Search for: If x and y are positive integers such that xy+x+y = 71, x2y +xy2 =880, then x 2+y2 is equal to If x and y are positive integers such that xy+x+y = 71, x2y +xy2 =880, then x 2+y2 is equal to ABCD Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:∵xy+x+y=71⇒xy+(x+y)=71and x2y+xy2=880⇒ xy(x+y)=880⇒xy and (x+y) are the roots of the quadratic equation. t2−71t+880=0⇒(t−55)(t−16)=0⇒t=55,16x+y=16andxy=55So,x2+y2=(x+y)2−2xy=(16)2−110=146 Related content Test your English Vocabulary CUET Exam Dates 2024 – Application Form, Fees, Eligibility CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4 CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers