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Updated on 1 Jul 2026, 12:02 IST
Light Reflection and Refraction Class 10 Notes explain how light behaves when it strikes a surface or passes from one medium to another. This chapter covers reflection, refraction, spherical mirrors, lenses, ray diagrams, mirror formula, lens formula, refractive index, magnification, power of a lens, sign convention, numericals, MCQs and important questions.
This chapter is commonly searched as Class 10 Science Chapter 9 Notes, Light Class 10 Notes, and Light Reflection Refraction Class 10 Notes. Chapter numbering may vary slightly depending on textbook edition, but the core concepts remain important for CBSE Class 10 Science board exam preparation.
Light is a form of energy that helps us see objects. We see objects because light from them enters our eyes. In this chapter, students learn how light travels, how it reflects from mirrors, how it refracts through glass and water, and how spherical mirrors and lenses form images.
| Topic | What You Will Learn |
| Reflection of Light | Laws of reflection, regular and diffuse reflection, plane mirror |
| Spherical Mirrors | Concave mirror, convex mirror, focus, centre of curvature, ray diagrams |
| Mirror Formula | Relation between object distance, image distance and focal length |
| Magnification | Image size compared to object size |
| Refraction of Light | Bending of light from one medium to another |
| Snell’s Law | Mathematical relation between angle of incidence and angle of refraction |
| Refractive Index | Measure of optical density of a medium |
| Glass Slab Refraction | Lateral displacement and emergent ray |
| Spherical Lenses | Convex lens, concave lens, focus, optical centre and ray diagrams |
| Lens Formula | Relation between object distance, image distance and focal length |
| Power of Lens | Ability of a lens to converge or diverge light |
| Numericals | Mirror formula, lens formula, refractive index, magnification and power |
Students can download the Light Reflection and Refraction Class 10 Notes PDF to revise the chapter anytime, even without internet access. This PDF is designed for quick concept revision, formula practice, ray diagram preparation, and step-by-step numerical solving.
The notes cover important topics such as laws of reflection, spherical mirrors, mirror formula, refraction of light, Snell’s law, refractive index, spherical lenses, lens formula, power of lens, ray diagrams, MCQs, and important questions.
Light is a form of energy that produces the sensation of vision. It travels in a straight line in a transparent medium. This straight-line path of light is called rectilinear propagation of light.
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| Property | Meaning |
| Light travels in straight lines | In a uniform transparent medium, light follows a straight path |
| Light can be reflected | It can bounce back from a surface |
| Light can be refracted | It can bend while passing from one medium to another |
| Light forms images | Mirrors and lenses form images using reflection and refraction |
| Light travels very fast | Speed of light in vacuum is about 3 × 10⁸ m/s |
Reflection of light is the bouncing back of light into the same medium after striking a surface. For example, when light falls on a plane mirror, it returns to the same medium and forms an image. This is reflection.
Reflection of light is the phenomenon in which light rays bounce back into the same medium after striking a reflecting surface.
| Term | Meaning |
| Incident ray | Ray of light that falls on the reflecting surface |
| Reflected ray | Ray of light that returns after reflection |
| Point of incidence | Point where incident ray strikes the surface |
| Normal | Perpendicular line drawn at the point of incidence |
| Angle of incidence | Angle between incident ray and normal |
| Angle of reflection | Angle between reflected ray and normal |
The laws of reflection are used to describe how light reflects from a surface.
The incident ray, reflected ray and normal at the point of incidence all lie in the same plane.

The angle of incidence is equal to the angle of reflection.
∠i = ∠r

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If a light ray falls on a mirror at an angle of incidence of 40°, then the angle of reflection will also be 40°.
| Basis | Regular Reflection | Diffuse Reflection |
| Surface | Smooth and polished | Rough or uneven |
| Reflected rays | Parallel after reflection | Scattered in different directions |
| Image formation | Clear image is formed | Clear image is not formed |
| Example | Plane mirror | Wall, paper, wooden surface |
Diffuse reflection does not mean that the laws of reflection fail. Each ray still follows the laws of reflection, but because the surface is uneven, reflected rays scatter in different directions.
A plane mirror is a flat reflecting surface. It forms an image that appears behind the mirror.
| Property | Description |
| Nature | Virtual and erect |
| Size | Same size as object |
| Distance | Image distance = object distance |
| Laterally inverted? | Yes |
| Can be obtained on screen? | No |
Lateral inversion means the left side of the object appears as the right side in the image, and the right side appears as the left side.

