Search for: The value of cot−11−sinx+1+sinx1−sinx−1+sinx, is 0 The value of cot−11−sinx+1+sinx1−sinx−1+sinx, is 0<x<π2 Aπ-x2B2π−xCx2D2π-x2 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, 1±sinx=cosx2±sinx22⇒ 1±sinx=cosx2±sinx22=cosx2±sinx2⇒ 1±sinx=cosx2±sinx2∴ cot−11−sinx+1+sinx1−sinx−1+sinx = cot−1cosx2−sinx2+cosx2+sinx2cosx2−sinx2−cosx2+sinx2= cot-1cotπ−x2=π−x2 Related content CBSE Class 9 English Beehive Book Poem 1 The Road Not Taken MCQ Questions with Answers MCQs Questions with Answers for Class 9 English Chapter 1 The Fun They Had CBSE Class 9 Tissue MCQs Female Reproductive System Diagram Class 10 NCERT Solutions for Class 11 English Reading Skills Chapter 1 The Portrait of a Lady 50+ Simple GK Questions and Answers for Class 8 Animal Cell Diagram Class 9 Preparation Strategy for NEET Repeaters CBSE Power Sharing Class 10 MCQs Political Science Chapter 1 How to Self Study for NEET Dropper at Home?