Search for: If ∑r=1n tr=112n(n+1)(n+2), the value ∑r=1n 1tr is If ∑r=1n tr=112n(n+1)(n+2), the value ∑r=1n 1tr is A2nn+1Bn−1(n+1)!C4nn+1D3nn+2 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have tr=∑k=1r tk−∑k=1r−1 tk=112r(r+1)(r+2)−112(r−1)(r)(r+1)=14r(r+1)Now, 1tr=4r(r+1)=41r−1r+1⇒ ∑r=1n 1tr=4∑r=1n 1r−1r+1=41−1n+1=4nn+1 Related content Class 9 Science MCQ Chapter 12 Sound CBSE Class 12 English MCQ with Answers (Flamingo & Vistas) CBSE Class 7 Science MCQ Questions with Answers CBSE Class 12 Subject Wise MCQ 2024-25 ICSE Class 10 Toppers List 2024 Available Tenses Worksheet for Class 10 CBSE Class 7 Science Chapter 4 Heat MCQ Questions with Answers Nephron Diagram Class 10 CBSE Class 7 Science Chapter 2 Nutrition in Animals MCQ with Answers Rabindranath Tagore Jayanti 2024