Example: The word “AMBULANCE” is written in reverse on ambulances so that drivers can read it correctly in rear-view mirrors.
A spherical mirror is a mirror whose reflecting surface is part of a hollow sphere. Spherical mirrors are of two types:
A concave mirror is a spherical mirror whose reflecting surface is curved inward. It is also called a converging mirror because it converges parallel rays of light.
| Use | Reason |
| Shaving mirror | Forms enlarged image when object is close |
| Dentist mirror | Gives magnified view of teeth |
| Torch reflector | Produces parallel beam of light |
| Headlights | Produces strong parallel beam |
| Solar furnace | Converges sunlight at focus |
A convex mirror is a spherical mirror whose reflecting surface is curved outward. It is also called a diverging mirror because it diverges parallel rays of light.
| Use | Reason |
| Rear-view mirror in vehicles | Gives wider field of view |
| Security mirror in shops | Covers larger area |
| Road safety mirrors | Helps see vehicles around corners |
A convex mirror is used as a rear-view mirror because it always forms a virtual, erect and diminished image. It also provides a wider field of view, allowing the driver to see a larger area of traffic behind the vehicle.
| Basis | Concave Mirror | Convex Mirror |
| Shape | Curved inward | Curved outward |
| Also called | Converging mirror | Diverging mirror |
| Focus | Real focus | Virtual focus |
| Image formed | Can be real or virtual | Always virtual and erect |
| Field of view | Small | Large |
| Use | Shaving mirror, headlights | Rear-view mirror |
| Term | Symbol | Meaning |
| Pole | P | Centre point of reflecting surface |
| Centre of curvature | C | Centre of the sphere of which mirror is a part |
| Radius of curvature | R | Distance between pole and centre of curvature |
| Principal axis | — | Straight line passing through P and C |
| Principal focus | F | Point where rays parallel to principal axis meet or appear to meet |
| Focal length | f | Distance between pole and focus |
| Aperture | — | Effective diameter of reflecting surface |
For a spherical mirror:
R = 2f
or
f = R/2
This relation is often used in mirror formula numericals.
The New Cartesian Sign Convention is used to assign positive and negative signs to distances in mirror and lens numericals.
| Quantity | Sign |
Object distance u | Usually negative |
| Distance measured in direction of incident light | Positive |
| Distance measured opposite to incident light | Negative |
| Height above principal axis | Positive |
| Height below principal axis | Negative |
| Focal length of concave mirror | Negative |
| Focal length of convex mirror | Positive |
| Quantity | Sign |
Object distance u | Usually negative |
| Image distance for real image | Positive |
| Image distance for virtual image | Negative |
| Focal length of convex lens | Positive |
| Focal length of concave lens | Negative |
| Height above principal axis | Positive |
| Height below principal axis | Negative |
Most mistakes in Light Reflection and Refraction numericals happen because of wrong signs. Always write u, v, f and their signs before substituting values in the formula.
Ray diagrams help us find the position, size and nature of images formed by mirrors.
| Incident Ray | Reflected Ray |
| Parallel to principal axis | Passes through focus |
| Passing through focus | Becomes parallel to principal axis |
| Passing through centre of curvature | Retraces its path |
| Incident at pole | Reflects according to laws of reflection |
| Incident Ray | Reflected Ray |
| Parallel to principal axis | Appears to come from focus |
| Directed towards focus | Becomes parallel to principal axis |
| Directed towards centre of curvature | Retraces its path |
| Incident at pole | Reflects according to laws of reflection |
A concave mirror can form different types of images depending on the position of the object.
| Object Position | Image Position | Image Size | Nature of Image |
| At infinity | At focus F | Highly diminished | Real and inverted |
| Beyond C | Between F and C | Diminished | Real and inverted |
| At C | At C | Same size | Real and inverted |
| Between C and F | Beyond C | Enlarged | Real and inverted |
| At F | At infinity | Highly enlarged | Real and inverted |
| Between F and P | Behind mirror | Enlarged | Virtual and erect |
Students should practise these object positions carefully:
A convex mirror always forms a virtual, erect and diminished image.
| Object Position | Image Position | Image Size | Nature of Image |
| At infinity | At focus behind mirror | Highly diminished | Virtual and erect |
| Anywhere between infinity and pole | Between pole and focus behind mirror | Diminished | Virtual and erect |
| Basis | Real Image | Virtual Image |
| Formation | Formed by actual meeting of rays | Formed by apparent meeting of rays |
| Screen | Can be obtained on screen | Cannot be obtained on screen |
| Nature | Usually inverted | Usually erect |
| Example | Image on cinema screen | Image in plane mirror |
The mirror formula gives the relation between object distance, image distance and focal length.
1/v + 1/u = 1/f
Where:
| Symbol | Meaning |
u | Object distance |
v | Image distance |
f | Focal length |
Question: A concave mirror has focal length 20 cm. An object is placed at a distance of 30 cm in front of it. Find the image distance.
Given:
f = -20 cmu = -30 cmv = ?
Using mirror formula:
1/v + 1/u = 1/f
1/v + 1/(-30) = 1/(-20)
1/v - 1/30 = -1/20
1/v = -1/20 + 1/30
1/v = (-3 + 2)/60
1/v = -1/60
v = -60 cm
Answer: The image is formed 60 cm in front of the mirror. It is real and inverted.
Magnification tells how many times the image is enlarged or diminished compared to the object.
m = h'/h = -v/u
Where:
| Symbol | Meaning |
m | Magnification |
h' | Height of image |
h | Height of object |
v | Image distance |
u | Object distance |
| Magnification | Meaning |
m > 1 | Image is enlarged |
m < 1 | Image is diminished |
m = 1 | Image is same size |
m positive | Image is virtual and erect |
m negative | Image is real and inverted |
Refraction of light is the bending of light when it passes from one transparent medium to another.
For example, a pencil partly immersed in water appears bent because light rays bend while moving from water to air.
Refraction of light is the change in direction or bending of light when it passes obliquely from one transparent medium to another due to change in speed.
A pencil appears bent in water because light coming from the submerged part of the pencil bends when it passes from water to air. This bending of light is called refraction. Due to refraction, the underwater part appears to be at a different position.
There are two laws of refraction.
The incident ray, refracted ray and normal at the point of incidence all lie in the same plane.
The ratio of sine of angle of incidence to sine of angle of refraction is constant for a given pair of media.
sin i / sin r = constant
This constant is called the refractive index of the second medium with respect to the first medium.
Snell’s law explains the relation between angle of incidence and angle of refraction.
n₂₁ = sin i / sin r
Where:
| Symbol | Meaning |
i | Angle of incidence |
r | Angle of refraction |
n₂₁ | Refractive index of medium 2 with respect to medium 1 |
When light travels from a rarer medium to a denser medium, it bends towards the normal.
When light travels from a denser medium to a rarer medium, it bends away from the normal.
| Path of Light | Bending |
| Rarer to denser | Towards normal |
| Denser to rarer | Away from normal |
| Along normal | No bending |
When light travels from air to glass, it bends towards the normal. When it travels from glass to air, it bends away from the normal.
Refractive index tells how much a medium bends light. It also tells how much the speed of light reduces in that medium.
n = c/v
Where:
| Symbol | Meaning |
n | Absolute refractive index |
c | Speed of light in vacuum |
v | Speed of light in the medium |
Relative refractive index of medium 2 with respect to medium 1 is:
n₂₁ = v₁/v₂
Where:
v₁ = speed of light in medium 1v₂ = speed of light in medium 2| Basis | Absolute Refractive Index | Relative Refractive Index |
| Meaning | Refractive index with respect to vacuum or air | Refractive index of one medium with respect to another |
| Formula | n = c/v | n₂₁ = v₁/v₂ |
| Depends on | Speed in vacuum and medium | Speed in two different media |
| Example | Refractive index of glass | Refractive index of glass with respect to water |
Question: Speed of light in a medium is 2 × 10⁸ m/s. Find its refractive index.
Given:
c = 3 × 10⁸ m/sv = 2 × 10⁸ m/s
Using:
n = c/v
n = (3 × 10⁸) / (2 × 10⁸)
n = 1.5
Answer: Refractive index of the medium is 1.5.
When a ray of light passes through a rectangular glass slab, it bends twice:
The emergent ray is parallel to the incident ray but shifted sideways. This sideways shift is called lateral displacement.
Lateral displacement is the perpendicular distance between the incident ray’s original path and the emergent ray.
| Observation | Result |
| Incident ray and emergent ray | Parallel |
| Angle of incidence and angle of emergence | Equal |
| Ray path | Shifted sideways |
| Cause | Refraction at two parallel surfaces |
Total internal reflection is the phenomenon in which light travelling from a denser medium to a rarer medium is completely reflected back into the denser medium.
