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By Ankit Gupta
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Updated on 16 Jul 2026, 12:56 IST
If you have ever stared at the CBSE Class 12 Physics syllabus a week before the board exam, you already know the feeling. There are dozens of derivations spread across multiple chapters, and remembering which ones matter most can quickly become overwhelming.
The good news? Not every derivation carries the same weight. Derivation-based questions regularly feature in the CBSE Class 12 Physics paper and contribute a significant share of the theory marks, but the board tends to rotate through a very predictable set of core derivations. This guide organizes your mandatory NCERT derivations chapter by chapter so you know exactly what to revise before stepping into the exam hall.
Electrostatics derivations are high-yield options for the 5-mark long-answer questions. The board expects clean geometric setups and explicit statements about your assumptions.
Fig 1: Axial fields subtract (opposite directions); equatorial components cancel vertically and add horizontally
Why It Matters: This is one of the easiest scoring derivations in the syllabus because the mathematical flow is completely linear.
The Steps: Start with the uniform electric field between two plates, which is E = σ/ε0. Link this to the potential difference using V = Ed. Finally, substitute this potential into the definition of capacitance (C = Q/V) to get C = ε0A/d.
Common Board Mistake: Students often forget to specify whether the battery remains connected or disconnected during the derivation. Always read the problem statement carefully.
The Steps: Introducing a dielectric slab reduces the internal electric field by a factor of K due to polarization (E = E0/K). Because the field drops, the potential difference decreases to V = V0/K. When you plug this back into the capacitance formula, the final value increases by a factor of K, giving C = KC0.

Fig 2: Inserting a dielectric slab drops E and V by a factor of K, so capacitance rises to C = KC0
Derivations here move away from complex geometry and focus squarely on circuit laws.

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Exam Tip: Do not just jump into the equations. State clearly that the bridge is balanced only when the current through the galvanometer drops to zero (Ig = 0).
The Steps: Apply Kirchhoff's Voltage Law (KVL) around both closed loops of the network. By matching the potential drops across adjacent resistors under zero-galvanometer current, you show that the ratio of the resistances matches: P/Q = R/S.
Fig 3: The Wheatstone bridge network, balanced when the galvanometer reads zero current
Revision Priority: This derivation is a practical application of the Wheatstone bridge.

