Search for: If 2sinx−1≤0 and x∈[0,2π]. then the solution set for x, is If 2sinx−1≤0 and x∈[0,2π]. then the solution set for x, is A[π/6,5π/6]B[0,π/6]∪[5π/6,π]C[0,π/6]∪[5π/6,2π]Dnone of these. Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:It is from the graph of y=sinx that sinx≤12 for all x∈[0,π/6]∪[5π/6,2π] Related content Animal Cell Diagram Class 9 Preparation Strategy for NEET Repeaters CBSE Power Sharing Class 10 MCQs Political Science Chapter 1 How to Self Study for NEET Dropper at Home? CBSE Class 9 English Wind Worksheet Viram Chinh in Hindi Worksheets Class 9 with Answers MP Board Class 8 Result 2024 – MPBSE Class 8 Result (Out) How To Fill NEET OMR Answer Sheet 2024 VITEEE Result 2024 Announce on the official website – viteee.vit.ac.in NEET Marks vs Rank 2024 – Check NEET Rank vs Marks vs Percentile Analysis