Search for: In a triangle ABC, if tanA=2sin2C and 3cosA=2sinBsinC, then C= In a triangle ABC, if tanA=2sin2C and 3cosA=2sinBsinC, then C= Aπ6Bπ4Cπ9Dπ2 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:3=2sin(A+C)sinCcosA=2(tanAcosC+sinC)sinC=24cos2C+1sin2C∴ 3=2s(5−4s), where s=sin2CSolving 8s2−10s+3=0, we get sin2C=s=34,12 ∴ C=π3,π4 Related content CBSE Class 9 English Beehive Book Poem 1 The Road Not Taken MCQ Questions with Answers MCQs Questions with Answers for Class 9 English Chapter 1 The Fun They Had CBSE Class 9 Tissue MCQs Female Reproductive System Diagram Class 10 NCERT Solutions for Class 11 English Reading Skills Chapter 1 The Portrait of a Lady 50+ Simple GK Questions and Answers for Class 8 Animal Cell Diagram Class 9 Preparation Strategy for NEET Repeaters CBSE Power Sharing Class 10 MCQs Political Science Chapter 1 How to Self Study for NEET Dropper at Home?