Search for: The integral ∫0π1+4sin2x2-4sinx2 dx equals The integral ∫0π1+4sin2x2-4sinx2 dx equals A43−4B43−4−π3Cπ−4D2π3−4−43 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Let I=∫0π 1+4sin2x2−4sinx2dx I=∫0π 1−2sinx22dx⇒ I=∫0π 1−2sinx2dx⇒ I=∫0π/3 1−2sinx2dx+∫π/3π 1−2sinx2dx⇒ I=∫0π/3 1−2sinx2dx+∫π/3π 2sinx2−1dx⇒ I=x+4cosx20π/3+−4cosx2−xπ/3π⇒ I=π3+4cosπ6−4+0−π+4cosπ6+π3⇒ I=−π3+43−4 Related content Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers KIITEE Sample Papers 2024 – Practice Paper PDF Download Linking Verbs NEET Exam Centres in Chhattisgarh 2024 Letter To Your Friend About Your Hobby