NCERT Solutions for Class 7 Maths Exercise 10.3 Chapter 10 Practical Geometry are provided in a simple PDF format. This exercise covers constructing a triangle when the lengths of two sides and the angle between them are known (SAS Criterion). These NCERT solutions, prepared by our subject experts, aim to help students clear their doubts effectively.
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry – Exercise 10.3
Ex 10.3 Class 7 Maths
Question 1. Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m ∠DEF = 90°.
Solution:
Steps of construction:
(i) Draw DF = 3 cm.
(ii) Draw an angle of 90° at D and cut DE = 5 cm.
(iii) Join EF.
(iv) EPF is the required triangle.
Using SAS property
Question 2. Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.
Solution:
Steps of construction:
(i) Draw AB = 6.5 cm.
(ii) Draw angle of 110° at A and cut AC = 6.5 cm.
(iii) Join C to B.
(iv) CAB is the required triangle.
[Using SAS criterion]Question 3. Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.
Solution:
Steps of construction:
(i) Draw BC = 7.5 cm.
(ii) Draw ∠C = 60° such that AC = 5 cm.
(iii) Join A to B.
(iv) ABC is the required triangle.
[Using SAS Criterion]
