Search for: If log52,log52x−5 and log52x−7/2 are in A.P., then x is equal to If log52,log52x−5 and log52x−7/2 are in A.P., then x is equal to A7B3C4D8 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:As log52,log52x−5, log52x−7/2 are in A.P., we get 2log52x−5=log52+log52x−7/2⇒ 2x−52=22x−7/2⇒ 2x2−122x+32=0 ⇒ 2x−42x−8=0⇒ 2x=22,23 ⇒ x=2,3.Clearly, x≠2. Therefore x=3 Related content Class 9 Science MCQ Chapter 12 Sound CBSE Class 12 English MCQ with Answers (Flamingo & Vistas) CBSE Class 7 Science MCQ Questions with Answers CBSE Class 12 Subject Wise MCQ 2024-25 ICSE Class 10 Toppers List 2024 Available Tenses Worksheet for Class 10 CBSE Class 7 Science Chapter 4 Heat MCQ Questions with Answers Nephron Diagram Class 10 CBSE Class 7 Science Chapter 2 Nutrition in Animals MCQ with Answers Rabindranath Tagore Jayanti 2024