Search for: In the expansion of x3−1x2n,n∈N, if the sum of the coefficients of x5 and x10is 0, then n is In the expansion of x3−1x2n,n∈N, if the sum of the coefficients of x5 and x10is 0, then n is A25B20C15DNone of these Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:x3−1r2nGeneral term Tr+1=n!r!(n−r)!(−1)n−rx5n−2nIf 5r−2n=5, then 5r=2n+5 or r=2n5+1If 5r−2n=10, then 5r=2n+10 or r=2n5+2x5 and x10 terms occurs if n=5kGiven that sum of x5 and x10 is zero.⇒5k!(2k+1)!(3k−1)!−5k!(2k+2)!(3k−2)!=0or 13k−1−12k+2=0or k=3⇒n=15 Related content Test your English Vocabulary CUET Exam Dates 2024 – Application Form, Fees, Eligibility CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4 CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers