Search for: The AM of 2n+1C0,2n+1C1,2n+1C2,…,2n+1Cn is The AM of 2n+1C0,2n+1C1,2n+1C2,…,2n+1Cn is A2nnB2nn+1C22nnD22n(n+1) Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution: 2n+1C0+2n+1C1+2n+1C2+…+2n+1C2n+2n+1C2n+1=22n+1Now 2n+1C0=2n+1C2n+1, 2n+1C1=2n+1C2n…2n+1Cr=2n+1C2n−r+1So, sum of first (n + 1 ) terms= sum of last (n + 1 ) terms⇒ 2n+1C0+2n+1C1+2n+1C2+…+2n+1Cn=22n⇒ 2n+1C0+2n+1C1+2n+1C2+…+2n+1Cnn+1=22n(n+1) Related content Test your English Vocabulary CUET Exam Dates 2024 – Application Form, Fees, Eligibility CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4 CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers