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NCERT Solutions – Class 7 Maths Practical Geometry Ex 10.3

Chapter 10 Practical Geometry

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    Exercise 10.3

    Ex 10.3 Class 7 Maths Question 1.
    Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m ∠DEF = 90°.
    NCERT Solutions for Class 7 Maths Practical Geometry Ex 10.3 1
    Solution:
    Steps of construction:
    (i) Draw DF = 3 cm.
    (ii) Draw an angle of 90° at D and cut DE = 5 cm.
    (iii) Join EF.
    (iv) EPF is the required triangle.
    Using SAS property

     

    Ex 10.3 Class 7 Maths Question 2.
    Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.
    NCERT Solutions for Class 7 Maths Practical Geometry Ex 10.3 2
    Solution:
    Steps of construction:
    (i) Draw AB = 6.5 cm.
    (ii) Draw angle of 110° at A and cut AC = 6.5 cm.
    (iii) Join C to B.
    (iv) CAB is the required triangle.
    [Using SAS criterion]

     

    Ex 10.3 Class 7 Maths Question 3.
    Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.
    NCERT Solutions for Class 7 Maths Practical Geometry Ex 10.3 3
    Solution:
    Steps of construction:
    (i) Draw BC = 7.5 cm.
    (ii) Draw ∠C = 60° such that AC = 5 cm.
    (iii) Join A to B.
    (iv) ABC is the required triangle.
    [Using SAS Criterion]

     

    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q1
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2.1
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2.2
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q3
    NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q3.1

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