Search for: Let f(x)=∫1x 2−t2dt, Then the real roots of the equation x2−f′(x)=0 are Let f(x)=∫1x 2−t2dt, Then the real roots of the equation x2−f′(x)=0 are A±1B±12C±12D0 and 1 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, f(x)=∫1x 2−t2dt⇒f′(x)=2−x2∴x2−f′(x)=0⇒x2−2−x2=0⇒x4=2−x2⇒x4+x2−2=0⇒x2+2x2−1=0⇒x=±1 ∵x2+2≠0 Related content How to use NEET UG College Predictor 2024 to find your dream Medical College Is a Gap Certificate for NEET Repeaters Necessary? General Knowledge Questions With Answers on Islamic CBSE Class 10 Worksheets NEET Rank Predictor 2024: Calculate Your Rank by Marks Why to Choose Infinity Learn NEET Rank Predictor 2024 – The Most Accurate NEET Rank Predictor CBSE Class 10 Science MCQs CBSE Class 9 Science Structure of Atom MCQs Class 7 MCQs for All Subjects with Answers Raidas ke Pad Class 9