This happens only when:
| Application | Explanation |
| Optical fibre | Light undergoes repeated total internal reflection |
| Diamond sparkling | Multiple total internal reflections make diamond shine |
| Mirage | Light bends and reflects in layers of hot air |
A diamond sparkles because its high refractive index causes light to undergo multiple total internal reflections inside it. This traps and reflects light many times, making the diamond appear bright and sparkling.
Optical fibres work on the principle of total internal reflection. Light entering the fibre undergoes repeated total internal reflection and travels long distances with very little loss of intensity.
A lens is a transparent medium bounded by two surfaces, at least one of which is spherical. Spherical lenses are mainly of two types:
A convex lens is thicker at the centre and thinner at the edges. It is also called a converging lens because it converges parallel rays of light.
| Use | Reason |
| Magnifying glass | Forms enlarged image |
| Camera | Forms real image on sensor |
| Microscope | Magnifies small objects |
| Telescope | Helps view distant objects |
| Spectacles | Corrects hypermetropia |
A concave lens is thinner at the centre and thicker at the edges. It is also called a diverging lens because it diverges parallel rays of light.
| Use | Reason |
| Spectacles | Corrects myopia |
| Door peephole | Gives wider field of view |
| Optical instruments | Used in lens combinations |
| Basis | Convex Lens | Concave Lens |
| Shape | Thicker at centre, thinner at edges | Thinner at centre, thicker at edges |
| Also called | Converging lens | Diverging lens |
| Focus | Real focus | Virtual focus |
| Image formed | Real or virtual depending on object position | Always virtual, erect and diminished |
| Focal length | Positive | Negative |
| Use | Magnifying glass, camera | Spectacles for myopia |
| Term | Meaning |
| Optical centre | Centre point of lens |
| Principal axis | Line passing through optical centre and centres of curvature |
| Principal focus | Point where rays parallel to principal axis meet or appear to meet |
| Focal length | Distance between optical centre and focus |
| Aperture | Effective diameter of lens |
| Centre of curvature | Centre of sphere of which lens surface is a part |
A convex lens forms different images depending on the position of the object.
| Object Position | Image Position | Image Size | Nature of Image |
| At infinity | At F₂ | Highly diminished | Real and inverted |
| Beyond 2F₁ | Between F₂ and 2F₂ | Diminished | Real and inverted |
| At 2F₁ | At 2F₂ | Same size | Real and inverted |
| Between F₁ and 2F₁ | Beyond 2F₂ | Enlarged | Real and inverted |
| At F₁ | At infinity | Highly enlarged | Real and inverted |
| Between F₁ and optical centre | Same side as object | Enlarged | Virtual and erect |
A concave lens always forms a virtual, erect and diminished image.
| Object Position | Image Position | Image Size | Nature of Image |
| At infinity | At focus on same side | Highly diminished | Virtual and erect |
| Anywhere between infinity and optical centre | Between focus and optical centre | Diminished | Virtual and erect |
The lens formula gives the relation between object distance, image distance and focal length.
1/v - 1/u = 1/f
Where:
| Symbol | Meaning |
u | Object distance |
v | Image distance |
f | Focal length |
Question: An object is placed at a distance of 30 cm from a convex lens of focal length 20 cm. Find the image distance.
Given:
u = -30 cmf = +20 cmv = ?
Using lens formula:
1/v - 1/u = 1/f
1/v - 1/(-30) = 1/20
1/v + 1/30 = 1/20
1/v = 1/20 - 1/30
1/v = (3 - 2)/60
1/v = 1/60
v = 60 cm
Answer: The image is formed 60 cm on the other side of the lens. It is real and inverted.
For lenses:
m = h'/h = v/u
Where:
| Symbol | Meaning |
m | Magnification |
h' | Height of image |
h | Height of object |
v | Image distance |
u | Object distance |
Power of a lens is the ability of a lens to converge or diverge light rays.
P = 1/f
Here, f is measured in metres.
The SI unit of power of lens is dioptre, represented by D.
1 D = 1 m⁻¹
| Lens | Focal Length | Power |
| Convex lens | Positive | Positive |
| Concave lens | Negative | Negative |
Question: Find the power of a convex lens of focal length 50 cm.
Given:
f = 50 cm = 0.5 m
Using:
P = 1/f
P = 1/0.5
P = +2 D
Answer: Power of the lens is +2 D.
