In the figure, an air lens of radii of curvature 10 cm R1=R2=10 cm is cut in a cylinder of glass μ=1.5.The focal length and the nature of the lens is

A
15 cm, concave
B
15 cm, convex
C
∞, neither concave nor convex
D
0, concave

Solution:

$\begin{array}{l} \frac{1}{f} = (_{g} μ_{a} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) = (\frac{2}{3} - 1) (\frac{2}{10}) \\ \Rightarrow f = - 15 cm, so behaves as concave lens . \end{array}$

In the figure, an air lens of radii of curvature 10 cm $(R_{1} = R_{2} = 10 cm)$ is cut in a cylinder of glass $(μ = 1.5)$ .The focal length and the nature of the lens is

Solution:

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