BlogGeneralTricks to Solve Math Problems of Various Classes

Tricks to Solve Math Problems of Various Classes

A Math problem can be solved in a variety of ways. Knowing how to get somewhere isn’t always enough. There are occasions when pupils must quickly solve Math problems. Let’s say they have five minutes until the exam bell rings. All of the complex questions must be completed within a certain amount of time, especially when a student is taking competitive exams. Fast computation tricks come in handy at times like these.

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    Developing a quick and precise mental math skill is not difficult, and it does not require years, contrary to popular opinion. By learning a few basic Arithmetic methods, you can enhance your mathematical thinking speed by over 100%. These fundamental techniques focus on mathematical properties that may be tested in specific situations. The length of a mathematics trick varies based on the mathematical operation and the actual figures, but it takes no more than 10 minutes to master one.

    A basic math method, according to the study, can answer difficult problems in record time. Knowing how to answer a mathematical problem can make a significant difference in an exam’s outcome. Addition, subtraction, multiplication, squares, powers, logarithms, and other mathematical tricks are all available. Let’s start with multiplication by 11 on the list of finest Math techniques.

    Trick 1: Multiplication by 11

    Assume you wish to solve the problem 58 x 11. Is it possible for you to solve it in less than 5 seconds? Most likely, you won’t be able to. It’s because you’re missing out on a simple multiplication by 11 tricks. The following is a math trick for multiplying by 11:

    Consider the problem N x 11. Now go through the following steps:

    · The second digit of N is the last digit of the solution.

    · The last digit of the sum of both digits of N is the middle digit of the solution.

    · If there is a carry, the first digit of the answer is the first digit of N plus the carry.

    Now let’s apply the steps to our prior 58 x 11 example:

    · 8 is the last digit.

    · 3 is the middle digit. 5 + 8 = 13 is the sum of the digits in the number 58.

    · 5 + 1 = 6 is the first digit. We have a carry since the sum of N’s digits is greater than 10, as we discovered in the previous step.

    As a result, we can deduce that 58 x 11 Equals 638.

    Trick 2: Finding a Square of 2 digit numbers

    Consider the case when you want to square 56. To fix it in seconds, follow the instructions below:

    · Create your total by adding the last digit of the number you’re trying to square to the full integer. As a result, we obtain 56 + 6 = 62.

    · Multiply the sum (Step 1) by the base number’s first digit. As a result, 62 multiplied by 5 equals 310.

    · Square the base number’s last digit. As a result, we obtain 62 = 36.

    · Add the square number to the above-mentioned product.

    As a result, 3136 will be our answer.

    Trick 3: Value of Pi

    If you’re always having trouble remembering the value of pi (who wouldn’t, because pi is an infinite number!), there’s a simple strategy to remember the first seven digits. The trick is as follows:

    Count the number of letters in each word in the statement to remember the first seven digits of pi:

    “How I wish I could calculate pi.”

    3.141592 is the result.

    Trick 4: Calculating Percentage

    Let’s say we need to locate 5% of 475. You can compute it using the long technique by writing 5/100, multiplying it by 475, and then calculating it. However, this is a time-consuming process, and in a competitive exam, every second counts. So, if you’re in a hurry, just follow the instructions below to determine this %. Move the decimal point one position to the right for the specified number. 475 is now 47.5. Then we divide 47.5 by two to get 23.75.

    The answer to the given problem is 23.75.

    Trick 5: Multiplication by 9, 99 and 999

    To multiply any integer by 9, 99, or 999, there is a simple yet effective trick. The trick is as follows: Multiplying a number by 9 is the same as multiplying a number by ten (10-1).

    Multiplying 9 by 9 produces 9(10-1), which equals 90-9 = 81.

    Another illustration:

    9 × 68 = 68 (10-1)

    = 680 – 68

    = 612

    Trick 6: Multiplying numbers when one of them is even

    If one of the numbers is even while multiplying large numbers, divide the very first number in half and then double the subsequent number. This strategy will immediately solve the problem. Consider the following scenario: 150 x 30

    Take 30 and divide it by 2, which is 15

    300 is the result of multiplying 150 by two.

    Add your two answers together in a multiplication table.

    As a result, 15 x 300 = 4500

    Importance of Math tricks

    Whether it’s for professional employment or to prepare for competitive exams, simple math short hacks will help you improve your ability to handle complicated arithmetic problems quickly and easily.

    The strategies break down enormous issues into smaller ones so that they can be solved in a short amount of time. Here are some of the most important characteristics of using short mathematical tricks:

    · Learning math tricks improve your critical thinking and problem-solving ability.

    · In practice, arithmetic is used in some form or another in practically every career path. As a result, it’s a complete win-win situation!

    · These modest tips will be quite beneficial in establishing a successful career in mathematics.

    Also read: Time Management In Exam

    Frequently Asked Questions

    How can I improve my math skills?

    You can use the Mathematics strategies on this website to answer mathematical problems more quickly and easily.

    What are the advantages of mastering these techniques?

    Using strategies to solve math issues allows us to complete calculations more quickly. It saves time and enhances the likelihood of getting higher grades on exams.

    Q. How do you determine whether a number is divisible by 13?

    Ans: If you’re given a number N, multiply the very last digit by 4 and add it to the remainder of the number. If the result is divisible by 13, the number N must be divisible by 13 as well.

    650, for instance, is divisible by 13 because 65+0*4=65.

    As a result, 65 can be divided by 13.

     

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