Use this formula sheet for quick revision before exams.
| Concept | Formula |
| Mirror formula | 1/v + 1/u = 1/f |
| Lens formula | 1/v - 1/u = 1/f |
| Mirror magnification | m = h'/h = -v/u |
| Lens magnification | m = h'/h = v/u |
| Radius and focal length | R = 2f |
| Refractive index | n = c/v |
| Relative refractive index | n₂₁ = v₁/v₂ |
| Snell’s law | sin i / sin r = constant |
| Power of lens | P = 1/f |
| Unit of power | 1 dioptre = 1 m⁻¹ |
Question: An object is placed 20 cm in front of a concave mirror of focal length 15 cm. Find the image distance.
Given:
u = -20 cmf = -15 cm
Using:
1/v + 1/u = 1/f
1/v + 1/(-20) = 1/(-15)
1/v - 1/20 = -1/15
1/v = -1/15 + 1/20
1/v = (-4 + 3)/60
1/v = -1/60
v = -60 cm
Answer: Image is formed 60 cm in front of the mirror.
Question: An object is placed 15 cm from a convex lens of focal length 10 cm. Find image distance.
Given:
u = -15 cmf = +10 cm
Using:
1/v - 1/u = 1/f
1/v - 1/(-15) = 1/10
1/v + 1/15 = 1/10
1/v = 1/10 - 1/15
1/v = (3 - 2)/30
1/v = 1/30
v = 30 cm
Answer: Image is formed 30 cm on the other side of the lens.
Question: An object of height 4 cm forms an image of height -8 cm. Find magnification.
Given:
h = 4 cmh' = -8 cm
Using:
m = h'/h
m = -8/4
m = -2
Answer: Magnification is -2. The image is real, inverted and enlarged.
Question: The speed of light in glass is 2 × 10⁸ m/s. Find refractive index of glass.
n = c/v
n = (3 × 10⁸)/(2 × 10⁸)
n = 1.5
Answer: Refractive index of glass is 1.5.
Question: Find the power of a concave lens of focal length -25 cm.
f = -25 cm = -0.25 m
P = 1/f
P = 1/(-0.25)
P = -4 D
Answer: Power of the lens is -4 D.
| Basis | Reflection | Refraction |
| Meaning | Bouncing back of light | Bending of light |
| Medium | Light returns to same medium | Light enters another medium |
| Cause | Striking a reflecting surface | Change in speed of light |
| Laws | Laws of reflection | Laws of refraction |
| Example | Mirror image | Pencil appearing bent in water |
| Basis | Concave Lens | Convex Lens |
| Shape | Thin at centre | Thick at centre |
| Nature | Diverging lens | Converging lens |
| Focal length | Negative | Positive |
| Image | Always virtual, erect, diminished | Real or virtual depending on object position |
| Use | Corrects myopia | Magnifying glass, camera |
| Basis | Concave Mirror | Convex Mirror |
| Surface | Reflecting surface curves inward | Reflecting surface curves outward |
| Nature | Converging mirror | Diverging mirror |
| Image | Real or virtual | Always virtual |
| Field of view | Less | More |
| Common use | Shaving mirror, headlights | Rear-view mirror |
A. Refraction
B. Reflection
C. Dispersion
D. Scattering
Answer: B. Reflection
A. Angle of refraction
B. Angle of reflection
C. Angle of deviation
D. Critical angle
Answer: B. Angle of reflection
A. Real and inverted
B. Virtual and erect
C. Real and enlarged
D. Real and same size
Answer: B. Virtual and erect
A. 1/v - 1/u = 1/f
B. 1/v + 1/u = 1/f
C. v/u = f
D. P = 1/f
Answer: B. 1/v + 1/u = 1/f
A. 1/v - 1/u = 1/f
B. 1/v + 1/u = 1/f
C. m = -v/u
D. R = 2f
Answer: A. 1/v - 1/u = 1/f
A. Diverging lens
B. Converging lens
C. Plane lens
D. Reflecting lens
Answer: B. Converging lens
A. metre
B. centimetre
C. dioptre
D. watt
Answer: C. Dioptre
A. n = v/c
B. n = c/v
C. n = u/v
D. n = f/R
Answer: B. n = c/v
A. R = f
B. R = 2f
C. f = 2R
D. R = 1/f
Answer: B. R = 2f
A. Real and inverted
B. Virtual, erect and diminished
C. Real and enlarged
D. Virtual and enlarged
Answer: B. Virtual, erect and diminished
Assertion: A convex mirror is used as a rear-view mirror.
