Search for: For |x|<1,let y=1+x+x2+… to ∞, then dydxis equal to For |x|<1,let y=1+x+x2+… to ∞, then dydxis equal to AxyBx2y2Cxy2Dxy2+y Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:∵y=1+x+x2+…∞∴ y=11−x=(1−x)−1On differentiating w.r.t. x, we getdydx=−1(1−x)2(−1)=1(1−x)2∴ dydx−y=1(1−x)2−1(1−x)=1−1+x(1−x)2=x(1−x)2⇒ dydx−y=xy2⇒dydx=xy2+y Related content Female Reproductive System Diagram Class 10 NCERT Solutions for Class 11 English Reading Skills Chapter 1 The Portrait of a Lady 50+ Simple GK Questions and Answers for Class 8 Animal Cell Diagram Class 9 Preparation Strategy for NEET Repeaters CBSE Power Sharing Class 10 MCQs Political Science Chapter 1 How to Self Study for NEET Dropper at Home? CBSE Class 9 English Wind Worksheet Viram Chinh in Hindi Worksheets Class 9 with Answers MP Board Class 8 Result 2024 – MPBSE Class 8 Result (Out)