the remainder is 0.

Q12. Quotient and Remainder

Find the quotient and remainder when (4r5 + 5r4 − 13r3 + 6r2 − 34r + 7) is divided by (r2 + 2r + 3).

Solution:

Using polynomial long division:

Quotient: 4r3 - 3r2 - 19r + 53

Remainder: -181r - 152

Q13. Amount Received by Each Person

If a sum of rupees (32a3 − 76a2 + 72a − 18) is divided equally among (8a − 3) persons. Find the amount received by each person.

Solution:

Divide the total sum by the number of persons using polynomial long division.

The amount received by each person is 4a2 - 8a + 6 rupees.

Q14. Perimeter of a Quadrilateral Field

If (3p + 5q), (9p + q), (p + 14q), and (5p − 6q) units are the lengths of the sides of a quadrilateral field, find the perimeter.

Solution:

The perimeter is the sum of the lengths of all sides.

(3p + 5q) + (9p + q) + (p + 14q) + (5p - 6q)

= (3+9+1+5)p + (5+1+14-6)q

The perimeter is 18p + 14q units.

Q15. Product of Two Numbers

The product of two numbers is (m6 − n6). If one of the numbers is (m − n), then find the other.

Solution:

Divide the product by the known number. You can use polynomial long division or factoring.

Factoring m6 - n6 gives (m-n)(m5 + m4n + m3n2 + m2n3 + mn4 + n5).

The other number is m5 + m4n + m3n2 + m2n3 + mn4 + n5.

Q16. Area Comparison

The length and breadth of a rectangular box are (x + 3y) and (5x − y) units respectively. Its perimeter is equal to the perimeter of a square box. Find how much the area of the rectangular box is less than that of the square.

Solution:

1. Perimeter of rectangle:2((x+3y)+(5x-y)) = 2(6x+2y) = 12x+4y

2. Side of square: The square's perimeter is also 12x+4y. So, its side is (12x+4y)/4 = 3x+y

3. Area of square:(3x+y)2 = 9x2+6xy+y2

4. Area of rectangle:(x+3y)(5x-y) = 5x2+14xy-3y2

5. Difference in area:(9x2+6xy+y2) - (5x2+14xy-3y2)

The rectangular box's area is 4x2 - 8xy + 4y2 units less than the square's.

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FAQs for a Worksheet on Algebraic Expressions

What is the difference between an 'expression' and an 'equation'?

An algebraic expression is a combination of variables, constants, and arithmetic operations (like addition, subtraction, multiplication). It does not have an equals sign (=). For example, 5x + 3y - 7 is an expression. An equation, on the other hand, always has an equals sign and states that two expressions are equal to each other. For example, 5x + 3y - 7 = 12 is an equation. Think of an expression as a phrase and an equation as a complete sentence.

 

What are 'like terms' and why can I only add or subtract them?

'Like terms' are terms that have the exact same variables raised to the exact same powers. The coefficients (the numbers in front) can be different.

  • Examples:7x²y and -3x²y are like terms.
  • Non-Examples:7xy² and -3x²y are not like terms because the powers on x and y are different.

You can only add or subtract like terms because you are combining quantities of the same thing. Think of it like fruit: you can add 3 apples and 4 apples to get 7 apples, but you cannot add 3 apples and 4 oranges to get "7 apple-oranges." Similarly, 3x² + 4x² becomes 7x², but 3x² + 4x cannot be simplified further.

 

What is the most common mistake when subtracting algebraic expressions?

The most common mistake is forgetting to change the sign of every term in the expression being subtracted. When you see a problem like Subtract (2a - 3b) from (5a + 4b), it means you are doing (5a + 4b) - (2a - 3b). The minus sign outside the bracket applies to both 2a and -3b.

  • Incorrect:5a + 4b - 2a - 3b
  • Correct: 5a + 4b - 2a + 3b = 3a + 7b

Always remember to distribute the negative sign to all the terms inside the parenthesis.

What is the difference between (a+b)2 and a2+b2?

This is a crucial concept. The identity for (a+b)2 is a2+2ab+b2. It means you are multiplying the entire term (a+b) by itself. The term a2+b2 is missing the middle term, 2ab.

  • Example: Let a=3 and b=4.
    • (3+4)2=7^2=49.
    • 3^2+4^2=9+16=25.

As you can see, the results are different. Never forget the middle 2ab term when squaring a binomial.