Reason: A convex mirror provides a wider field of view and forms virtual, erect and diminished images.
Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
Assertion: A pencil appears bent when partly immersed in water.
Reason: Light bends when it passes from water to air.
Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
Assertion: A concave mirror can form both real and virtual images.
Reason: The nature of image depends on the position of the object.
Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
Assertion: Power of a concave lens is negative.
Reason: Focal length of a concave lens is negative according to sign convention.
Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
Assertion: The emergent ray from a rectangular glass slab is parallel to the incident ray.
Reason: Refraction occurs at two parallel surfaces of the glass slab.
Answer: Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
A student places an object in front of a concave mirror. When the object is placed beyond the centre of curvature, the image is formed between focus and centre of curvature. The image is real, inverted and diminished.
Questions:
Answers:
A ray of light enters a rectangular glass slab from air. It bends towards the normal while entering the slab and bends away from the normal while coming out. The emergent ray is parallel to the incident ray but shifted sideways.
Questions:
Answers:
A convex lens is used to form an image of an object. When the object is placed between F and 2F, the image is formed beyond 2F. The image is real, inverted and enlarged.
Questions:
Answers:
Students should solve NCERT Solutions for class 10 Science after revising the concepts. The most important NCERT question types include:
Students should practise these diagrams carefully:
| Diagram | Why Important |
| Laws of reflection | Basic ray diagram |
| Concave mirror image formation | Very important for board exams |
| Convex mirror image formation | Common conceptual question |
| Refraction through glass slab | Important practical-based question |
| Convex lens image formation | High diagram value |
| Concave lens image formation | Frequently asked |
| Total internal reflection | Useful for application questions |
| Mistake | Correct Concept |
| Using wrong sign for focal length | Concave mirror negative, convex mirror positive |
| Confusing mirror and lens formula | Mirror: 1/v + 1/u = 1/f; Lens: 1/v - 1/u = 1/f |
| Writing convex mirror forms real image | Convex mirror always forms virtual and erect image |
| Forgetting focal length in metres for power | Convert cm to m before using P = 1/f |
| Confusing real and virtual image | Real image can be obtained on screen |
| Confusing concave lens and convex lens | Convex converges, concave diverges |
| Ignoring signs in numericals | Always apply New Cartesian Sign Convention |
Light Reflection and Refraction is one of the most important Physics chapters in Class 10 Science Syllabus. Students should focus on laws of reflection, laws of refraction, spherical mirrors, spherical lenses, sign convention, mirror formula, lens formula, refractive index, magnification, power of lens and ray diagrams.
For scoring well, practise all formulas, draw ray diagrams neatly, revise image formation tables and solve numericals step by step using the correct sign convention. Also practise MCQs, assertion-reason questions, case-based questions and important board-style questions for complete preparation.
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Reflection of light is the bouncing back of light into the same medium after striking a reflecting surface. A plane mirror forms an image due to reflection.
The laws of reflection are: the incident ray, reflected ray and normal lie in the same plane, and the angle of incidence is equal to the angle of reflection.
Refraction of light is the bending of light when it passes from one transparent medium to another due to change in its speed.
Snell’s law states that for a given pair of media, the ratio of sine of angle of incidence to sine of angle of refraction is constant. It is written as sin i / sin r = constant.
The formula for absolute refractive index is n = c/v, where c is the speed of light in vacuum and v is the speed of light in the medium.
The mirror formula is 1/v + 1/u = 1/f, where u is object distance, v is image distance and f is focal length.
The lens formula is 1/v - 1/u = 1/f, where u is object distance, v is image distance and f is focal length.
For a spherical mirror, radius of curvature is twice the focal length. The formula is R = 2f.
A convex lens is thicker at the centre and converges light rays. A concave lens is thinner at the centre and diverges light rays.
A real image is formed by actual meeting of light rays and can be obtained on a screen. A virtual image is formed by apparent meeting of light rays and cannot be obtained on a screen.
Total internal reflection is the complete reflection of light back into the denser medium when light travels from a denser medium to a rarer medium at an angle greater than the critical angle.
Power of lens is the ability of a lens to converge or diverge light rays. It is calculated using P = 1/f, where focal length is measured in metres.
The SI unit of power of lens is dioptre, represented by D.