The Steps: Because the resistance of a uniform wire is directly proportional to its length (R ∝ l), the balancing condition at a null point l allows you to find the unknown resistance X using the remaining wire length (100 − l): X = R(100 − l)/l.
This chapter tests your ability to handle three-dimensional vector orientations. Your diagrams must match your mathematical signs perfectly.
Why It Matters: This is a favorite 5-mark question for board paper setters.
The Steps: Select a tiny current element dl on the loop. Use the Biot-Savart equation to project its small magnetic field dB. Notice that the components perpendicular to the central axis cancel out completely as you move around the ring. To find the net field, integrate only the axial components (dB cosθ) around the full circle.
Fig 4: Only the axial components of dB survive after integrating around the full loop
Exam Tip: Always sketch your imaginary Amperian loop clearly. For a solenoid, use a rectangular loop that goes inside and outside the coil structure.
The Steps: Apply the integral formula ∮B·dl = μ0 I_enclosed. Show that the magnetic field outside an ideal solenoid is zero. This means the only segment contributing to the integration is the one running parallel to the field inside, which gives B = μ0 n I.
Fig 5: The rectangular Amperian loop used to derive the solenoid's interior field
These chapters rely heavily on rates of change and time-dependent calculus.
The Steps: Start by writing down the interior magnetic field of a solenoid, B = μ0 n I. Use this to find the total magnetic flux linking all turns of the wire (Φ = Nφ_B). Since flux is also directly related to inductance by Φ = LI, equate the expressions to get your final formula: L = μ0 n² A l.
The Steps: Imagine a coil of area A spinning with a constant angular velocity ω inside a uniform magnetic field B. The changing flux through the turning loop is written as Φ = BA cos(ωt). Differentiate this expression with respect to time using Faraday's Law (e = −dΦ/dt) to reveal the classic sinusoidal induced EMF: e = BAω sin(ωt).
Optics contains the most visually demanding derivations in your Class 12 preparation. One missing arrow on a light ray or a flipped sign convention can break the entire mathematical sequence.
Common Board Mistake: Skipping the intermediate step where you treat the image from the first refracting surface as a virtual object for the second surface. Evaluators look specifically for this statement.
The Steps: Start by applying the single spherical refraction formula to the first surface of a thick lens. Then, write the refraction equation for the second surface. Adding these two geometric equations together cancels out the intermediate image distance, which gives the final Lens Maker's relation: 1/f = (n−1)(1/R1 − 1/R2).
Revision Priority: This derivation shows up regularly in both theory papers and practical viva questions.
The Steps: Track a light ray passing through a triangular prism and use geometry to relate the angle of deviation to the interior angles (i + e = A + D). Next, apply the condition for minimum deviation (D = Dm), where the light path becomes perfectly symmetric (i = e and r1 = r2 = A/2). Substitute these values into Snell's Law to find the refractive index.
Fig 6: Tracking the ray through a prism from incidence to emergence, the geometry behind the deviation formula
The Steps: Calculate the path difference (Δx = xd/D) between two overlapping light waves traveling from coherent slits to a screen. Set this path difference equal to whole numbers of the wavelength (nλ) to find the locations of bright fringes. Subtracting adjacent positions shows that the fringe width (β) remains uniform across the screen.
Fig 7: YDSE geometry, the path difference xd/D determines where bright and dark fringes fall on the screen
Modern physics derivations are purely algebraic. They do not require complex geometric diagrams, but you must define your quantum variables clearly.
The Steps: Start by balancing the inward electrostatic Coulomb force with the outward centripetal force for a revolving electron. Combine this with Bohr's quantization condition for angular momentum (mvr = nh/2π) to solve for the radius of the orbit. Finally, substitute this radius into the total mechanical energy equation (E = K + U) to find the quantized energy states.
The Steps: Start with the foundational core principle: the rate at which a radioactive sample disintegrates is directly proportional to the total number of active nuclei present at that exact moment (−dN/dt = λN). Separate your variables (dN/N = −λdt) and integrate both sides from your initial state t = 0 (N = N0) to time t to find the exponential decay curve: N = N0e^(−λt).
Use this breakdown to prioritize your revision sessions. Focus heavily on the three-star derivations before moving down the list.
| ⭐⭐⭐ Must Revise | ⭐⭐ Good to Revise | ⭐ Optional Revision |
| Lens Maker's Formula | Axial Line Electric Field | Toroid Magnetic Field |
| Equatorial Line Electric Field | Self-Inductance of a Solenoid | Transformer Turn Ratio |
| Prism Refractive Index Formula | Wheatstone Bridge Balance | de Broglie Wavelength Relation |
| Fringe Width in YDSE | Bohr Orbit Energy Expression | Magnetic Force on a Wire |
| Parallel Plate Capacitor (with Dielectric) | Potentiometer Applications | Metre Bridge Verification |
Successfully reproducing these derivations under exam conditions requires moving past temporary memorization to understanding the structural logic behind each step. Infinity Learn supports your board prep through targeted academic resources:
Even if derivations seem difficult, remember that they are among the most predictable questions in the CBSE Physics paper. Once you understand the sequence of steps, reproducing them becomes straightforward. Use these presentation strategies to ensure the evaluator gives you full marks:
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The highest-yield derivations include the Lens Maker's Formula, Refraction through a Prism, the Fringe Width expression in YDSE, the Electric Field on the Equatorial Line of a Dipole, and the Capacitance of a Parallel Plate Capacitor containing a dielectric slab.
To get full marks, your answer must include a brief initial statement defining your variables, a neat and fully labelled pencil diagram, logical step-by-step algebraic transitions, and the final formula clearly highlighted inside a box with its proper SI units.
Are derivations from all chapters asked in CBSE boards?