Search for: The general value of θ satisfying the equation 2sin2θ−3sinθ−2=0, is The general value of θ satisfying the equation 2sin2θ−3sinθ−2=0, is Anπ+(−1)nπ6Bnπ+(−1)nπ2Cnπ+(−1)n5π6Dnπ+(−1)n7π6 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have,2sin2θ−3sinθ−2=0⇒(2sinθ+1)(sinθ−2)=0⇒sinθ=−12⇒sinθ=sin−π6⇒θ=nπ+(−1)n−π6,n∈Z⇒θ=nπ+(−1)n+1π6,n∈Z Related content How to use NEET UG College Predictor 2024 to find your dream Medical College Is a Gap Certificate for NEET Repeaters Necessary? General Knowledge Questions With Answers on Islamic CBSE Class 10 Worksheets NEET Rank Predictor 2024: Calculate Your Rank by Marks Why to Choose Infinity Learn NEET Rank Predictor 2024 – The Most Accurate NEET Rank Predictor CBSE Class 10 Science MCQs CBSE Class 9 Science Structure of Atom MCQs Class 7 MCQs for All Subjects with Answers Raidas ke Pad Class 9