Search for: If y=4x−5 is a tangent to the curve y2=px3+q at (2,3) then pq= If y=4x−5 is a tangent to the curve y2=px3+q at (2,3) then pq= Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Point (2, 3) lies on y2=px3+q. . Therefore, 9=8p+qNow, y2=px3+q⇒2ydydx=3px2⇒dydx=3px22y⇒dydx(2,3)=12p6=2p.Since , y=4x−5 is y2=px3+q at (2,3) ∴ dydx(2,3)= (Slope of the line y=4x−5)⇒ 2p=4⇒p=2Putting p = 2 in (i) , we get q = -7 Hence, pq=−14 Related content Female Reproductive System Diagram Class 10 NCERT Solutions for Class 11 English Reading Skills Chapter 1 The Portrait of a Lady 50+ Simple GK Questions and Answers for Class 8 Animal Cell Diagram Class 9 Preparation Strategy for NEET Repeaters CBSE Power Sharing Class 10 MCQs Political Science Chapter 1 How to Self Study for NEET Dropper at Home? CBSE Class 9 English Wind Worksheet Viram Chinh in Hindi Worksheets Class 9 with Answers MP Board Class 8 Result 2024 – MPBSE Class 8 Result (Out)